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1、第 21 章二次根式教材内容1本单元教学的主要内容:二次根式的概念;二次根式的加减;二次根式的乘除;最简二次根式2本单元在教材中的地位和作用:二次根式是在学完了八年级下册第十七章反比例正函数、第十八章勾股定理及其应用等内容的基础之上继续学习的,它也是今后学习其他数学知识的基础教学目标1知识与技能(1)理解二次根式的概念(2)理解a(a0)是一个非负数,(a)2=a(a0),2a=a(a0)(3)掌握abab(a0,b 0),ab=ab;ab=ab(a 0,b0),ab=ab(a0,b0)(4)了解最简二次根式的概念并灵活运用它们对二次根式进行加减2过程与方法(1)先提出问题,让学生探讨、分析问
2、题,师生共同归纳,得出概念?再对概念的内涵进行分析,得出几个重要结论,并运用这些重要结论进行二次根式的计算和化简(2)用具体数据探究规律,用不完全归纳法得出二次根式的乘(除)法规定,?并运用规定进行计算(3)利用逆向思维,?得出二次根式的乘(除)法规定的逆向等式并运用它进行化简(4)通过分析前面的计算和化简结果,抓住它们的共同特点,?给出最简二次根式的概念利用最简二次根式的概念,来对相同的二次根式进行合并,达到对二次根式进行计算和化简的目的3情感、态度与价值观通过本单元的学习培养学生:利用规定准确计算和化简的严谨的科学精神,经过探索二次根式的重要结论,二次根式的乘除规定,发展学生观察、分析、发
3、现问题的能力教学重点1二次根式a(a0)的内涵a(a0)是一个非负数;(a)2a(a0);2a=a(a0)?及其运用2二次根式乘除法的规定及其运用3最简二次根式的概念4二次根式的加减运算教学难点文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4
4、I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W
5、2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7
6、V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5
7、E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E
8、7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5
9、C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I8文档编码:CO2E7W2E9P4 HG5Y5C7V1W10 ZH3U1V5E4I81对a(a0)是一个非负数的理解;对等式(a)2 a(a0)及2a=a
10、(a0)的理解及应用2二次根式的乘法、除法的条件限制3利用最简二次根式的概念把一个二次根式化成最简二次根式教学关键1潜移默化地培养学生从具体到一般的推理能力,突出重点,突破难点2培养学生利用二次根式的规定和重要结论进行准确计算的能力,?培养学生一丝不苟的科学精神单元课时划分本单元教学时间约需11 课时,具体分配如下:211 二次根式3 课时212 二次根式的乘法3 课时213 二次根式的加减3 课时教学活动、习题课、小结2 课时211 二次根式第一课时教学内容二次根式的概念及其运用教学目标理解二次根式的概念,并利用a(a0)的意义解答具体题目提出问题,根据问题给出概念,应用概念解决实际问题教学
11、重难点关键1重点:形如a(a0)的式子叫做二次根式的概念;2难点与关键:利用“a(a0)”解决具体问题教学过程一、复习引入(学生活动)请同学们独立完成下列三个问题:问题 1:已知反比例函数y=3x,那么它的图象在第一象限横、?纵坐标相等的点的坐标是 _问题 2:如图,在直角三角形ABC 中,AC=3,BC=1,C=90,那么 AB 边的长是_文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:
12、CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5
13、HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 Z
14、F5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编
15、码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H
16、5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4
17、 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文
18、档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6BAC问题 3:甲射击6 次,各次击中的环数如下:8、7、9、9、7、8,那么甲这次射击的方差是 S2,那么 S=_老师点评:问题 1:横、纵坐标相等,即x=y,所以 x2=3因为点在第一象限,所以x=3,所以所求点的坐标(3,3)问题 2:由勾股定理得AB=10问题 3:由方差的概念得S=46.二、探索新知很明显3、10、46,都是一些正数的算术平方根像这样一些正数的算术平方根的式子,我们就把它称二次根式因此,一般地,我们把形如a(a0)?的式子叫做二次根式,“”称为二次根号(学生活动)议一议:1-1 有算术平方
19、根吗?20的算术平方根是多少?3当 a0)、0、42、-2、1xy、xy(x0,y?0)分析:二次根式应满足两个条件:第一,有二次根号“”;第二,被开方数是正数文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10
20、H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q
21、4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6
22、文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U
23、10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C
24、3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1
25、D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6或 0解:二次根式有:2、x(x0)、0、-2、xy(x0,y0);不是二次根式的有:33、1x、42、
26、1xy例 2当 x 是多少时,31x在实数范围内有意义?分析:由二次根式的定义可知,被开方数一定要大于或等于0,所以 3x-10,?31x才能有意义解:由 3x-10,得:x13当 x13时,31x在实数范围内有意义三、巩固练习教材 P 练习 1、2、3四、应用拓展例 3当 x 是多少时,23x+11x在实数范围内有意义?分析:要使23x+11x在实数范围内有意义,必须同时满足23x中的 0 和11x中的 x+10解:依题意,得23010 xx由得:x-32由得:x-1 当 x-32且 x-1 时,23x+11x在实数范围内有意义例 4(1)已知 y=2x+2x+5,求xy的值(答案:2)(2
27、)若1a+1b=0,求 a2004+b2004的值(答案:25)五、归纳小结(学生活动,老师点评)本节课要掌握:文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1
28、D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O
29、2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I
30、3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6
31、C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R
32、5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T
33、4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D61形如a(a0)的式子叫做二次根式,“”称为二次根号2要使二次根式在实数范围内有意义,必须满足被开方数是非负数六、布置作业1教材 P8复习巩固1、综合应
34、用52选用课时作业设计第一课时作业设计一、选择题1下列式子中,是二次根式的是()A-7B37CxDx 2下列式子中,不是二次根式的是()A4B16C8D1x3已知一个正方形的面积是5,那么它的边长是()A5 B5C15D以上皆不对二、填空题1形如 _的式子叫做二次根式2面积为 a 的正方形的边长为_3负数 _平方根三、综合提高题1某工厂要制作一批体积为1m3的产品包装盒,其高为0.2m,按设计需要,?底面应做成正方形,试问底面边长应是多少?2当 x 是多少时,23xx+x2在实数范围内有意义?3若3x+3x有意义,则2x=_4.使式子2(5)x有意义的未知数x 有()个A0 B1 C2 D无数
35、5.已知 a、b 为实数,且5a+2102a=b+4,求 a、b 的值第一课时作业设计答案:一、1A 2 D 3B 二、1a(a0)2a3没有文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I
36、3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6
37、C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R
38、5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T
39、4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4
40、Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF
41、8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6三、1设底面边长为x,则 0.2x2=1,解答:x=52依题意得:2300 xx,320 xx当 x-32且 x0 时,2
42、3xxx2在实数范围内没有意义3.134B 5a=5,b=-4 21.1 二次根式(2)第二课时教学内容1a(a 0)是一个非负数;2(a)2=a(a0)教学目标理解a(a0)是一个非负数和(a)2=a(a 0),并利用它们进行计算和化简通过复习二次根式的概念,用逻辑推理的方法推出a(a0)是一个非负数,用具体数据结合算术平方根的意义导出(a)2=a(a 0);最后运用结论严谨解题教学重难点关键1重点:a(a0)是一个非负数;(a)2=a(a0)及其运用2难点、关键:用分类思想的方法导出a(a0)是一个非负数;?用探究的方法导出(a)2=a(a0)教学过程一、复习引入文档编码:CF8R5O2U
43、10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C
44、3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1
45、D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O
46、2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I
47、3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6
48、C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R
49、5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6文档编码:CF8R5O2U10H5 HS6T4I3C3Q4 ZF5D4Z6C1D6(学生活动)口答1什么叫二次根式?2当 a0 时,a叫什么?当a0;(2)a20;(3)a2+2a+1=(a+1)0;(4)4x2-12x+9=(2x)2-22x 3+32=(2x-3)20所以上面的4 题都可以运用(a)2=a(a0)的重要结论解题解:(1)因为 x0,所以 x+10(1
50、x)2=x+1(2)a20,(2a)2=a2(3)a2+2a+1=(a+1)2 又(a+1)20,a2+2a+10,221aa=a2+2a+1(4)4x2-12x+9=(2x)2-22x3+32=(2x-3)2 又(2x-3)20 4x2-12x+90,(24129xx)2=4x2-12x+9 例 3 在实数范围内分解下列因式:(1)x2-3(2)x4-4(3)2x2-3 分析:(略)五、归纳小结本节课应掌握:1a(a 0)是一个非负数;2(a)2=a(a0);反之:a=(a)2(a0)六、布置作业1教材 P8复习巩固2(1)、(2)P9 7文档编码:CF8R5O2U10H5 HS6T4I3C