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1、优秀学习资料欢迎下载反比例函数一、反比例函数定义：1、反比例函数xky（0k）的图象经过点（1，-3），则 k 的值为。2、在下列函数中，y 是 x 的反比例函数是（）A、y=4+x B、xy=0 C、kxyD、y=x213、若函数y=0.53mx+2n1 是反比例函数，则y=x2n+2m 是_函数二、反比例函数图象的画法与性质：1、在函数 y=a2x1（a 为常数）的图象上三点（3、y1）（1、y2）（2、y3）则函数值y1、y2、y3的大小关系是_。2、三角形面积b（cm2）这时底边上的高ycm 与底边 x（cm）之间的函数关系图象大致是_ 3、反比例函数y=xk图象在第二、四象限，则一次
2、函数y=kx5 的图象不经过 _象限。4、在同直角坐标系中，函数y=kxk 与 y=k/x（k 0）的图象大致是_。-第 1 页，共 4 页精品p d f 资料 可编辑资料-优秀学习资料欢迎下载5、如果反比例函数y=-1/x 的图象上有一点A，过 A 分别作 X 轴和 Y 轴的垂线与X 轴和 Y轴围成一矩形，则这个矩形的面积是三、反比例函数y=xk（k 0）中比例系数k 的意义1、如图已知A、B 是函数 Y=x1的图象上关于原点O 的任意一对对称点，AC 平行于Y轴，BC 平行于 X 轴，ABC 的面积为S，则 S=_ 2、如图，正比例函数Y=kx（ko）和反比例函数Y=x1的图象相交于AC
3、两点，过 A 作 X 轴垂线交 X 轴于 B，连接 BC，若 ABC 面积为 S，则 S=_。3、如图在Rt ABO 中，顶点 A 是双曲线y=k/x 与直线y=x+(k+1)在第四象限的交点，AB X 轴于 B 且 S ABO=3/2。（1）求这两个函数的解析式（2）求直线与双曲线的两个交点 AC 的坐标和 AOC 的面积四、反比例函数的应用：1.水池内装有12m3的水，如果从排水管中每小时流出x m3的水，则经过y 小时，就可以把水放完。（1）求 y 与 x 的函数关系式。（2）画出函数的图象。（3）当 x=6 m3/小时，求时间y 的值。-第 2 页，共 4 页精品p d f 资料 可编
4、辑资料-文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档
5、编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4
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7、0V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU
8、9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U
9、4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 Z
10、C1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3优秀学习资料欢迎下载2.为了预防非典，某学校对教室采用药熏消毒，已知药物燃烧时，室内每立方米空气中的含药量y（毫克）与时间x（分）成正比例，药物燃烧后 y 与
11、x 成反比例（如图），现测得药物8 分钟燃毕，此时室内中每立方米的含药量6 毫克，请根据题中所提供的信息，解答下列问题：（1）药物燃烧时，y 关于 x 的函数关系式为_自变量 x 的取值范围 _。（2）燃烧后，y 关于 x 的函数关系式为_。（3）当空气中每立方米的含药量低于1、6 毫克时，学生方可入教室，那么从消毒开始，至少需 _分钟后，学生才能回到教室。（4）当空气中每立方米含药量不低于3 毫克且持续时间不低于10 分钟时，才能有效杀灭病菌，那么此次消毒是否有效？为什么？五、反比例函数与一次函数综合训练：1、如下图，已知一次函数y=kx+b（k 0）的图象与x 轴、y 轴分别交于A、B 两
12、点，且与反比例函数y=m/x（m 0）的图象在-第 3 页，共 4 页精品p d f 资料 可编辑资料-文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5
13、M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档
14、编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4
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19、 OA=OB=OD=1（1）求点 A、B、D 的坐标（2）求一次函数和反比例函数的解析式。2、已知反经例函数y=k/2x 和一次函数y=2x1，其中一次函数的图象经过点（2，1+k）（1）求反比例函数的解析式（2）已知点 A 在第一象限，且同时在两个函数的图象上，求点 A 的坐标。（3）利用（2）的结果，在 x 轴上是否存在点P，使 OA=OP，若存在求出点P 的坐标，不存在说明理由。-第 4 页，共 4 页精品p d f 资料 可编辑资料-文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S
20、2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y3文档编码:CW4G9A4X10V2 HU9F5X4U4Z10 ZC1S2X5M2Y
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