2022年中考数学50个知识点专练26答案圆的基本性质 .pdf

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1、2013 中考数学50 个知识点专练26 圆的基本性质一、选择题1(2011上海)矩形 ABCD 中，AB8，BC3 5，点 P在边 AB上，且 BP 3AP，如果圆 P是以点 P为圆心，PD为半径的圆，那么下列判断正确的是()A.点 B、C均在圆 P外B.点 B在圆 P外、点 C在圆 P内C.点 B在圆 P内、点 C在圆 P外D点 B、C均在圆 P内答案C 解析如图，AB8，BP 3AP，得 BP 6，AP 2.在 RtAPD中，PD 3 52227BP，所以点 B在圆 P内；在 RtBPC中，PC 3 52 62 9PD，所以点 C在圆 P外2(2011凉山)如图，AOB 100，点 C在

2、 O上，且点 C不与 A、B重合，则 ACB的度数为()A50 B80或 50C130 D50 或 130答案D 解析当点 C在优弧上，ACB 12 AOB 50；当点 C在劣弧上，ACB 18050130.综上，ACB 50或 130.3(2011重庆)如图，O是 ABC的外接圆，OCB 40，则 A的度数等于()A60 B50C40 D30答案B 解析在 OBC 中，OB OC，OCB 40，BOC 180240100.A 12BOC 1210050.4(2011绍兴)一条排水管的截面如图所示已知排水管的截面圆半径OB 10，截面圆圆心 O到水面的距离OC是 6，则水面宽AB是()A16

3、B10 C8 D6 文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编

4、码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1

5、 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2

6、ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文

7、档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7

8、M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W

9、2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9文档编码:CH8C3Q1A7M1 HS1B3J7R3W2 ZL10E7L5B2Y9答案A 解析在 Rt OBC 中，OB 10，OC 6，BC 102 62 8.OC AB，AC BC.AB 2BC 28 16.5(2011嘉兴)如图，半径为 10 的 O中，弦 AB的长为 16，则这条弦的弦心距为()A6 B 8 C10

10、D 12 答案A 解析作弦心距OC，得 AC BC 1216 8.连接 AO，在 RtAOC中，OC 102 826.二、填空题6(2011扬州)如图，O 的弦CD 与直径AB 相交，若BAD 50，则ACD _度答案40 解析AB是 O的直径，文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8

11、I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C

12、4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9

13、M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10

14、W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M

15、4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7

16、P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3 ADB 90.B

17、 90 BAD 905040.ACD B40.7(2011安徽)如图，O的两条弦AB、CD互相垂直，垂足为E，且 AB CD，已知 CE1，ED 3，则 O的半径是 _答案5 解析画 OM AB，ON CD，垂足分别为M、N，连接 OD.AB CD，OM ON.易证四边形OMEN 是正方形CN DN 12CD 12(1 3)2，EN CN CE211.ON 1.在 RtDON中，OD 12225.8(2011杭州)如图，点A、B、C、D都在 O上，CD的度数等于84，CA是 OCD文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z

18、4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9

19、 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文

20、档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I

21、7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4

22、L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M

23、3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W

24、8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3的平分线，则ABD CAO _.答案48解析OA OC，CAO ACO.又 ABD ACD，ABD CAO ACD ACO DCO.在 CDO 中，OC OD，COD=mCD84，DCO 18084248，即 ABD CAO 48.9(2011威海)如图，O的直径 AB与弦 CD相交于点E，若 AE 5，BE 1，CD 4 2，则 AED _.答案30解析连接 DO，画 OF

25、CD，垂足是F.文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:

26、CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4

27、HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 Z

28、D6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编

29、码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z

30、4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9

31、 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3CFDF12CD 124 22 2.AB AE BE516，DO 12AB 3.在 RtDFO中，OF 322 221，在 RtOFE中，OE 312，OF 1.AED 30.10(2011舟山)如图，AB 是半圆直径，半径OC AB于点 O，AD

32、平分 CAB交弧 BC于点 D，连接 CD、OD，给出以下四个结论：AC OD；CE OE；ODE ADO；2CD2CE AB.其中正确结论的序号是_答案解析OC AB，A C B C 90.AD平分 CAD，CAD BAD，CD BD45.CAB=m12BC45，DOB=mBD45，文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D

33、8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:C

34、D8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 H

35、W2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD

36、6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码

37、:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4

38、 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9

39、ZD6D8V7P9M3 CAD DOB，AC OD；在 ACO 中，ACAO，AE平分 CAO，CE EO；由 AC OD，得 ODE CAE，而 CAD BAO，ACE AOD，AEC AOD.ACE与 ADO不相似，即 ODE与 ADO不相似；连接 BD，有 BD CD，可求得 B67.5，又 CED AEO 67.5，B CED.又 CDE DOB 45，CDE DOB，CDDOCEDB，CD DB CE DO，CD2CE 12AB，即 2CD2CE AB.故结论、正确三、解答题11(2011上海)如图，点 C、D分别在扇形AOB的半径 OA、OB的延长线上，且 OA 3，AC 2，CD

40、平行于 AB，并与 A B 相交于点M、N.(1)求线段 OD的长；(2)若 tan C12，求弦 MN 的长解(1)CD AB，OAB C，OBA D.OA OB，OAB OBA.C D.OC OD.OA 3，AC 2，OC 5.OD 5.文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7

41、Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L

42、9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3

43、文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8

44、I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C

45、4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9

46、M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3(2)过点 O作 OE

47、 CD，E为垂足，连接OM.在 RtOCE中，OC 5，tan C12，设 OE x，则 CE 2x.由勾股定理得x2(2x)252，解得 x15，x25(舍去)OE 5.在 RtOME 中，OM OA 3，ME OM2 OE232522.MN 2ME 4.12(2011江西)如图，已知 O的半径为2，弦 BC的长为 2 3，点 A为弦 BC所对优弧上任意一点(B、C两点除外)(1)求 BAC的度数；(2)求 ABC面积的最大值(参考数据：sin60 32，cos3032，tan3033.)解(1)解法一：连接 OB、OC，过 O作 OE BC于点 E(如图)文档编码:CD8F10W8I7Z4

48、 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9

49、ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档

50、编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7Z4 HW2Z1M4C4L9 ZD6D8V7P9M3文档编码:CD8F10W8I7