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1、?d?d ?d ?d c(t) + Ker(Tt)= p(t) + S(t). y X y | A c(t) K ?y7?x| X y | BwO?I? XJ S(T) Ky |3 T ?d S(T) XJ S(T) Ky |3 T ?d K gI?uI?w! wO?B c(t) p(t) = K Ker(Tt) 0. d?Ay ?d c(t) + Ker(Tt)= p(t) + S(t). X ?S(t) = c(t) + Ker(Tt) p(t) X Ker(Tt)= p(t) + S(t) c(t) X w?c(t) = p(t) + S(t) Ker(Tt) X wO?p(t) = c
2、(t) + Ker(Tt) S(t) - 3d=I61XL/ai?J| I?|E 6d=17K?kD1?d=5 n*?E|E!|E ?d? ?d? S(t) K C(t) P(t) S(t) Ker(Tt). m5gu?dP(t) p(t), C(t) = c(t) u5XJS(t) + P(t) C(t) + K 1. 3 t ?|m?|y76 ? 2. XJ P 3 1?a|G K S() 3. XJ P 1?3?F C 1? ?d|dX n ?“ ? H+n? wO?d1d? ?d?p(K1) p(K2)( 0) K1K2 K2 (K2 K1) 0 K1 ST (K2 ST)+ (K1
3、ST)+ |? wO?d1d? ?d?puts+ ( K2 K1 0) p(K1) p(K2) + (K2 K1) B K1K2 K2 0 +(K2 K1) K1 ST (K2 ST)+ (K1 ST)+ K2 K1 |? wO?d1d? ?d?puts+ ( K2 K1 0) p(K1) p(K2) + (K2 K1) B ( 0) Td?KX1dzO 1wO ?dOL 1 ?y 0 p(K2) p(K1) K2 K1 B0 p K B w?d1d? =?d?calls+ ( K2 K1 0) c(K2) c(K1) + (K2 K1) B K1K2 0 (K2 K1) ST (ST K2)
4、+ (ST K1)+ |? w?d1d? =?d?calls+ ( K2 K1 0) c(K2) c(K1) + (K2 K1) B ( 0) Td?KX1dzO 1w ?d$L 1 ?y B c(K2) c(K1) K2 K1 0B c K 0 ? ? X u?|y?O3u? U3?1?1?m X XJ?Jc1?7LduR?d ?1d?|E X u?1dl K1Cz K2| 3?A?dCzpu |K2 K1| ? d?|? (K2 K1) C(K2) C(K1) 0 1 C K 0 0 P(K2) P(K1) (K2 K1) 0 P K 1. f Kp3|? ?c?d 100c?1d 100 ?wO ?d 2.5c?1d 110 ?wO?d 12.25ly3?F?1?| 5% X p(110)p(100) = 9.75 9.5238 = 110 100 1 + 0.05 3| X |1d 110 ?wO?1d 100 ?wO?y7 9.75 5% ?| 1?y76 10.2375 I. ?d1d? ff?E?|? 100 110 10 0 10.2375 ST (K2 ST)+ (K1 ST)+ ? |?