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1、班级班级 建筑 141姓名姓名 钟诚学号学号指导老师指导老师 Tony1建筑物理建筑物理 2 2 热工学大作业热工学大作业1.1.查资料得查资料得:宁波市冬季日平均气温在 513之间，则取室外温度为 t1=7，室内适宜温度取为 t2=22，室内外温差 15.2.2.建筑维护结构材料的选取建筑维护结构材料的选取墙体：墙体分外墙、保温层和内墙 外墙（d1=240mm)和内墙(d2=140mm)材料为灰砂石砌体，=1.10；保温层材料(d3=60mm)为矿棉板，=0.050屋顶：钢筋混凝土（d1=30mm）=1.74；保温砂浆(d2=20mm)=0.29；油毡防水层(d3=10mm)=0.17楼地面
2、：钢筋混凝土(d=150mm)=1.74门：胶合板(d=50mm)=0.17窗：单层玻璃 材料取平板玻璃(d=5mm)=0.76 窗框窗洞面积比 25%23.3.传热阻计算传热阻计算墙体：R1=0.24/1.10=0.218(K/W)R2=0.14/1.10=0.127(K/W)R3=0.06/0.05=1.2(K/W)R(wall)=Ri+R1+R2+R3+Re=0.11+0.218+0.127+1.2+0.04=1.695(K/W)屋顶：R1=0.03/1.74=0.017(K/W)R2=0.02/0.29=0.069(K/W)R3=0.01/0.17=0.059(K/W)R(roof)=
3、Ri+R1+R2+R3+Re=0.11+0.017+0.069+0.059+0.04=0.295(K/W)楼地面:R1=0.150/1.74=0.086(K/W)R(floor)=Ri+R1+Re=0.11+0.086+0.08=0.276(K/W)门:R1=0.05/0.17=0.294(K/W)R(door)=Ri+R1+Re=0.11+0.294+0.04=0.444(K/W)窗：R1=0.005/0.76=0.0066(K/W)R(window)=Ri+R1+Re=0.11+0.0066+0.04=0.1566(K/W)34.4.面积计算面积计算long=5.6m wide=3.31m
4、 high=3.05m+0.2m=3.25m（假设室内比室外高 0.2m)墙体：A1(west wall)=5.6x3.25=18.2A2(north wall)=2.01x3.25+0.7x3.25=8.8 A3(east wall)=4.3x3.25+1.3x3.25-0.87x2.07=16.4A4(south wall)=3.31x3.25-2.38x1.45=5.35 A(wall)=18.2+8.8+16.4+5.35=48.75 楼板:A(roof)=5.6x3.31-0.7x1.3=17.626楼地面:A(floor)=5.6x3.31-0.7x1.3=17.626前门:A(d
5、oor)=0.87x2.07=1.8009 铝合门窗:A(window)=2.38x1.45=3.451 45.计算传热系数计算传热系数墙体:K(wall)=1/1.695=0.59W/(K)屋顶:K(roof)=1/0.295=3.39W/(K)楼地面:K(floor)=1/0.276=3.62W/(K)门:K(door)=1/0.444=2.25W/(K)窗：K(window)=1/0.1566=6.39W/(K)6.6.计算热损系数计算热损系数HLC(wall)=48.75x0.59=28.77W/K)HLC(roof)=17.626x3.39=59.75(W/K)HLC(floor)=
6、17.626x3.62=59.75(W/K)HLC(door)=1.8009x2.25=4.052(W/K)HLC(window)=3.451x6.39=20.05W/K)THLC=28.77+59.75+59.75+4.052+20.05=172.372(W/K)7.7.维护结构热损失维护结构热损失Qt=15x173.372=2585.58W8.8.全年能源需求全年能源需求Energy=2585.58x365x24x60=1358980848(kWh)59.9.主卧计算主卧计算i=ti-Ri(ti-te)/Ro=22-0.11x15/1.695=21.23m140mm 砌体=22-(0.11+0.127)x15/1.695=19.91m 保温层=22-(0.11+0.127+1.2)x15/1.695=9.28m240mm 砌=22-(0.11+0.127+1.2+0.127)x15/1.695=8.16e=22-(0.11+0.127+1.2+0.127+0.04)x15/1.695=7.8110.10.参考资料参考资料Re,Ri 选择参考上表（来源于民用热工设计规范）6窗户选择最简单的单层窗，窗洞比取 25%（来源于民用热工设计规范）7