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1、第1页共 27页杨浦区 2015-2016学年度第二学期初三质量调研数学2016.04.12 一、选择题1以下等式成立的是A=2 B=CD|a+b|=a+b 2以下关于x 的方程一定有实数解的是A2x=m Bx2=m C=m D=m 3以下函数中，图象经过第二象限的是Ay=2x By=Cy=x2 Dy=x22 4以下图形中既是轴对称图形又是中心对称图形的是A正五边形B正六边形C等腰三角形D等腰梯形5某射击选手在一次训练中的成绩如下表所示，该选手训练成绩的中位数是成绩环6 7 8 9 10 次数1 4 2 6 3 A2 B3 C8 D9 6已知圆 O 是正 n 边形 A1A2An的外接圆，半径长
2、为18，如果弧 A1A2的长为 ，那么边数n 为A5 B10 C36 D72 二、填空题7计算：=8写出的一个有理化因式：9如果关于x 的方程 mx2mx+1=0 有两个相等的实数根，那么实数m 的值是10函数 y=+x 的定义域是11如果函数y=x2m 的图象向左平移2 个单位后经过原点，那么m=第2页共 27页12在分别写有数字1，0，2，3 的四张卡片中随机抽取一张，放回后再抽取一张，如果以第一次抽取的数字作为横坐标，第二次抽取的数字作为纵坐标，那么所得点落在第一象限的概率为13在 ABC 中，点 M、N 分别在边 AB、AC 上，且 AM：MB=CN：NA=1：2，如果，那么=用表示1
3、4某大型超市有斜坡式的自动扶梯，人站在自动扶梯上，沿着斜坡向上方向前进13 米时，在铅锤方向上升了5 米，如果自动扶梯所在的斜坡的坡度i=1：m，那么 m=15某校为了解本校学生每周阅读课外书籍的时间，对本校全体学生进行了调查，并绘制如下图的频率分布直方图不完整，则图中m 的值是16如图，在平面直角坐标系xOy 中，正方形OABC 的边长为2写出一个函数y=k 0，使它的图象与正方形OABC 有公共点，这个函数的表达式为17在矩形 ABCD 中，AB=3，AD=4，点 O 为边 AD 的中点，如果以点O 为圆心，r 为半径的圆与对角线 BD 所在的直线相切，那么r 的值是18如图，将平行四边形
4、ABCD 绕点 A 旋转到平行四边形AEFG 的位置，其中点B、C、D 分别落在点 E、F、G 处，且点 B、E、D、F 在一直线上，如果点E 恰好是对角线BD 的中点，那么的值是文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9
5、文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:C
6、M10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O
7、5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8
8、HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10
9、N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3
10、 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1E3O1L9文档编码:CM10A4O5A7S8 HZ2U10N2R1F3 ZP7E1
11、E3O1L9第3页共 27页三、解答题19计算：20解不等式组：，并写出它的所有非负整数解21已知，在 RtABC 中，ACB=90 ，A=30 ，点 M、N 分别是边AC、AB 的中点，点D 是线段 BM 的中点1求证：；2求 NCD 的余切值22某山山脚的M 处到山顶的N 处有一条长为600 米的登山路，小李沿此路从M 走到 N，停留后再原路返回，期间小李离开M处的路程y米与离开M处的时间x分x0之间的函数关系如图中折线 OABCD 所示1求上山时y 关于 x 的函数解析式，并写出定义域：文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2
12、B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M
13、1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C
14、5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6
15、Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I
16、8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I1
17、0C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:C
18、D6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5第4页共 27页2已知小李下山的时间共26 分钟，其中前 18 分钟内的平均速度与后8 分钟内的平均速度之比为2：3，试求点C 的纵坐标23已知：如图，在直角梯形纸片ABCD 中，DCAB，AB CDAD，A=90 ，将纸片沿过点D 的直线翻折，使点A 落在边 CD 上的点 E 处，折痕为DF，联结 EF 并展开纸片1求证：四边形ADEF 为正方形；2取线段AF的
19、中点G，联结GE，当BG=CD时，求证：四边形GBCE为等腰梯形24已知在直角坐标系中，抛物线y=ax28ax+3a0与y轴交于点A，顶点为D，其对称轴交x 轴于点 B，点 P在抛物线上，且位于抛物线对称轴的右侧文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 Z
20、R6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档
21、编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F
22、9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4
23、 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5
24、文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D
25、1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5第5页共 27页1当 AB=BD 时如图，求抛物线的
26、表达式；2在第 1小题的条件下，当DPAB 时，求点P的坐标；3点 G 在对称轴 BD 上，且 AGB=ABD，求 ABG 的面积25已知：半圆O 的直径 AB=6，点 C 在半圆 O 上，且 tanABC=2，点 D 为弧 AC 上一点，联结 DC如图1求 BC 的长；2假设射线DC交射线AB于点M，且MBC与 MOC相似，求CD的长；3联结 OD，当 ODBC 时，作 DOB 的平分线交线段DC 于点 N，求 ON 的长文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码
27、:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9
28、HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 Z
29、R6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档
30、编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F
31、9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4
32、 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5
33、文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5第6页共 27页文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:
34、CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 H
35、G7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR
36、6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编
37、码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9
38、 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4
39、ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5第7页共 27页2016 年上海市杨浦区中考数学二模试卷参考答案与试题解析一、选择题
40、1以下等式成立的是A=2 B=CD|a+b|=a+b【考点】实数的运算；绝对值【专题】推理填空题；实数【分析】A：根据求一个数的算术平方根的方法计算即可B：分别把、化成小数，判断出它们的大小关系即可C：根据 8=23，可得=，据此判断即可D：当 a+b 是正有理数时，a+b 的绝对值是它本身a+b；当 a+b 是负有理数时，a+b 的绝对值是它的相反数a+b；当 a+b 是零时，a+b 的绝对值是零【解答】解：=2，选项 A 不正确；3.142857，3.1415927，选项 B 不正确；8=23，=，选项 C 正确；当 a+b 是正有理数时，|a+b|=a+b；当 a+b 是负有理数时，|a
41、+b|=a+b；文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:
42、CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 H
43、G7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR
44、6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编
45、码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9
46、 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4
47、ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5第8页共 27页当 a+b 是零时，|a+b|=0；选项 D 不正确故选：C【点评】1此题主要考查了实数的运算，要熟练掌握，解答此题的关键是要明确：在进行实数运算时，和有理数运算一样，要从高级到低级，即先算乘方、开方，再算乘除，最后算加减，有括号的
48、要先算括号里面的，同级运算要按照从左到有的顺序进行另外，有理数的运算律在实数范围内仍然适用2此题还考查了绝对值的含义和应用，要熟练掌握，解答此题的关键是要明确：当 a是正有理数时，a 的绝对值是它本身a；当 a是负有理数时，a 的绝对值是它的相反数a；当 a是零时，a 的绝对值是零2以下关于x 的方程一定有实数解的是A2x=m Bx2=m C=m D=m【考点】无理方程；一元一次方程的解；根的判别式；分式方程的解【分析】根据一元一次方程的解、无理方程、一元二次方程和分式方程的解的特点分别对每一项进行判断即可【解答】解：A.2x=m，一定有实数解；Bx2=m，当 m0 时，无解；C.=m，当 m
49、=0 或时无解；D.=m，当 m0 时，无解；故选 A【点评】此题考查了一元一次方程的解、无理方程、一元二次方程和分式方程，关键是灵活运用有关知识点进行判断3以下函数中，图象经过第二象限的是Ay=2x B y=Cy=x 2 Dy=x2 2【考点】二次函数的性质；一次函数的性质；正比例函数的性质；反比例函数的性质【分析】分别根据正比例函数的性质、反比例函数的性质、二次函数的性质、一次函数的性质进行解答文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9
50、HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 ZR6I10C5Y2A5文档编码:CD6Q2B1D1F9 HG7I8M1L9S4 Z