-全国各地中考数学试题分类汇编:相交线与平行线.pdf

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1、1/37 A2010-2012 年三年全国各地中考数学真题分类汇编相交线与平行线一.选择题1(2012 临沂)如图,AB CD,DB BC,1=40,则 2 的度数是()A40B50C60D140考点:平行线的性质;直角三角形的性质。解答:解:AB CD,DB BC,1=40,3=1=40,DBBC,2=90 3=9040=50故选B2(2012 张家界)如图,直线a、b 被直线 c 所截,下列说法正确的是()A 当 1=2时,一定有abB当 ab 时,一定有1=2 C 当 ab 时,一定有 1+2=90D当 1+2=180时,一定有ab 考点:平行线的判定;平行线的性质。解答:解:A若 1=

2、2 不符合 ab的条件,故本选项错误;3(2012 中考)如图,直线ab,直线 c 与 a,b 相交,1=65,则 2=()A115B 65C35D254(2012 山西)如图,直线AB CD,AF交 CD于点 E,CEF=140,则A等于()A 35B 40C 45D 50考点:平行线的性质。解答:解:CEF=140,FED=180 CEF=180 140=40,直线 AB CD,2/37 AFED=40 故选 B5(2012 潜江)如图,AB CD,A=48,C=22 则E等于()A 70B 26C 36D 16考点:平行线的性质;三角形内角和定理。分析:由 ABCD,根据两直线平行,内错

3、角相等,即可求得1 的度数,又由三角形外角的性质,即可求得E的度数解答:解:ABCD,A=48,1=A=48,C=22,E=1C=48 22=26故选 B 点评:此题考查了平行线的性质与三角形外角的性质此题比较简单,注意掌握两直线平行,内错角相等定理的应用6.(2012 十堰)图,直线BD EF,AE与 BD交于点 C,若 ABC=30,BAC=75,则CEF的大小为()A60B75C90D105【考点】平行线的性质;三角形内角和定理【专题】探究型【分析】先根据三角形外角的性质求出1 的度数,再由平行线的性质即可得出结论【解答】解:1 是 ABC的外角,ABC=30,BAC=75,1=ABC+

4、BAC=30+75=105,直线 BD EF,CEF=1=105故选 D【点评】本题考查的是平行线的性质及三角形外角的性质,熟知两直线平行,同位角相等是解答此题的关键7(2012 宜昌)如图,将三角尺与直尺贴在一起,使三角尺的直角顶点C(ACB=90)在直尺的一边上,若 1=60,则2 的度数等于()文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E

5、5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C1

6、0文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2

7、C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E

8、5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C1

9、0文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2

10、C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E

11、5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C10文档编码:CI10H8K5E5G10 HZ2G10H6Z2C1 ZP2B4I2J10C103/37 A75B60C45D30考点:平行线的性质;余角和补角。分析:根据题意得:ADC=BEF=90,又由直角三角形的性质,即可求得A的值,继而求得B的度数,然后求得2 的度

12、数解答:解:如图,根据题意得:ADC=BEF=90,1=60,A=90 1=30,ACB=90,B=90 A=60,2=90 B=30 故选 D点评:此题考查了直角三角形的性质此题难度不大,注意直角三角形中两锐角互余定理的应用是解此题的关键8(2012 海南)小明同学把一个含有450角的直角三角板在如图所示的两条平行线mn,上,测得0120,则的度数是【】A450B550 C650 D750【答案】D。【考点】平行线的性质,平角定义,对顶角的性质,三角形内角和定理。【分析】mn,ABn=0120。ABC=600。又 ACB=,A=450,根据三角形内角和定理,得=1800600450=750。

13、故选 D。9(2012?连云港)如图,将三角尺的直角顶点放在直线a上,ab,150,260,则3 的度数为()A50B 60C 70D 80文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9

14、D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档

15、编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P

16、10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I1

17、0 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A

18、10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3

19、G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:C

20、K2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U64/37 解答:解:BCD中,150,260,4180 12180506070,5470,ab,3570故选C点评:本题考查的是平行线的性质,解答此类题目时往往用到三角形的内角和是180这一隐藏条件10.(2012重庆)已知:如图,BD平分 ABC,点 E在 BC上,EF/AB 若 CEF=100,则ABD的度数为()A.60 B.50 C.40D.30FEDCBA解读:本题由平行很容易想到同位角相等,再由角平分线的性质可得证。答案

21、:B 点评:由平行线想到同位角相等,内错角相等,同旁内角互补,是解本题的关键。11.(2012 玉林)如图,ab,c与a,b都相交,1=50,则 2=A.40 B.50 C.100 D.130分析:根据两直线平行,同位角相等,即可得出2 的度数解:ab,1=2=50故选B点评:此题考查了平行线的性质,关键是掌握平行线的性质:两直线平行,同位角相等,难度一般文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 Z

22、I8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H

23、6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10

24、 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L

25、9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文

26、档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6

27、P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I

28、10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U65/37 12.(2012?吉林)如图,在RtABC中,C=90 D 为边 CA 延长线上的一点,DE AB,ADE=42,则 B的大小为(A)42 (B)45 (C)48 (D)58解读:C DE AB,ADE=42

29、 CAB=42 C=90 B=90-42=48。考查知识:平行线的性质、三角形的内角和13.(2012 衡阳)如图,直线a直线 c,直线 b直线 c,若 1=70,则2=()A70B90C110D80解读:首先根据垂直于同一条直线的两直线平行可得ab,再根据两直线平行同位角相等可得 1=3根据对顶角相等可得2=3,利用等量代换可得到2=1=70答案:解:直线a直线 c,直线 b直线 c,ab,1=3,3=2,2=1=70故选:A文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10

30、E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10

31、ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10

32、H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G1

33、0 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2

34、L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6

35、文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P

36、6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U66/37 点评:此题主要考查了平行线的判定与性质,关键是掌握平行线的判定方法与性质定理14.(2012 呼和浩特)如图,已知ab,1=65,则

37、2 的度数为A.65 B.125 C.115D.25 ab21【解读】平行线的性质。法一,由ab,根据两直线平行,同位角相等,即可求得3 的度数,又由邻补角的定义,即可求得2 的度数法二,由对顶角相等,可求得4 的度数,再由由ab,根据两直线平行,同旁内角互补求得2 的度数。法一:ab,1=3=65,又2+3=180,2=115法二:1=4=65,ab,4+2=180,2=115ab4321【答案】C【点评】此题考查了平行线的性质注意两直线平行,同位角相等与数形结合思想的应用15.(2012?内江)如图 1,3,1402,651,/00则ba()A.0100 B.0105 C.0110 D.0

38、115【解读】:如图 1:连接 AC,则0231180,0000031801218065140105,故选 B【考点】:本题考查三角形内角和定理,平行线的性质,以及构造图象添加辅助线。16.(2012 绥化)如图,AB ED,ECF=70o,则 BAF的度数为()文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P

39、6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2

40、I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA

41、1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4

42、X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码

43、:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10

44、E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10

45、ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U67/37 A130o B 110o C 70o D 20o【解读】解:ABED,BAC=ECF=70o,BAF=180o-70o=110o故选 B【答案】B【点评】本题主要考查了平行线性质及邻补角概念,考生不难解决此种类型的题目难度较小17.(2012 广元)一辆汽车在公路上行驶,两次拐弯后,仍在原来的方向上平

46、行行驶,那么两个拐弯的角度可能为【】A.先向左转130,再向左转50 B.先向左转50,再向右转50C.先向左转50,再向右转40 D.先向左转50,再向左转40【答案】B。【考点】平行线的性质。【分析】根据题意画出图形,然后利用同位角相等,两直线平行与内错角相等,两直线平行,即可判定:如图:A、1=130,3=50=2。ab,且方向相反;B、1=2=50,ab;C、1=50,2=40,12,a不平行于b;D、2=40,3=140 1,a不平行于 b。故选 B。18.(2012 盐城)一只因损坏而倾斜的椅子,从背后看到的形状如图,其中两组对边的平行关系没有发生变化,若1=750,则 2 的大小

47、是第 6 题图文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I

48、10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1

49、A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X

50、3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:CK2L9D4X3G10 HA1A10H6R2I10 ZI8P6P10E3U6文档编码:

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