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1、2016 年东营职业学院单招数学模拟试题（附答案解析）一、选择题（本题共10 个小题，每小题5 分，共 50 分。）1.正弦函数是奇函数，f(x)sin(x21)是正弦函数，因此f(x)sin(x21)是奇函数以上推理()A结论正确B大前提不正确C小前提不正确 D全不正确2.若，则等于（）A 1 B 2 C1 D 3.已知 c1，a，b，则正确的结论是()AabBabCabDa4.展开式中只有第六项二项式系数最大,则展开式中的常数项是（）ABCD5.用数学归纳法证明，从“到”，左端需增乘的代数式为().A.B.C.D.6.从不同号码的双鞋中任取只，其中恰好有双的取法种数为（）A.B.C.D.7
2、.若函数 f(x)exmx 的单调递增区间是(1，)，则 f(x)dx 等于()A e1 Be2 C.e D.e1 8.古希腊人常用小石子在沙滩上摆成各种形状来研究数。比如：他们研究过图1 中的 1，3，6，10，由于这些数能够表示成三角形，将其称为三角形数；类似的，称图2 中的 1，4，9，16，这样的数为正方形数。下列数中既是三角形数又是正方形数的是（）.A.289 B.1024 C.1225 D.1378 9.已知定义在 R 上的函数满足为的导函数。已知的图象如图所示，若两个正数满足，则的取值范围是A.B.C.D.10.设函数y=f(x)在（a,b）上的导函数为f (x),f (x)在(
3、a,b)上的导函数为f (x)，若在（a,b）上，f(x)0恒成立，则称函数f(x)在(a,b)上为“凸函数”，已知当m 2时，f(x)=x3mx2+x 在（1，2）上是“凸函数”，则 f(x)在（1，2）上（）A.既有极大值，也有极小值B.既有极大值，也有最小值C.极大值，没有极小值D.没有极大值，也没有极小值二、填空题（本题共5 小题，每小题5 分，共 25 分）11.|x|dx_.12.从甲、乙、丙、丁四名同学中选出三名同学，分别参加三个不同科目的竞赛，其中甲同学必须参赛，则不同的参赛方案共有_.13.如果函数f(x)x36bx3b 在区间(0,1)内存在与x 轴平行的切线，则实数b 的
4、取值范围是 _14.已知：中，于，三边分别是，则有；类比上述结论，写出下列条件下的结论：四面体中，的面积分别是，二面角的度数分别是，则15.计算+22+32+n2=三、解答题（本大题共6 小题，共 75 分，解答应写出文字说明与演算步骤）16.（本小题 12 分）已知（x2）n展开式中的二项式系数的和比（3a+2b）7展开式的二项式系数的和大128，求（x2）n展开式中的系数最大的项和系数最小的项。文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5
5、HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10
6、ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档
7、编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F
8、5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S1
9、0 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4
10、文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W
11、1F5 HU4G6S3H4S10 ZS7V9P1R1R4文档编码:CW1O3V8W1F5 HU4G6S3H4S10 ZS7V9P1R1R417.（本小题12 分）用数学归纳法证明：18.（本小题12 分）有6 本不同的书按下列分配方式分配，问共有多少种不同的分配方式？（1）分成 1 本、2 本、3 本三组；（2）分成每组都是2 本的三组；（3）分给甲、乙、丙三人，每人2 本。19.（本小题12 分）某商场销售某种商品的经验表明，该商品每日的销售量y(单位：千克)与销售价格x(单位：元/千克)满足关系式y 10(x6)2.其中 3x6，a为常数已知销售价格为 5 元/千克时，每日可售出该商品11
12、千克(1)求 a 的值；(2)若该商品的成本为3 元/千克，试确定销售价格x 的值，使商场每日销售该商品所获得的利润最大20.（本小题13 分）在曲线yx2(x 0)上的某点A 处作一切线使之与曲线以及x 轴所围图形的面积为.试求：切点A 的坐标以及切线方程文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编
13、码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A
14、8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F
15、10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3
16、D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4
17、D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7
18、L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E
19、4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E521.（本小题满分14 分）已知函数在点处取得极值（1）求实数的值；（2）若关于的方程在区间上有两个不等实根，求的取值范围；（3）证明：对于任意的正整数，不等式都成立参考答案文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5
20、文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:C
21、G6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5
22、J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10
23、HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V
24、4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2
25、ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10
26、B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5一、选择题1、C 2、A 3、B 4、A 5、D 6、A 7、D 8、C 9、A 10、C二、填空题11.12、CA=18种.13.b|0b 14、s1cos +s2cos +s3cos 15、(n+1).n.2n2三、解题答16、17、所以由（1）（2）得（12 分）18、（每小问 4 分）文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3
27、D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4
28、D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7
29、L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E
30、4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编
31、码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A
32、8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F
33、10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E519、解：(1)因为 x5 时，y11，所以 1011，a2.5分(2)由(1)可知，该商品每日的销售量y 10(x 6)2.所以商场每日销售该商品所获得的利润f(x)(x3)10(x6)2 210(x3)(x6)2,（(3x6.)8 分从而，f(x)10(x6)2 2(x3)(x6)30(x4)(x6)于是，当x变化时，f(x)，f(x)的变化情况如下表：x(3,4)4(4
34、,6)f(x)0f(x)单调递增极大值 42单调递减由上表可得，x4 是函数 f(x)在区间(3,6)内的极大值点，也是最大值点所以，当x4 时，函数f(x)取得最大值，且最大值等于42.1 1 分答：当销售价格为4 元/千克时，商场每日销售该商品所获得的利润最大1 2分20、解；可设切点A 的坐标为(，)，k=f()=2,则切线方程为y2(x)，即 y2x，3 分可得切线与x 轴的交点坐标为(，0)4 分画出草图，得曲文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码
35、:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8
36、H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F1
37、0 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D
38、8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D
39、2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L
40、10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4
41、E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E521.解：（1），函数在点处取得极值，即当时，则得.（2）,.令,则.,令,解得；令,解得，可得如下当时，随的变化情况表：0（0,1）1（1，2）2文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4
42、F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM
43、3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E
44、4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE
45、7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9
46、E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档
47、编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6
48、A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5+0-0“关于的方程在区间上有两个不等实根”等价于“在内，函数的图像和直线有两个交点”，由上表可知，.（3）由（1）知,则.解得,解得,在递增，在递减，当时，.且，,即,.文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5
49、J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10
50、HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V4E4D2 ZE7L10B9E4E5文档编码:CG6A8H5J4F10 HM3D8V