外文翻译--相位锁相环.doc

《外文翻译--相位锁相环.doc》由会员分享，可在线阅读，更多相关《外文翻译--相位锁相环.doc（34页珍藏版）》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。

1、外文翻译 THE PHASE-LOCKED LOOP (PLL)The PLL as an FM DemodulatorAs you have seen, the VCO control voltage in a PLL depends on the deviation of the incoming frequency. The PLL will produce a voltage proportional to the frequency of the incoming signal which, in the case of FM, is the original modulating

2、signal.Figure 13-54 shows a typical connection for the LM565 as an FM demodulator. If the IF input is frequency modulated by a sinusoidal signal, you get a sinusoidal signal on the output as indicated. Since the maximum operating frequency is 500 kHz, this device must be used in double-conversion FM

3、 receiver is one in which essentially two mixers are used to first convert the RF to a 10.7 MHz IF and then convert this to a 455 kHz IF.The free-running frequency of the VCO is adjusted to approximately 455 kHz, which is the center of the modulated IF range, C can be any value, but R should be in t

4、he range from 2k to 20k ,The input van be directly coupled as long as there is no dc voltage difference between pins 2 and 3.The VCO is connected to the phase detector by an external wire between pins 4 and 5.Determine the values for R,C and C for the LM565 in Figure 13-54 for a free-running frequen

5、cy of 455 kHz and a capture range of 10kHz.The dc supply voltages are 6V.Solution Use Equation (13-5) to calculate C.Choose R =4.7k. COMMUNICATIONS CIRCUITSThe lock range and capture range must be determined before C can be calculated. The lock range isUse Equation (13-7) to calculate C.Therefore,Pr

6、actice Exercise What can you do to increase the capture range from 10 kHz to 15 kHz ?13-8 REVIEW QUESTIONS 1. List the three basic components in a phase-locked loop. 2. What is another circuit used in some PLLs other than the three listed in Question 1? 3. What is the basic function of a PLL? 4. Wha

7、t is the difference between the lock range and the capture range lf a PLL? 5. Basically, how does a PLL track the incoming frequency? A SYSTEM APPLICATION The DCE (data communications equipment) system introduced at the opening of this chapter includes an FSK (frequency shift keying) modem (modulato

8、r/demodulator). FSK is one method for modulating digital data for transmission over voice phone lines and is basically a form of frequency modulation .In this system application, the focus is on the low-speed modulator/demodulator (modem) board, which is implemented with a VCO for transmitting FSK s

9、ignals and a PLL for receiving FSK signals.After completing this section, you should be able to Apply what you have learned in this chapter to a system applicationDescribe how a VCO and a PLL can be used in a communications system Discuss how FSK is used to send digital information over phone lines

10、Translate between a printed circuit board and a schematic Analyze the modem circuitry Troubleshoot some common problems A SYSTEM APPLICATIONA Brief Description of the SystemThe FSK modem interfaces a computer with the telephone network so that digital data, which are incompatible with the standard p

11、hone system because of bandwidth limitations, can be transmitted and received over regular phone lines, thus allowing computers to communicate with each other. Figure 13-55 shows a diagram of a simple data communications system in which a modem at each end of the phone line provides interfacing for

12、a computer.A data communications system. The modem (DCE) consists of three basic functional blocks as shown in Figure 13-56:the FSK modem circuits, the phone line interface circuits, and the timing and control circuits. The dual polarity power supply is not shown. Although the focus lf this system a

13、pplication is the FSK modem board, we will briefly look at each of the other parts to give you a basic idea of the overall system function.Basic block diagram of a modem. COMMUNICATIONS CIRCUITSThe Phone Line Interface The main purposes of this circuitry are to couple the phone line to the modem by

14、proper impedance matching, to provide necessary filtering, and to accommodate full-duplex transmission of data, Full-duplex means essentially that information can be going both ways on a single phone line at the same time, This allows a computer, connected to a modem, to be sending data and receivin

15、g data simultaneously without the transmitted data interfering with the received data. Full-duplexing is implemented by assigning the transmitted data one bandwidth and the received data another separate bandwidth within the 300 Hz to 3 kHz overall bandwidth of the phone network.Timing and Control O

16、ne basic function of the timing and control circuits is to determine the proper mode of operation for the modem. The two modes are the originate mode and the answer mode. Another function is to provide a standard interface (such as RS-232C) with the DTE (computer). The RS-232C standard requires cert

17、ain defined command and control signals, data signals, and voltage levels for each signal.Digital Data Before we get into FSK, lets briefly review digital data. A detailed knowledge of binary numbers is not necessary for this system application. Information is represented in digital form by 1s and 0

18、s, which are the binary digits or bits. In terms of voltage waveforms, a 1 is generally represented by a high level and a 0 by a low level. A stream of serial data consists if a sequence of bits as illustrated by an example in Figure 13-57(a).FIGURE 13-57A serial stream of digital data.Baud Rate A l

19、ow-speed modem, such as the one we are focusing on, sends and receives digital data at a rate of 300 bits/s or 300 baud.5For example, if we have an alternating sequence of 1s and 0s (highs and lows),as indicated in Figure 13-57(b),each bit takes 3.33 ms. Since it takes two bits, a 1 and a 0, to make

20、 up the period of this particular waveform, the fundamental frequency of this format is 1/6.67 ms =150 Hz. This is the maximum frequency of a 300 baud data stream because normally there may be several consecutive 1s and/or several consecutive zeros in a sequence, thus reducing the frequency, As ment

21、ioned earlier, the telephone network has a 300 Hz minimum frequency response, so the fundamental frequency of the 300 baud data stream will fall outside of the telephone bandwidth. This prevents sending digital data in its pure form over the phone lines.Technically, bit rate and baud rate are not th

22、e same. Baud rate indicates how many frequency shifts are sent per second. Each frequency shift can represent more than one bit; thus, a 14,400 bits/s modem actually transmits at 2400 baud. SYSTEM APPLICATIONFrequency-Shift Keying (FSK) FSK is one method used to overcome the bandwidth limitation of

23、the telephone so that digital data can be sent over the phone lines. The basic idea of FSK is to represent 1s and 0s by two different frequencies within the telephone bandwidth. By the way, any frequency within the telephone bandwidth is an audible tone. The standard frequencies for a full-duplex 30

24、0 baud modem in the originate mode are 1070 Hz for a 0 (called a space) and 1270 Hz for a 1 (called a mark). In the answer mode, 2025 Hz is a 0 and 2225 Hz is a 1. The relationship of these FSK frequencies and the telephone bandwidth is illustrated in Figure 13-58.Signals in both the originate and a

25、nswer bands can exist at the same time on the phone line and not interfere with each other because of the frequency separation.Frequencies for 300 baud, full-duplex data transmission.An example of a digital data stream converted to FSK by a modem is shown in Figure Example if FSK data. COMMUNICATION

26、S CIRCUITSModem Circuit Operation The FSK modem circuits, shown in Figure 13-60, contain an LM565 PLL and a VCO integrated circuit. The VCO can be a device such as the 4046 (not covered specifically in this chapter), which is a PLL device in which the VCO portion van be used by itself because all of

27、 the necessary inputs and outputs are available. The VCO in the LM565cannot be used independently of the PLL because there is on input pin for the control voltage. The function of the VCO is to accept digital data from a DTE and provide FSK modulation. The VCO is always the transmitting device. The

28、digital data come in on the control voltage input (pin 9) of the VCO via a level-shifting circuit formed by Q3 and Q4.This circuit is used because the data from the RS-232C interface are dual polarity with a positive voltage representing a 0 and a negative voltage representing a 1.Potentiometer R8 i

29、s for adjusting the high level of the control voltage and R11 is for adjusting the low level for the purpose of fine-tuning the frequency. Transistor Q5 provides for originate/answer mode frequency selection by changing the value of the frequency-selection resistance from pin 11 to ground. Transisto

30、rs Q1 and Q2 perform a similar function for the PLL. A SYSTEM APPLICATIONWhen the digital data are at high levels, corresponding to logic 0s, the VCO oscillates at 1070 Hz in the originate mode and 2025 Hz in the answer mode. When the digital data are at low levels, corresponding to logic 1s, the VC

31、O oscillates at 1270 Hz in the originate mode and 2225 Hz in the answer mode. An example of the originate mode is when the receiving DTE responds to a request and sends data back to the originating DTE.The function of the PLL is to accept incoming FSK-modulated data and convert it to a digital data

32、format for use by the DTD. The PLL is always a receiving device. When the modem is in the originate mode, the PLL os receiving originate-mode data from the other modem. The 741 op-amp is connected as a comparator that changes the data levels from the PLL to dual-polarity format for compatibility wit

33、h the RS-232C interface.Now, so that you can take a closer look at the FSK modem board, lets take it out of the system and put it on the troubleshooters bench.TROUBLESHOOTERS BENCH ACTIVITY 1 Relate the PC Board to the SchematicLocate and identify each component and each input/output pin on the PC b

34、oard in Figure 13-61 using the schematic in Figure 13-60. Verify that the board and the schematic agree. If the PC board and the schematic do not agree, indicate the problem. COMMUNICATIONS CIRCUITS ACTIVITY 2 Analyze the CIRCUITSFor this application, the free-running frequencies of both the PLL and

35、 the VCO circuits are determined by the formula in Equation (13-5).Step 1: Verify that the free-running frequency for the PLL OC is approximately 1070 Hz in the originate mode and approximately 1270 Hz in the answer mode.Step 2: repeat Step 1 for the VCO.Step 3: Determine the approximate minimum and

36、 maximum output voltages for the 741 comparator.Step 4: Determine the maximum high-level voltage on pin 9 of the VCO.Step 5: If a 300 Hz square wave that varies from +5 V to 5 V is applied to the data from the DTE input, what should you observe on pin 4 of the VCO?Step 6: When the data from the DTE

37、are low, pin 9 of the VCO is at approximately 0V. At this level, the VCO oscillates at 1070 Hz or 2025 Hz. When the data from the DTE go high, to what value should the voltage at pin 9 be adjusted to produce a 1270 Hz or 2225 Hz frequency if the transfer function of the VCO is 50 Hz/V? ACTIVITY 3 Wr

38、ite a Technical Report Describe the overall operation of the FSK modem board. Specify how each circuit works and what its purpose is. Identify the function of each component Use the results of Activity 2 as appropriate. ACTIVITY 4 Troubleshoot the System for Each of the Following Problems By Stating

39、 the probable Cause or Causes1. There is no demodulated data output voltage when there are verified FSK data from the phone line interface.2. The LM565 properly demodulates 1070 Hz and 1270 Hz FSK data but does not properly demodulate 2025 Hz and 2225 Hz data.3. The VCO produces no FSK output.4. The

40、 VCO produces a continuous 1070 Hz tone in the originate mode and a continuous 2025 Hz tone in the answer mode when there are proper data from the DTE.13-9 REVIEW QUESTIONS1. The originate/answer input to the modem is low. In what mode is the system?2. What is the purpose of diode D1 in the FSK mode

41、m circuit?3. The VCO is transmitting 1070 Hz and 1270 Hz FSK signals. To what frequencies does the PLL respond from another modem?4. If the VCO is transmitting a constant 2225 Hz tone, what does this correspond to in terms of digital data? I what mode is the modem? GLOSSARYSUMMARY In amplitude modul

42、ation (AM), the amplitude of a higher-frequency carrier signal is varied by a lowerfrequency modulating signal (usually an audio signal).A basic superheterodyne AM receiver consists of an RF amplifier (not always), a mixer, a local oscillator, an IF (intermediate frequency) amplifier, an AM detector

43、, and audio and power amplifiers.The IF in a standard AM receiver is 455 kHz.The AGC (automatic gain control) in a receiver tends to keep the signal strength constant within the receiver to compensate for variations in the received signal.In frequency modulation (FM), the frequency of a carrier sign

44、al is varied by a modulating signal. A superheterodyne FM receiver is basically the same as an AM receiver except that it requires a limiter to keep the IF amplitude constant, a different kind of detector or discriminator, and a de-emphasis network. The IF is 10.7 MHz.A four-quadrant linear multipli

45、er can handle any combination of voltage polarities on its inputs.Amplitude modulation is basically a multiplication process.The multiplication of sinusoidal signals produces sum and difference frequencies.The output spectrum of a balanced modulator includes upper-side and lower-side frequencies, bu

46、t no carrier frequency.The output spectrum of a standard amplitude modulator includes upper-side and lower-side frequencies and the carrier frequency.A linear multiplier is used as the mixer in receiver systems.A mixer converts the RF signal down to the IF signal. The radio frequency varies over the

47、 AM or FM band. The intermediate frequency is constant.One type of AM demodulator consists of a multiplier followed by a low-pass filter.The audio and power amplifiers boost the output of the detector or discriminator and drive the speaker.A voltage-controlled oscillator (VCO) produces an output fre

48、quency that can be varied bb a control voltage. Its operation is based on a variable reactance.A VCO is a basic frequency modulator when the modulating signal is applied to the control voltage input.A phase-locked loop (PLL) is a feedback circuit consisting of a phase detector, a low-pass filter, a VCO, and sometimes an amplifier.The purpose of a PLL is to lock onto and track incoming frequencies.