《梧桐中学2019届高中毕业班第四次阶段考试数学试题(理科)39233.pdf》由会员分享,可在线阅读,更多相关《梧桐中学2019届高中毕业班第四次阶段考试数学试题(理科)39233.pdf(16页珍藏版)》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。
1、20191-m=1-nimnim ni=()1+i A.1+2i B.1-2i C.2+i D.2-i 2Aqppq2 2BambmabCp:x Rx2 x 1::0pxRx2 x 1 _0 D1,2 4 12 A3.0an,2a3-a;2a10,bnby=a7,beb8=6f(x)f(x)=x2-4x,3f(x 1)A.2 B 4 C 8 D 16 4.m,nFm _:,n/:,m _ n m/一,n/一,m/n/:,:/m _ m _ A.B 5.S()C.rA.2019 B.-1 C.-D.3 A.2)C.(1,3)D.0,2 S=3,k=0k=k+1 7.f(x)=x2 bx ag(x
2、)=In x f(x)1 1 1 A()B 1)4 2 2 C 12D 23&A(1,0),B(13),0C=,OC=-2OAOB,(R),6 A.9a 2)b=44)a b(0 4)?).1 m=(2,)n=(,0)P(x,y)y=sin xQy=f(x)2 3 OQ=m OP n oyf(x)1 1 A.2B 24 C D 4 2 2 1004R04mM1ABAB2yA0433AMxN(n0mnf n=n.AOCf 2=0f(x20f(x34f(x()U80 542011 T x (1,2)x2 mx 4 _ 0 m12,L J4-x2 dx=.2y x _1 r 13.x,yy-x1ax
3、 y0 14.5.6cmP,1cm,2cm,3cm,cm.15.AB ACABAC|AC|B CADAB=2 AC=3U AD BC68016(13)3 2f(x)=x ax bP(1,f(1)3xy-3=0 1f(x)20,t(t0)17(13)f(x)=2cos x(3sinx cos x)-1 y=f(x)0:x:ABCAf(A)=2AB AC=3BCAD18.(13)A.1 B.2 C.3 D.4 1a 19.(13)117212450f(n)n彳5)=nnIII 4816MBD.EM/ABC()DCNNMBDE N.1812 a.D220.(14)an 0 an 11 1 an-1
4、anns:Sn n-ln(n 1)9、n 3 bn=an()nm,|Dm|.10 5 21714 74 2 OABCMOABC,OABCNOABC OABCOA B C 74 4xOy0rOI374 52 2 2a 2D 3c-6a,D,ca 2D 3c|x 1|x 2Br cos,2 xI CBDDD DBBDC 11.(5 122 13.1-1,1 14.4 15.5 16:1Pf(1)=oP10y=f(x)a b-1 f(1)-3=2a-6 f(x)=x33x2 2 .5 21f(x)=3x2-6xf(x)0 x-2x 0 .f(x)(-:,0),(2,:)(0,2).7 3 2 02
5、f(X)max f(0)=2,f(X)min f(t)=t3t 2 2 3f(X)max=f(0)=f(3)=2,f(X)min=f(2)=2 3 2 t 3 f(X)max=f(t)=t-3t 2,f(X)min=f(2)=-2 .13 17.1f(x)=23cosxsin x 2cos2x 3sin2x cos2x=2sin(2 x)-3 6 JI JI JI JT JI 2k_2x 2kk x_k k Z-2 2 6 2 3 6 0:x:y=f(x)(0,2,2 6 3(2f(A)=2 A -1 6 AB AC=3 be=2-1 -S ABC bcsin A -2 2 a=b2 c2-3
6、bc.(2-、.3)bc=.3-1-2 J3+1 BCAD _ 1。-1 2 18.EUABC,DC ABC,AE DC,AE=2,DC=4,AB AC,AB=AC=2 EALABCx EAAB,ABAC,A ABACDE B-ACDEh=AB=2 ACDES=6 1 VB _ACDE S*h=4 3 4.MDBBCG,EM,MG,AG1 MG/DCMG=DC MGAE AGME2 EM/AG,AG ABC EM/ABC.8 1EM/AGBCDLABC AG1 BC,AG!BCD EMLBCDEM BDE BDELBCD BCDMMN DBDCN,MNBDENDMN L DCBx DN DB
7、DM DC DN 2,6 4 DN=3 DN=3DC 4 3 DCN,DNDCNMLBDE.4 2 AA 000B(020C 200D 204E 002M(-1 1 2DB=DC 2-4 0-4 DE=2 0-2 IDM 11-2 DCNy =?0,1.43 DCN,DNDC4 19 124f(n),f(n)=50n-12n 472=2n2 40n-72 .3 2 I f(n).0,.-2n2 40n-72.0,2:n 18.N6 II=40 _2(n 36r16.n=6 n n 6 16+48=144 n=6,.9 f(n)=-2(n-10)2 128.n=10 f(n)max=128 12
8、8+16=144 12 144 61013 20.(12-an=-V-n+_1 1 1 11an 11 1(n _1)(-1)=_n an-1 a1-1 1 an=1-1 .n(2F(x)=1 n(x 1)-x(x 0)DN DC=(0,0,-4),0,1,9 NM DM DN=(1,1,-2)-(0,0,-4)=MN BDE,NM DB=0 口口,NM DE=0(1,1,-2 4 J.2+2+8-16=02+4-8=0NIVBDE.13 1 x F(x)=丄一仁:0(x 0)x+1 x+1 F(x):F(0)=0,In(x 1)x(x 0)ln(1 丄):丄,1 1:1 In(1 丄)n n
9、 n n 1 an=1 1-In(n 1)In n n Sn:::(1 _ln 2 In 1)(1 _ln 3 In 2)1 _ In(n 1)In n Sn:n-In(n 1).3bn(2)nn 10 bn n n 9 n 9-b n 2 11n.10 n _ 4 bn 1 n2 9 0:1n:.10n _ 3 bn 1 n 9 b1b-b3b5b6.n_2bn 0b1=00bnb4 nm,|b nbm 3 9 4 19683 24000 3 b4-b1()-0=4 10 40000 40000 5 nm,|b nbm 3 .4 5 OABCOABCMA(2,0)MA(0,2)C(0,2)M
10、C(2,2)bp 0 d Z 2a=0,2c=2.a=22b=-2 2 dI2 2 2d=2.a=0,c=1,b-1,d=1 f 0 1 M=7-1 1 0(0,0),A(2,0),B(2,2),C(0,2)0(0,0),A(2,0),B(4,2),C(2,2)O(0,0),A(0,2),B(-2,4),C(-2,2)N_1J 0 5(1,34 x y-0 2 d 22)gc+2d=2,”2b=2,d=2,1 1 r_2h2 4 32e=0h 2g=2 NM 0 1 X-11 1-1 1 OABCOABCMMh 2+2h=4.e g 1 1 0-1 1 J 0 1 恵 42|_T2T|O(,d 52 207 x|-7 x:5 2-?2(,)(1,)2 2 4 x y-0 42 2(a 2b 3c)2(a2 2b2 3c2)(1 2 3),a=b=c=13 a 2b 3c6|x 1p:6 5 0I-+r cosT 2+r sin0-1 2 2 72 d=FT 72 J2r+J2+1 J2 d-32-7