2022年6_实数_教案2 .pdf

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1、名师精编优秀教案2.6 实数(2)教学目标：(一)教学知识点1.了解有理数的运算法则在实数范围内仍然适用.2.用类比的方法，引入实数的运算法则、运算律，并能用这些法则，运算律在实数范围内正确计算.3.正确运用公式);0,0(bababa)0,0(bababa.(二)能力训练要求1.让学生根据现有的条件或式子找出它们的共性，进而发现规律，培养学生的钻研精神和创新能力.2.能用类比的方法去解决问题，找规律，用旧知识去探索新知识.(三)情感与价值观要求通过探索规律的过程，培养学生学习的主动性，敢于探索，大胆猜想，和同学积极交流，增强学习数学的兴趣和信心。教学重点：1.用类比的方法，引入实数的运算法则

2、、运算律，并能在实数范围内正确进行运算.2.发现规律：);0,0(bababa)0,0(bababa.并能用规律进行计算.教学难点：1.类比的学习方法.2.发现规律的过程.教学方法：类比法.教学过程：.新课导入上节课我们学习了实数的定义、实数的两种分类，还有在实数范围内如何求相反数、倒数、绝对值，它们的求法和在有理数范围内的求法相同.那么在有理数范围内的运算法则、运算律等能不能在实名师精编优秀教案数范围内继续用呢？本节课让我们来一起进行探究.新课讲解1.有理数的运算法则在实数范围内仍然适用.师大家先回忆一下我们在有理数范围内学过哪些法则和运算律.生加、减、乘、除运算法则，加法交换律，结合律，分

3、配律.师好.下面我们就来验证一下这些法则和运算律是否在实数范围内适用.我们知道实数包括有理数和无理数，而有理数不用再考虑，只要对无理数进行验证就可以了.如：2332，.252)32(2322,3)212(32123所以说明有理数的运算法则与运算律对实数仍然适用.下面看一些例题.计算：(1)1313；(2)77；(3)(25)2；(4)2)212(.2.做一做填空：(1)94=_，94=_；(2)916=_，916=_；(3)94=_，94=_；(4)2516_，2516=_.师 通过上面计算的结果，大家认真总结找出规律.如果把具体的数字换成字母应怎样表示呢？baba(a0,b 0)；baba(

4、a0,b0)并作一些练习.化简：(1)326；(2)3274；(3)(31)2；(4)326；(5)546.文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7

5、O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7

6、文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:C

7、D10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R

8、8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10

9、 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1

10、D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7名师精编优秀教案3.例题讲解例题化简：(1)5312；(2)

11、236；(3)(5+1)2；(4)12)(12(.课堂练习(一)随堂练习化简：(1)2095；(2)8612；(3)(1+3)(2 3)；(4)(323)2.(二)补充练习1.化简：(1)250580；(2)(1+5)(52)；(3)82(2；(4)3721；(5)2)313(；(6)104051042.一个直角三角形的两条直角边长分别为5 cm 和45 cm，求这个直角三角形的面积.解：S=45521)cm(5.71521)35(214552122答：这个三角形的面积为7.5 cm2.课时小结本节课主要掌握以下内容.1.在实数范围内，有理数的运算法则、运算律仍然适用，并能正确运用.2.bab

12、a(a0,b0)；baba(a 0,b0)的推导及运用.课后作业习题 2.9 1.化简：文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码

13、:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W

14、8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J

15、10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2

16、K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8

17、H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1

18、C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7名师精编优秀教案(1)313；(2)23；(3)23222；(4)85021.活

19、动与探究下面的每个式子各等于什么数？2222222003,2002,2001,4,3,2.由此能得到一般的规律吗？对于一个实数a、2a一定等于a吗？当a0 时，2a=a.当a0 时，有.20032003)2003(,20022002)2002(,20012001)2001(,416)4(,39)3(,24)2(222222222所以当a0 时，有2a=a.板书设计：2.6.2 实数(二)一、有理数的运算法则在实数范围内仍然适用二、找规律baba(a0,b0)；baba(a0,b0)三、例题讲解四、课堂练习五、课时小结六、课后作业教学反思：这节内容是两个公式的推导与运用。当然计算的熟练始终是初中

20、阶段的一个大的环节，只有让学生多做练习才能熟练。有待另外花时间加大训练。文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R

21、8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10

22、 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1

23、D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9

24、 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7

25、O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7文档编码:CD10W8R8P2J10 HN2K1D6G8H9 ZK1C7O8M6V7