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1、#include int index(int x,int n);unsigned int f(int a,int n,unsigned int R,char*kx);void infor();void main()char m8,k8;char IP64=58,50,42,34,26,18,10,2,60,52,44,36,28,20,12,4,62,54,46,38,30,22,14,6,64,56,48,40,32,24,16,8,57,49,41,33,25,17,9,1,59,51,43,35,27,19,11,3,61,53,45,37,29,21,13,5,63,55,47,39,
2、31,23,15,7;char zm064,zm164;char IP_164=40,8,48,16,56,24,64,32,39,7,47,15,55,23,63,31,38,6,46,14,54,22,62,30,37,5,45,13,53,21,61,29,36,4,44,12,52,20,60,28,35,3,43,11,51,19,59,27,34,2,42,10,50,18,58,26,33,1,41,9,49,17,57,25;int i,n=1,a,over;unsigned int L=0,R=0,middle,res2=0,0;infor();printf(请连续输入明文（
3、密文）和密钥(16 位)：n);for(i=0;i8;i+)scanf(%c,&mi);for(i=0;i8;i+)scanf(%c,&ki);printf(你输入的明文（密文）是(十进制):n);for(i=0;i8;i+)printf(%d,mi);printf(n 你输入的密钥是(十进制):n);for(i=0;i8;i+)printf(%d,ki);for(i=0;i(7-i%8)&1;for(i=0;i64;i+)zm1i=zm0IPi-1;for(i=0;i32;i+)L=index(2,31-i)*zm1i+L;for(i=32;i64;i+)R=index(2,31-(i-32
4、)*zm1i+R;printf(n 请选择加密还是解密：（加密输入非零数，解密输入0）n);scanf(%d,&a);do/进行十六次迭代 middle=L;L=R;R=middlef(a,n,R,k);n+;while(n=16);middle=L;/交换左右分量L=R;R=middle;for(i=0;i(31-i)&1;for(i=32;i(31-(i-32)&1;for(i=0;i64;i+)zm0i=zm1IP_1i-1;for(i=0;i32;i+)res0=index(2,31-i)*zm0i+res0;for(i=32;i64;i+)/检结果保存在无符号整形数组res中res1
5、=index(2,31-(i-32)*zm0i+res1;printf(加密（解密）结果是：n);printf(%x,%xn,res0,res1);printf(按任意键结束。);scanf(%d,&over);int index(int x,int n)/简单的指数子函数 int i=0,j=n;int Pro=1;for(;in;i+)Pro=Pro*x;return Pro;unsigned int f(int a,int n,unsigned int R,char*kx)/定义的 F 函数 char E48=32,1,2,3,4,5,4,5,6,7,8,9,8,9,10,11,12,1
6、3,12,13,14,15,16,17,16,17,18,19,20,21,20,21,22,23,24,25,24,25,26,27,28,29,28,29,30,31,32,1;char zm232,zm348,zm464,C28,D28,tzjc,tzjd,zm556,kmy48,sbh32;int i,n0=1,t;char PC_128=57,49,41,33,25,17,9,1,58,50,42,34,26,18,10,2,59,51,43,35,27,19,11,3,60,52,44,36;char PC_228=63,55,47,39,31,23,15,7,62,54,46,3
7、8,30,22,14,6,61,53,45,37,29,21,13,5,28,20,12,4;char PC248=14,17,11,24,1,5,3,28,15,6,21,10,23,19,12,4,26,8,16,7,27,20,13,2,41,52,31,37,47,55,30,40,51,45,33,48,44,49,39,56,34,53,46,42,50,36,29,32;char S864=14,4,13,1,2,15,11,8,3,10,6,12,5,9,0,7,0,15,7,4,14,2,13,1,10,6,12,11,9,5,3,8,4,1,14,8,13,6,2,11,1
8、5,12,9,7,3,10,5,0,15,12,8,2,4,9,1,7,5,11,3,14,10,0,6,13,15,1,8,14,6,11,3,4,9,7,2,13,12,0,5,10,3,13,4,7,15,2,8,14,12,0,1,10,6,9,11,5,0,14,7,11,10,4,13,1,5,8,12,6,9,3,2,15,13,8,10,1,3,15,4,2,11,6,7,12,0,5,14,9,10,0,9,14,6,3,15,5,1,13,12,7,11,4,2,8,13,7,0,9,3,4,6,10,2,8,5,14,12,11,15,1,13,6,4,9,8,15,3,
9、0,11,1,2,12,5,10,14,7,1,10,13,0,6,9,8,7,4,15,14,3,11,5,2,12,7,13,14,3,0,6,9,10,1,2,8,5,11,12,4,15,13,8,11,5,6,15,0,3,4,7,2,12,1,10,14,9,10,6,9,0,12,11,7,13,15,1,3,14,5,2,8,4,3,15,0,6,10,1,13,8,9,4,5,11,12,7,2,14,2,12,4,1,7,10,11,6,8,5,3,15,13,0,14,9,14,11,2,12,4,7,13,1,5,0,15,10,3,9,8,6,4,2,1,11,10,
10、13,7,8,15,9,12,5,6,3,0,14,11,8,12,7,1,14,2,13,6,15,0,9,10,4,5,3,12,1,10,15,9,2,6,8,0,13,3,4,14,7,5,11,10,15,4,2,7,12,9,5,6,1,13,14,0,11,3,8,9,14,15,5,2,8,12,3,7,0,4,10,1,13,11,6,4,3,2,12,9,5,15,10,11,14,1,7,6,0,8,13,4,11,2,14,15,0,8,13,3,12,9,7,5,10,6,1,13,0,11,7,4,9,1,10,14,3,5,12,2,15,8,6,1,4,11,1
11、3,12,3,7,14,10,15,6,8,0,5,9,2,6,11,13,8,1,4,10,7,9,5,0,15,14,2,3,12,13,2,8,4,6,15,11,1,10,9,3,14,5,0,12,7,1,15,13,8,10,3,7,4,12,5,6,11,0,14,9,2,7,11,4,1,9,12,14,2,0,6,10,13,15,3,5,8,2,1,14,7,4,10,8,13,15,12,9,0,3,5,6,11;char P32=16,7,20,21,29,12,28,17,1,15,23,26,5,18,31,10,2,8,24,14,32,27,3,9,19,13,
12、30,6,22,11,4,25;if(a=0)n=17-n;for(i=0;i(7-i%8)&1;/进行 PC1 置换for(i=0;i28;i+)Ci=zm4PC_1i-1;for(i=0;i28;i+)Di=zm4PC_2i-1;do/循环移位tzjc=C0;tzjd=D0;for(i=0;i27;i+)Ci=Ci+1;Di=Di+1;C27=tzjc;D27=tzjd;if(n0!=1)&(n0!=2)&(n0!=9)&(n0!=16)tzjc=C0;tzjd=D0;for(i=0;i27;i+)Ci=Ci+1;Di=Di+1;C27=tzjc;D27=tzjd;n0+;while(n0
13、=n);for(i=0;i28;i+)/进行 PC2 置换zm5i=Ci;for(i=28;i56;i+)zm5i=Di-28;for(i=0;i48;i+)kmyi=zm5PC2i-1;for(i=0;i(31-i)&1;for(i=0;i48;i+)zm3i=zm2Ei-1;for(i=0;i48;i+)/zm3 与子密钥异或zm3i=zm3ikmyi;for(i=0;i(3-i%4)&1;for(i=0;i32;i+)/进行 p 置换zm2i=sbhPi-1;R=0;for(i=0;i32;i+)R=index(2,31-i)*zm2i+R;return R;/返回无符号整形数 void infor()printf(提示：n);printf(1.输入密文或明文还有密钥时，按字符型输入，实际存进去的是此字符的ASC码n);printf(2.如果不想按字符输入，可以打开源程序，给k【8】和 m【8】进行整型赋值，但n 不要超过255n);printf(3.此程序输出结果为两个十六进制无符号整型数，如果不够八位请自己在相应数n 的高位补上零 n);printf(4.输入明文（密文）和密钥时，要连续输入字符n);printf(*n);