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1、高二数学期中模拟考试题姓名考号一、选择题（每小题5 分，共 60 分）1以下命题正确的是（）A0ba，bdacdc0 Bbaba11Cba，dbcadc D22bcacba2不等式210axbx的解集是12，13，则不等式20 xbxa的解集是（）.A2,3 B,23,C.1 1,3 2 D.11,323若实数,a b满足2ab，是33ab的最小值是（）A18 B 6 C 23D2434在等比数列an中，393aa，则6a等于（）A 3 B3 C3D35数列na中，16a，且13nnaa，则这个数列的第30 项为（）A81 B1125 C87 D99 6在 ABC中，:1:2:3A B C，则
2、:a b c等于（）A1:2:3 B3:2:1 C1:3:2 D 2:3:17已知锐角三角形的边长分别为2,3,x，则x的取值范围是()A15x B513x C 05x D 135x8 已知,x y满足条件.3,0,05xyxyx则24xy的最小值为（）A.6 B.12 C.-6 D.-12 9等差数列na中,若1201210864aaaaa,则15S的值为（）A180 B240 C 360 D720 10等差数列na中，564aa，则10122log(222)aaa（）A10 B20 C40 D22log 511 已知两个等差数列na和nb的前n项和分别为nA和nB，且74 53nnAnBn
3、，则使得nnab为整数的正整数n的个数是（）.A2 B.3 C5 .D4 12.在ABC中，角A、B、C所对的边分别为,a b c，且BC边上的高为36a，则cbbc的最大值是()A.8 B.6 C.32 D.4 二、填空题（每小题5 分，共 20 分）13不等式2422210axax对xR恒成立，则a的取值范围是 .14数列na的前n项和为nS，121,2,aa*211,nnnaanN则100S=.15设0,0 xy35xy，则131xy的最小值为 .16下表给出一个“三角形数阵”：1814，1838，316，332,已知每一列的数成等差数列；从第三行起，每一行的数成等比数列，每一行的公比都
4、相等.记第i行第j列的数为ija，则（1）8 3a_；（2）前 20 行中14这个数共出现了_次文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:C
5、O5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ
6、4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1
7、I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码
8、:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5
9、HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 Z
10、R1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5三、解答题（70 分）17.（10 分）在ABC中，内角,A B C的对边分别为,a b c，满足222ababc（1）求角C的度数；（2）若10ab求ABC周长的最小
11、值18（10 分）已知数列na的前n项和为nS，且12nnSn，又数列nb满足：nnabn.(1)求数列na的通项公式；(2)当为何值时，数列nb是等比数列？此时数列nb的前n项和为nT，若存在mZ，rR，使nmTr成立，求m的最大值和r的范围.19.（12 分）已知函数()f xxaxx22，1,x（）当a21时，求函数()f x的最小值；（2）若对任意1,x，()0f x恒成立，试求实数a的取值范围文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X
12、5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7
13、 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5
14、文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G
15、3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7
16、M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6
17、L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I
18、7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L520（12 分）某科研小组研究发现：一棵水果树的产量x（单位：百千克）与肥料费用x（单位：百元）满足如下关系：211 02234251xxxxx.此外，还需要投入其它成本（如施肥的人工费等）2x百元.已知这种水果的市场售价为16 元/千克（即16 百元/百千克），且市场需求始终供不应求.记该棵水果树获得的利润为L x（单位：百元）.（1）求L x的函数关系式；（2）当投入的肥料费用为多少时，该水果树获得的利润最大？最大利润是多少？21.（13）在 平 面
19、内，四 边 形ABCD的 内 角B与D互 补，2BC，连 结AC，45BAC，60DAC.(1)求 DC；(2)若ADC的面积为32，求四边形ABCD的周长.22（13 分）在数列na中，11111 12nnnnaaan，.（1）设nnabn，求数列nb的通项公式；（2）求数列na的前n项和nS.文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7
20、 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5
21、文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G
22、3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7
23、M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6
24、L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I
25、7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4
26、P7M7 ZR1I9Y10O6L5高二数学期中模拟考试题参考答案一、选择题1.C 2.A 3.B 4.C 5.A；6.C 7.B 8.C 9.C 10.B 11 C 12.D 二、填空题1322a 142600 1532 1614，4 三、解答题17.解：（1）由条件的222+abcab，所以2221cos222abcabCabab，又C为三角形内角，故0120C.（2）222222=+=()()()752abcababababab，得5 3c所以当5ab时，ABC周长取得最小值105 318解：(1)由12nnSn，当1n时，11aS；当2n时，11112222nnnnnnaSSnnn故数列
27、na的通项公式为1122nnnann .(2)由nnabn，则111122nnnbn,则数列nb为等比数列，则首项为11b满足2n的情况，故1，则121112.2 11212nnnnTbbb文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5
28、文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G
29、3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7
30、M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6
31、L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I
32、7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4
33、P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5因为1102nnnTT，所以12 12n是单调递增的，故1nT且2nT，存
34、在mZ，rR，使nmTr成立，则m的最大值为0，r的范围2,.19解（1）当a21时，221)(xxxf，因为)(xf在区间,1上为增函数，所以)(xf在区间,1的最小值为27)1(f（2）在区间,1上，02)(2xaxxxf恒成立022axx恒成立设,1,22xaxxy，1)1(222axaxxy在,1递增，当1x时，ay3min，于是当且仅当03minay时，函数)(xf恒成立，故有 a 的范围3aa20.解：（1）162L xw xxx281630248643251xxxxxx（2）当02x时max242L xL;当25x时867311L xxx4867231431xx.当且仅当4831
35、1xx时，即3x时等号成立.因为434232LL即答：当投入的肥料费用为300 元时，种植该果树获得的最大利润是4300 元.文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1
36、I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码
37、:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5
38、HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 Z
39、R1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档
40、编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X
41、5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L521.解：（1）在ADC中，由正弦定理sinsinDCACDACD，在ABC中同理可得sinsinBCACBACB，因为B与D互补，所以s
42、insinBD，则sinsinDCBCDACBAC，即2sin60sin45DC，解得3DC.（2）在ADC中，由面积公式13sin22AC ADDAC，得2ACAD，由余弦定理2222cosDCADACAD ACDAC，得225ADAC，解得21ACAD，或12ACAD若1,2ACAD，则30,150DB，与ACBC矛盾，则2,1ACAD，所以90D，那么90B，所以2AB.所以四边形ABCD的周长为132 2文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7
43、I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X
44、4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y1
45、0O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5
46、G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S
47、1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9
48、Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:C
49、O5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L522 解：（1）由已知得111ba，且1112nnnaann.即112nnnbb，从而2112bb，32212bb，11122nnnbbn.于是12111111222222nnnbbn，又11b，故所求的通项公式1122nnb.（2）由（1）知1112222nnnnann，111112222nnnnkkkkkkkSkk.而121nkkn n，又112nkkk是一个典型的错位相减法模型，易得1112422nknkkn，12142nnnSn n.文
50、档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3X5 HZ4S1X4P7M7 ZR1I9Y10O6L5文档编码:CO5G7I7G3