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1、2016 年八年级数学上册期中测试题（北师大版教材全解带答案和解释）二、填空题（每小题3 分，共 24 分）11.（2016•山东潍坊中考）计算：（+）=_.12.（宁夏中考）点P（a，a3）在第四象限，则a 的取值范围是.13.已知点 P（3，1）关于 y 轴的对称点Q 的坐标是（a+b，1b），则 ab 的值为 _.14.（2015•广州中考）某水库的水位在5 小时内持续上涨，初始的水位高度为6 米，水位以每小时0.3 米的速度匀速上升，则水库的水位高度y 米与时间x 小时（0 x5）的函数关系式为_.15.在 ABC 中，a，b，c 为其三边长，则 ABC是_.1
2、6.（甘肃白银中考）在等腰ABC 中，AB=AC=10 cm，BC=12 cm，则 BC 边上的高是 _cm17.若在 第 二、四 象 限 的 角 平 分 线 上,与的 关 系 是_.18（2016•哈尔滨中考）在等腰直角三角形ABC 中，ACB=90 ，AC=3，点 P 为边 BC 的三等分点，连接AP，则 AP 的长为三、解答题（共66 分）19.（8 分）如图，已知等腰ABC 的周长是16，底边BC上的高 AD 的长是 4，求这个三角形各边的长.20.（8 分）计算：（1）；（2）；（3）；（4）；（5）；（6）.21.（8 分）在平面直角坐标系中,顺次连接（-2,1）,（-
3、2,-1）,（2,-2）,（2,3）各点,你会得到一个什么图形?试求出该图形的面积.22（8 分）已知和 8b3互为相反数，求27 的值.23.（8 分）（湖南怀化中考）设一次函数y=kx+b（k0）的图象经过 A（1，3），B（0，2）两点，试求k，b 的值24.（8 分）一架云梯长25 m，如图所示斜靠在一面墙上，梯子底端 C 离墙 7 m.（1）这个梯子的顶端A 距地面有多高？（2）如果梯子的顶端下滑了4 m，那么梯子的底部在水平方向也是滑动了4 m 吗？文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5
4、T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6
5、I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X
6、2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1
7、F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5
8、B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A
9、8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4
10、T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3第 24 题图 第 25 题图25.（8 分）（2015•浙江丽水中考）甲、乙两人匀速从同一地点到1 500 米处的图书馆看书，甲出发5 分钟后，乙以 50 米/分的速度沿同一路线行走.设甲、乙两人相距（米），甲行走的时间为（分），关于的函数图象的一部分如图所示.（1）求甲行走的速度；（2）在坐标系中，补画s关于 t 的函数图象的其余部分；（3）问甲、乙两人何时相距360 米？26.
11、（10 分）（2015•湖北孝感中考）某服装公司招工广告承诺：熟练工人每月工资至少3 000 元，每天工作8 小时，一个月工作25 天，月工资底薪800 元，另加计件工资.加工 1 件 A 型服装计酬16 元，加工 1 件 B 型服装计酬12元.在工作中发现一名熟练工加工1 件 A 型服装和2 件 B 型服装需 4 小时，加工3 件 A 型服装和1 件 B 型服装需7 小时.（工人月工资底薪+计件工资）（1）一名熟练工加工1 件 A 型服装和 1 件 B 型服装各需要多少小时？文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2
12、M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F
13、5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B
14、6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8
15、X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T
16、1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S
17、5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4
18、A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3（2）一段时间后,公司规定：“每名工人每月必须加工A,B两种型号的服装，且加工A 型服装数量不少于B 型服装的一半”.设一名熟练工人每月加工A 型服装 a 件，工资总额为W 元，请你运用所学知识判断该公司在执行规定后是否违背了广告承诺？期中检测题参考答案一、选择题1.C 解析：因为整数与分数都是有理数,所以 0.7，8 都是有理数，无理数就是无限不循环小数，是无理数.
19、2.C 解析：选项A 中，选项 B 中，选项 D 中,所以只有选项 C 中 正确.3.D 解析：8190100，即 9 10，k=9.4.D 解析：因为，所以 A 项错误；因为，所以 B 项错误；因为，所以 C 项错误；因为，所以 D 项正确.5.D 解析：判断一个三角形是不是直角三角形有以下方法：有一个角是直角或两锐角互余；文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M
20、2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5
21、T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6
22、I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X
23、2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1
24、F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5
25、B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A
26、8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3两边的平方和等于第三边的平方；一边的中线等于这条边的一半.由 A 得有一个角是直角.B、C 满足勾股定理的逆定理，故选D.6.C 解析：因直角三角形的斜边不明确，结合勾股定理可求得第三边的长为5 或，所以直角三角形的周长为34512 或 34 7，故选 C.7.D 解析：筷子在杯中的最大长度为17（cm），最短长度为 8 cm，则筷子露在杯子外面的长度h 的取值范围是2417h248，即 7h16，故选 D.8.C 解析:关于原点对称的点的坐标的特点是横、纵坐标均互为相反数，所以点（2，3）关于原点的对称点为（2，3）.根据平移的
27、性质，结合直角坐标系，（2，3）点向左平移2个单位长度，即横坐标减2，纵坐标不变.故选 C.9.B 解析:当 b0 时，点（0，b）在 y 轴的负半轴上，直线与y 轴交于负半轴又，所以直线与 x 轴不平行.故选 B.10.D 解析：设直线的表达式为，直线经过第一、二、三象限，函数值随 的增大而增大.，故 A 项错误；，故B 项错误；，故 C 项错误；，故 D 项正确.二、填空题11.12 解析：（+）=+=（）2+=3+9=12.12.0a3 解析：本题考查了各象限内点的坐标的符号特征文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2
28、H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T
29、5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I
30、3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2
31、M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F
32、5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B
33、6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8
34、X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3以及不等式的解法.点 P（a，a3）在第四象限，a>0，a3<0，解得 0a313.25 解析：本题考查了关于y 轴对称的点的坐标特点，关于 y 轴对称的点的横坐标互为相反数，纵坐标相同，可得ab 3，1b 1，解得 b2，a 5，ab25.14.y=0.3x+6 解析：因为水库的初始水位高度是6 米，每小时上升 0.3 米，所以 y 与 x的函数关系式为y=
35、0.3x+6（0 x5）.15.直角三角形解析：因为所以是直角三角形.16.8 解析：如图，AD 是 BC 边上的高线 AB=AC=10 cm，BC=12 cm，BD=CD=6 cm，在 RtABD 中，由勾股定理，得AD=8（cm）17.互为相反数解析:第二、四象限的角平分线上的点的横、纵坐标的绝对值相等,?符号相反.18.或 解析：(1)如图(1)，ACB=90，AC=BC=3，PB=BC=1，PC=2，AP=.(2)如图(2)，ACB=90，AC=BC=3，PC=BC=1，AP=.综上所述，AP 的长为或 文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3
36、文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M
37、2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5
38、T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6
39、I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X
40、2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1
41、F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5
42、B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3三、解答题19.解：设，由等腰三角形的性质，知.由勾股定理，得，即，解得，所以，20.解：（1）.（2）.（3）（4）（5）（6）.21.解:梯形.因为 ABCD，的长为 2,的长为 5,与 之间的距离为 4,所以梯形 ABCD 14.22.解:因为 0，8b30，且 和 8b3互为相反数，所以8b3所以所以27642737.23.分析：直接把
43、 A 点和 B 点的坐标分别代入y=kx+b，得到文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5
44、ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文
45、档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2
46、H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T
47、5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I
48、3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2
49、M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3文档编码:CA4A8X2M2H3 HD2A4T1F5T5 ZW5L10S5B6I3关于 k 和 b 的方程组，然后解方程组即可.解：把（1，3）、（0，2）分别代入y=kx+b，得 解得即 k，b 的值分别为5，224.分析：（1）可设这个梯子的顶端A 距地面有x m 高，因为云梯长、梯子底端离
50、墙距离、梯子的顶端距地面高度是直角三角形的三边长，所以x2+72=252，解出 x 即可.（2）如果梯子的顶端下滑了4 m，那么梯子的底部在水平方向不一定滑动了4 m，应计算才能确定.解：（1）设这个梯子的顶端A 距地面有x m 高，根据题意，得AB2+BC2=AC2，即 x2+72=252，解得 x=24，即这个梯子的顶端A 距地面有 24 m 高.（2）不是.理由如下：如果梯子的顶端下滑了4 m，即 AD=4 m,BD=20 m.设梯子底端E 离墙距离为y m，根据题意，得BD2+BE2=DE2，即 202+y2=252，解得 y=15.此时 CE=15 7=8（m）.所以梯子的底部在水平