2022年三角形手拉手模型专题讲义 .pdf

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1、手拉手模型1、等边三角形条件:OAB,OCD 均为等边三角形结论:;导角核心:八字导角2、等腰直角三角形条件:OAB,OCD 均为等腰直角三角形结论:;导角核心:3、任意等腰三角形条件:OAB,OCD 均为等腰三角形,且 AOB=COD 结论:;核心图形:核心条件:;例题讲解:A类1:在直线 ABC的同一侧作两个等边三角形ABD和 BCE,连接 AE与 CD,等边三角形要得到哪些结论?要联想到什么模型?文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T

2、10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 H

3、N3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8

4、T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 Z

5、K8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9

6、Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文

7、档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV

8、9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10文档编码:CV9L8E5T10M1 HN3D2C8T4M5 ZK8L7Y9Z9X10证明:(1)ABE DBC;(2)AE=DC;(3)AE与 DC的夹角为 60;(4)AGB DFB;(5)EGB CFB;(6)BH平分AHC;解题思路:1:出现共顶点的等边三角形,联想手拉手模型2:利用边角边证明全等;3:八字导角得角相等;2:如图两个等腰直角三角形ADC与 EDG,连接 AG,CE,二者相交于 H.问(1)ADG CDE是否成立?(2)A

9、G是否与 CE相等?(3)AG与 CE之间的夹角为多少度?(4)HD是否平分AHE?等腰直角三角形要得到哪些结论?要联想到什么模型?文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9

10、ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文

11、档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9

12、J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T

13、9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N

14、3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8

15、R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3解题思路:1:出现共顶点的等腰直角三角形,联想手拉手模型2:利用边角边证明全等;3:八字导角得角相等;3:如图,分别以ABC 的边

16、AB、AC 同时向外作等腰直角三角形,其中 AB=AE,AC=AD,BAE=CAD=90,点G为 BC中点,点 F 为 BE 中点,点 H 为 CD中点。探索GF 与GH 的位置及数量关系并说明理由。多个中点,一般考虑什么?等腰直角三角形要得到哪些结论?要联想到什么模型?文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3

17、文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R

18、9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5

19、T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9

20、N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K

21、8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1

22、J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2

23、Z9N3解题思路:1:有两个共顶点的等腰直角三角形,联想手拉手全等,连接BD,CE,BAD EAC 2:多个中点,联想中位线,得线段关系B类1:如图 1,已知DAC=90,ABC是等边三角形,点P为射线 AD任意一点(P 与 A 不重合),连结 CP,将线段 CP绕点 C顺时针旋转60得到线段CQ,连结 QB并延长交直线AD于点E.(1)如图 1,猜想QEP=_;旋转 60,要做什么?出现等边三角形,要想到哪些?文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3

24、K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X

25、1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U

26、2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2

27、K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q

28、4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W1

29、0U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:C

30、D2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3(2)如图 2,3,若当DAC是锐角或钝角时,其它条件不变,猜想QEP 的度数,选取一种情况加以证明;(3)如图 3,若DAC=135,ACP=15,且AC=4,求 BQ的长解题思路:1:旋转 60,出现等边三角形2:两个共顶点的三角形,联想手拉手全等3:求线段长度,利用勾股定理求线段长有哪些方法?有特殊的钝角,需要做什么?文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5

31、Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W

32、10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:

33、CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 H

34、T5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO

35、6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编

36、码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5

37、 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N32:在ABC中,2ABBC,90ABC,BD为斜边 AC上的中线,将ABD 绕点 D 顺时针旋转(0180)得到EFD,其中点 A的对应点为点E,点 B的对应点为点F,BE与 FC相交于点 H.(1)如图 1,直接写出BE与 FC的数量关系:_;(2)如图 2,M、N分别为 EF、BC的中点.求证:MNCF22;(3)连接 BF,CE,如图 3,直接写出在此旋转过程中,线段BF、CE

38、与 AC之间的数量关系:.解题思路:线段的关系都有哪些?出现中点要想到什么?等腰直角三角形绕顶点旋转,是什么模型?等腰直角三角形斜边的中线可以得到什么?文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT

39、5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6

40、W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码

41、:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5

42、HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 Z

43、O6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档

44、编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N31:等腰直角三角形斜边的中线把三角形分成两个相同的等腰直角三角形2:等腰直角三角形绕顶点旋转,联想手拉手模型3:

45、等腰直角三角形中出现中点,联想斜边中点4:利用勾股定理得线段关系3:在 Rt ABC中,90ACB,D是 AB的中点,DE BC于 E,连接 CD(1)如图 1,如果30A,那么 DE与 CE之间的数量关系是_(2)如图 2,在(1)的条件下,P是线段 CB上一点,连接DP,将线段 DP绕点 D逆时针旋转 60,得到线段 DF,连接 BF,请猜想 DE、BF、BP三者之间的数量关系,并证明你的结论(3)如图 3,如果A(090),P 是射线 CB上一动点(不与B、C重合),连接 DP,将线段 DP绕点 D逆时针旋转 2,得到线段 DF,连接 BF,请直接写出DE、BF、BP三者之间的数量关系(

46、不需证明)线段关系,一般有哪些?旋转 60,要做什么,还要联想什么?直角+中点,联想什么?文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K

47、3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4

48、X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10

49、U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD

50、2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5Q4X1J5T9 ZO6W10U2Z9N3文档编码:CD2K3K8R9J5 HT5

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