2015年四川省南充市中考数学试题及解析.pdf

上传人:Q****o 文档编号:55479295 上传时间:2022-10-30 格式:PDF 页数:25 大小:829.88KB
返回 下载 相关 举报
2015年四川省南充市中考数学试题及解析.pdf_第1页
第1页 / 共25页
2015年四川省南充市中考数学试题及解析.pdf_第2页
第2页 / 共25页
点击查看更多>>
资源描述

《2015年四川省南充市中考数学试题及解析.pdf》由会员分享,可在线阅读,更多相关《2015年四川省南充市中考数学试题及解析.pdf(25页珍藏版)》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。

1、课件园http:/第1页(共 25页)2015 年四川省南充市中考数学试卷一、选择题(本大题共10 个小题,每小题3 分,共 30 分)每小题都有代号A、B、C、D四个答案选项,其中只有一个是正确的1(3 分)(2015?南充)计算3+(3)的结果是()A6B6 C1D02(3 分)(2015?南充)下列运算正确的是()A3x 2x=x B2x?3x=6x C(2x)2=4x D6x 2x=3x 3(3 分)(2015?南充)如图是某工厂要设计生产的正六棱柱形密封罐的立体图形,它的主视图是()ABCD4(3 分)(2015?南充)学校机房今年和去年共购置了100 台计算机,已知今年购置计算机数

2、量是去年购置计算机数量的3倍,今年购置计算机的数量是()A25 台B50 台C75台D100 台5(3 分)(2015?南充)如图,一艘海轮位于灯塔P的北偏东55 方向,距离灯塔2 海里的点 A 处,如果海轮沿正南方向航行到灯塔的正东方向,海轮航行的距离AB 长是()A2 海里B2sin55 海里C2cos55 海里D2tan55 海里6(3 分)(2015?南充)若mn,下列不等式不一定成立的是()Am+2 n+2 B2m2n CDm2n2课件园http:/第2页(共 25页)7(3 分)(2015?南充)如图是一个可以自由转动的正六边形转盘,其中三个正三角形涂有阴影,转动指针,指针落在有阴

3、影的区域内的概率为a,如果投掷一枚硬币,正面向上的概率为 b,关于 a、b 大小的正确判断是()Aab Ba=b Ca b D不能判断8(3 分)(2015?南充)如图,PA和 PB 是O 的切线,点A 和 B 的切点,AC 是O 的直径,已知 P=40,则 ACB 的大小是()A40B60C70D809(3分)(2015?南充)如图,菱形ABCD 的周长为8cm,高 AE 长为cm,则对角线AC长和 BD 长之比为()A1:2 B1:3 C1:D1:10(3 分)(2015?南充)关于x 的一元二次方程x2+2mx+2n=0 有两个整数根且乘积为正,关于 y 的一元二次方程y2+2ny+2m

4、=0 同样也有两个整数根且乘积为正,给出三个结论:这两个方程的根都负根;(m 1)2+(n1)2 2;1 2m2n 1,其中正确结论的个数是()A0 个B1 个C2 个D3 个二、填空题(本大题共6 个小题,每小题3 分,共 18 分)11(3 分)(2015?南充)计算2sin45 的结果是12(3 分)(2015?南充)不等式1 的解集是13(3 分)(2015?南充)如图,点 D 在ABC 边 BC 的延长线上,CE 平分 ACD,A=80 ,B=40,则 ACE 的大小是度文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2

5、HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L

6、4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2

7、HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L

8、4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2

9、HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L

10、4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2

11、HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1课件园http:/第3页(共 25页)14(3 分)(2015?南充)从分别标有数3,2,1,0,1,2,3 的七张卡片中,随机抽取一张,所抽卡片上数的绝对值小于2 的概率是15(3 分)(2015?南充)已知关于x,y 的二元一次方程组的解互为相反数,则 k 的值是16(3 分)(2015?南充)如图,正方形ABCD 的边长为1,以 AB 为直径作半圆,点P 是CD 中点,BP 与半圆交于点Q,连结 PQ,给出如下结论:DQ=1;=;SPDQ=;cosADQ=,其中正

12、确结论是(填写序号)三、解答题(本大题共9 个小题,共72 分)17(6 分)(2015?南充)计算:(a+2)?18(6 分)(2015?南充)某学校要了解学生上学交通情况,选取九年级全体学生进行调查,根据调查结果,画出扇形统计图(如图),图中“公交车”对应的扇形圆心角为60,“自行车”对应的扇形圆心角为120,已知九年级乘公交车上学的人数为50 人(1)九年级学业生中,骑自行车和乘公交车上学哪个更多?多多少人?(2)如果全校有学生2000 人,学校准备的400 个自行车停车位是否足够?19(8 分)(2015?南充)如图,ABC 中,AB=AC,AD BC,CEAB,AE=CE 求证:(1

13、)AEF CEB;文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z

14、4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT

15、6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z

16、4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT

17、6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z

18、4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT

19、6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1课件园http:/第4页(共 25页)(2)AF=2CD 20(8 分)(2015?南充)已知关于x 的一元二次方程(x1)(x4)=p2,p 为实数(1)求证:方程有两个不相等的实数根;(2)p 为何值时,方程有整数解(直接写出三个,不需说明理由)21(8 分)(2015?南充)反比例函数y=(k 0)与一次函数y=mx+b(m 0)交于

20、点 A(1,2k 1)(1)求反比例函数的解析式;(2)若一次函数与x 轴交于点B,且 AOB 的面积为3,求一次函数的解析式22(8 分)(2015?南充)如图,矩形纸片ABCD,将 AMP 和BPQ 分别沿 PM 和 PQ 折叠(APAM),点 A 和点 B 都与点 E 重合;再将 CQD 沿 DQ 折叠,点C 落在线段 EQ上点 F 处(1)判断 AMP,BPQ,CQD 和FDM 中有哪几对相似三角形?(不需说明理由)(2)如果 AM=1,sinDMF=,求 AB 的长23(8 分)(2015?南充)某工厂在生产过程中每消耗1 万度电可以产生产值5.5 万元,电力公司规定,该工厂每月用电

21、量不得超过16 万度,月用电量不超过4 万度时,单价是1 万元/万度;超过 4 万度时,超过部分电量单价将按用电量进行调查,电价 y 与月用电量x 的函数关系可用如图来表示(效益=产值用电量 电价)(1)设工厂的月效益为z(万元),写出 z 与月用电量x(万度)之间的函数关系式,并写出自变量的取值范围;(2)求工厂最大月效益文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2

22、HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L

23、4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2

24、HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L

25、4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2

26、HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L

27、4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1课件园http:/第5页(共 25

28、页)24(10 分)(2015?南充)如图,点P是正方形 ABCD 内一点,点P到点 A、B 和 D 的距离分别为1,2,ADP 沿点 A 旋转至 ABP,连结 PP,并延长AP 与 BC 相交于点 Q(1)求证:APP是等腰直角三角形;(2)求 BPQ 的大小;(3)求 CQ 的长25(10 分)(2015?南充)已知抛物线y=x2+bx+c 与 x 轴交于点A(m2,0)和 B(2m+1,0)(点 A 在点 B 的左侧),与 y 轴相交于点C,顶点为P,对称轴为l:x=1(1)求抛物线解析式(2)直线 y=kx+2(k 0)与抛物线相交于两点M(x1,y1),N(x2,y2)(x1x2),

29、当|x1x2|最小时,求抛物线与直线的交点M 与 N 的坐标(3)首尾顺次连接点O、B、P、C 构成多边形的周长为L,若线段 OB 在 x 轴上移动,求L 最小值时点O,B 移动后的坐标及L 的最小值文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1

30、文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5

31、N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1

32、文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5

33、N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1

34、文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5

35、N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1课件园http:/第6页(共 25页)2015 年四川省南充市中考数学试卷参考答案与试题解析一、选择题(本大题共10 个小题,每小题3 分,共 30 分)每小题

36、都有代号A、B、C、D四个答案选项,其中只有一个是正确的1(3 分)(2015?南充)计算3+(3)的结果是()A6B6 C1D0考点:有 理数的加法分析:根 据有理数的加法运算法则计算即可得解解答:解:3 与 3 互为相反数,且互为相反数的两数和为0 3+(3)=0故选 D点评:本 题考查了有理数的加法运算,是基础题,熟记运算法则是解题的关键2(3 分)(2015?南充)下列运算正确的是()A3x 2x=x B2x?3x=6x C(2x)2=4x D6x 2x=3x 考点:整 式的除法;合并同类项;幂的乘方与积的乘方;单项式乘单项式分析:根 据同类项、整式的乘法、幂的乘方和整式的除法计算即可

37、解答:解:A、3x2x=x,正确;B、2x?3x=6x2,错误;C、(2x)2=4x2,错误;D、6x 2x=3,错误;故选 A点评:此 题考查同类项、整式的乘法、幂的乘方和整式的除法,关键是根据法则计算3(3 分)(2015?南充)如图是某工厂要设计生产的正六棱柱形密封罐的立体图形,它的主视图是()ABCD考点:简 单几何体的三视图分析:主 视图、左视图、俯视图是分别从物体正面、左面和上面看,所得到的图形文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I

38、2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J

39、6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I

40、2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J

41、6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I

42、2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J

43、6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I

44、2 HK5N2X1W4A5 ZT6P5J6L4B1课件园http:/第7页(共 25页)解答:解:根据主视图的定义,可得它的主视图为:,故选:A点评:本 题考查三视图的有关知识,本题只要清楚了解各个几何体的三视图即可求解4(3 分)(2015?南充)学校机房今年和去年共购置了100 台计算机,已知今年购置计算机数量是去年购置计算机数量的3倍,今年购置计算机的数量是()A25 台B50 台C75台D100 台考点:一 元一次方程的应用分析:设 今年购置计算机的数量是x 台,根据今年购置计算机数量是去年购置计算机数量的3 倍列出方程解得即可解答:解:设今年购置计算机的数量是x 台,去年购置计算机的

45、数量是(100 x)台,根据题意可得:x=3(100 x),解得:x=75故选 C点评:此 题考查一元一次方程的应用,关键是根据今年购置计算机数量是去年购置计算机数量的 3 倍列出方程5(3 分)(2015?南充)如图,一艘海轮位于灯塔P的北偏东55 方向,距离灯塔2 海里的点 A 处,如果海轮沿正南方向航行到灯塔的正东方向,海轮航行的距离AB 长是()A2 海里B2sin55 海里C2cos55 海里D2tan55 海里考点:解 直角三角形的应用-方向角问题分析:首 先由方向角的定义及已知条件得出NPA=55,AP=2 海里,ABP=90 ,再由AB NP,根据平行线的性质得出A=NPA=5

46、5 然后解Rt ABP,得出AB=AP?cosA=2cos55 海里解答:解:如图,由题意可知NPA=55,AP=2 海里,ABP=90 ABNP,A=NPA=55 在 RtABP 中,ABP=90 ,A=55 ,AP=2 海里,AB=AP?cosA=2cos55 海里故选 C文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文

47、档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N

48、2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文

49、档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N

50、2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文档编码:CV6Z1Z4M9I2 HK5N2X1W4A5 ZT6P5J6L4B1文

展开阅读全文
相关资源
相关搜索

当前位置:首页 > 教育专区 > 高考资料

本站为文档C TO C交易模式,本站只提供存储空间、用户上传的文档直接被用户下载,本站只是中间服务平台,本站所有文档下载所得的收益归上传人(含作者)所有。本站仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。若文档所含内容侵犯了您的版权或隐私,请立即通知淘文阁网,我们立即给予删除!客服QQ:136780468 微信:18945177775 电话:18904686070

工信部备案号:黑ICP备15003705号© 2020-2023 www.taowenge.com 淘文阁