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1、-1 2019(550)B-2 1 1 5aVI7a,b,c 8a=(1,2),b=(x 1,-x),a _ bx x 9f(x)=2sin(),x,RAx x.3l,Bx 0Ag B 3,4 2 2f(x)=3x lg(3x 1)J1 _x C-2,1-1:D f 1)-f 1 1 1 B.,1 C.-I D.1-co _.3 3,1 3,3 1,3 3p:X R,sin x _1,A_p:x R,sin x 1 C p:x R,sin x 1 4CaJa2,a5_p:_x _p:_x BD 1,q=4R,sin x 1 R,sin x 1 C2 A c:a:b 6AB a,AC b,BD=
2、3DC,1+4 T T a,bAD,AD=(1 1 u C.a b 4 4 7y=x3-2x 1(1,0)A y=x-1 B y-x 1 C y=2x-2 Aa 3b 4 BDf(x)2sin x,x RA D1 A 6 B 6 C 6 D 6 10yf(x)la,b l(a:b)yf(x)a,bl(a:b 11a n=n$-1,Na5=_ 12(sin J COST)2=2,v,13f(x)-f(x 1)f(-1)=2f f(1)=_ 2 14f(x)m2-3m 3 xm0m15Mf(x)Xf(x 1)=f(x)f(1)f(x)=1 f(x)=2x f(x)=lg(x2 2)x f(x)co
3、sxM3 1 3 33-3 (550)()12 3 4 5 6 7 8 9 10 (525)11 12 13 14 15 (16171819 12 20132114 75)2 J L 16f(x)=2cos x 2sinxcosx 1(x R 0)2(I)(n)f(x)f(x)x17a?=5,a5=14-4 (I)(n)an nSn=155n 18a,b,cABCA,B,Csin?A sin?C sin?B=sin Asin C(I)B(n)c=3atan A 5 2 2 a 19a-,an i N*3 an+1(I)A J(n)2nSlanj 2 20f(x)=x 1-alnx,a 0 x(
4、I)a=3f(x)1,e2(n)f(x)21f(xex(ax2 x 1)y=f(x)x=1x(I)a(n)f(x)-0,2 f(cosR-f(sin 2-6 B B A D D E AACA 11.9 12x 1 13.-2 14.1 15.16I)j(x)=cos2+sin2x+2=V2sm(2iPA+)+2 4 7*=m=2 .4 2B 2 C II)I)/(x)=2 sm(4x+)1-2 J28 4 ittLtze*x x=+,4;z*12 I 16 2 J 17(I);.aaid,11=155“1010.12 18(I)a2 c2-b2 ac cos B a2 c2 b2 2ac 1/
5、(II)(I)268-7 B .6 3(II)c=3a i G=3sm A .8 sin(-A)=3sinA 10 COS-4+sin A=3sin Atan 12 2 2 5 19(I)in N*-,nN*2an+1 a4 2an 2a.2 1 1111 1(1),nN*an1 2an 2 2an 2(II)I 2+1*2 2T 1+21.+U 2 1 2 =2+F+F =22B .11 12 20I)=3f(x)x2-3x 2 2 x(x-2)(x-1)2 x 1,2 2,e2 f(x)LI 8 (H)f(x)ex(-x2-x 2)-ex(x 2)(x-1).5 x,2U1,=f(x)0
6、x,(-2,1)f(x)0f(x)-2,1,(-2,1)8(H)f(x)10,1 1f(x)10,11f(1)=e,f(x)0 23In 2 e2-g-5 e 2-3(11)A 0&|10 a 0a 2 x:a-Pa-8 I0,c I 2 f(x)+f(x):f(x)a-Ja-8 a+Ja-8 2,2 y 21(I)f(x)=a=T a Y:a2-8 Ja2-8!2 f|a_&a-8 I 13ex(ax2 x 1 2ax 1)f(1)=0,a 3 2 0 -9 f(0)=1,X,X20,11 f(Xi)-f(X2)e-1.2 0,cos,si nT|0,i f(cosB)f(si nT)c2 1014