《2022年人教版八年级数学上册第二章全等三角形 .pdf》由会员分享,可在线阅读,更多相关《2022年人教版八年级数学上册第二章全等三角形 .pdf(6页珍藏版)》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。
1、精编学习资料欢迎下载人教版八年级数学(上册)第二章:全等三角形一、基本概念1、全等的图形必须满足:(1)形状相同的图形;(2)大小相等的图形;我们把能够完全重合的两个三角形叫做全等三角形。2、全等三角形的性质(1)全等三角形对应边相等;(2)全等三角形对应角相等;3、全等三角形的判定方法(1)三边对应相等的两个三角形全等。(2)两角和它们的夹边对应相等的两个三角形全等。(3)两角和其中一角的对边对应相等的两个三角形全等。(4)两边和它们的夹角对应相等的两个三角形全等。(5)斜边和一条直角边对应相等的两个直角三角形全等。4、角平分线的性质及判定性质:角平分线上的点到这个角的两边的距离相等判定:到
2、一个角的两边距离相等的点在这个角平分线上二、灵活运用定理1、判定两个三角形全等的定理中,必须具备三个条件,且至少要有一组边对应相等,因此在寻找全等的条件时,总是先寻找边相等的可能性。(1)已知条件中有两角对应相等,可找:夹边相等(ASA)任一组等角的对边相等(AAS)(2)已知条件中有两边对应相等,可找夹角相等(SAS)第三组边也相等(SSS)(3)已知条件中有一边一角对应相等,可找任一组角相等(AAS 或 ASA)夹等角的另一组边相等(SAS)三、常见考法(1)利用全等三角形的性质:证明线段(或角)相等;证明两条线段的和差等于另一条线段;证明面积相等;(2)利用判定公理来证明两个三角形全等精
3、编学习资料欢迎下载A D B C(第 2题)A F E C D B(第 3题)A B C(第 4题)ABECD(第 5 题)A B C D E(第 4题)A O D B C(第 1题)考点 1 全等三角形一、选择题1如图,已知 ABC DCB,且 AB=DC,则 DBC 等于()A A B DCB C ABC D ACB 2已知 ABC DEF,AB=2,AC=4,DEF 的周长为偶数,则EF 的长为()A3 B4 C 5 D 6 二、填空题3已知 ABC DEF,A=50,B=65,DE=18,则 F=_,AB=_ 4如图,ABC 绕点 A 旋转 180 得到 AED,则 DE 与 BC 的
4、位置关系是_,数量关系是_三、解答题5把ABC 绕点 A 逆时针旋转,边AB 旋转到 AD,得到 ADE,用符号“”表示图中与 ABC 全等的三角形,并写出它们的对应边和对应角考点 2 三角形全等的条件(1)一、选择题1 如果 ABC 的三边长分别为3,5,7,DEF 的三边长分别为3,3x2,2x1,若这两个三角形全等,则 x 等于()A73B3 C4 D 5 二、填空题2如图,已知AC=DB,要使 ABC DCB,还需知道的一个条件是_3已知 AC=FD,BC=ED,点 B,D,C,E 在一条直线上,要利用“SSS”,还需添加条件_,文档编码:CV4K6H10T1E1 HW1V8K6H2V
5、5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W
6、4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10
7、G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码
8、:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6
9、H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E
10、1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V
11、8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9精编学习资料欢迎下载A B C E D(第 6题)A B F E D C 得 ACB _4如图 ABC中,AB=AC,现想利用证三角形全等证明B=C,若证三角形全等所用的公理是SSS公理,则图中所添加的辅助线应是_二、解答题
12、5 如图,A,E,C,F 在同一条直线上,AB=FD,BC=DE,AE=FC 求证:ABC FDE考点 3 三角形全等的条件(2)一、填空题3下列命题:腰和顶角对应相等的两个等腰三角形全等;两条直角边对应相等的两个直角三角形全等;有两边和一角对应相等的两个三角形全等;等腰三角形顶角平分线把这个等腰三角形分成两个全等的三角形其中正确的命题有_二、解答题4 已知:如图,C 是 AB 的中点,ADCE,AD=CE 求证:ADC CEB6已知:如图,AC BD,BC=CE,AC=DC 求证:B+D=90;考点 4 三角形全等的条件(3)一、选择题1下列说法正确的是()A有三个角对应相等的两个三角形全等
13、B有一个角和两条边对应相等的两个三角形全等C有两个角和它们夹边对应相等的两个三角形全等D面积相等的两个三角形全等二、填空题2如图,B DEF,BCEF,要证 ABC DEF,(1)若以“SAS”为依据,还缺条件;(2)若以“ASA”为依据,还缺条件DCEFBA(第 5 题)(第 4 题)A B C D E(第 2题)文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1
14、E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1
15、V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2
16、V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2
17、W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B1
18、0G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编
19、码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K
20、6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9精编学习资料欢迎下载(第 4题)3421EDCBAA B E D C F(第 3题)(第 6题)A B C D O A E C B D 三、解答题4已知:如图,AB CD,OA=OC 求证:OB=OD 5已知:如图,ACCE,AC=CE,ABC=CDE=90 ,求证:BD=AB+ED 考点 5 三角形全等的条件(4)一、选择题1已知 ABC 的六个元素,则下面甲、乙、丙三个三角形中和 ABC 全等的图形是()A甲和乙B乙和丙C只有乙D只有丙二、填
21、空题2如图,已知A=D,ABC=DCB,AB=6,则 DC=3如图,已知A=C,BEDF,若要用“AAS”证 ABE CDF,则还需添加的一个条件是(只要填一个即可)三、解答题6如图,已知1 2,3 4,ECAD,求证:ABBE 考点 6 课三角形全等的条件(5)一、选择题(第 5题)DCBA(第 2 题)文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW
22、1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H
23、2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD
24、2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B
25、10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档
26、编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4
27、K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T
28、1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9精编学习资料欢迎下载(第 3题)(第 2题)(第 4题)A C B E D 1使两个直角三角形全等的条件是()A一个锐角对应相等B两个锐角对应相等C一条边对应相等D。一直角边和斜边对应相等二、填空题3如图,有两个长度相同的滑梯(即BCEF),左边滑梯的高度AC 与右边滑梯水平方向的长度DF 相等,则 ABC DFE_度三、解答题6如图,AD 为 ABC 的高,E 为 AC 上一点,BE 交 AD 于点 F,且有 BF=AC,FD=CD 求证:BEAC考点
29、7 三角形全等的条件(6)一、选择题2如图,E 点在AB上,AC AD,BC BD,则全等三角形的对数有()A1 B2 C3 D4 3有下列命题:两边及第三边上的高对应相等的两个三角形全等;两边及其中一边上的中线对应相等的两个三角形全等;两边及第三边上的高对应相等的两个锐角三角形全等;有锐角为30 的两直角三角形,有一边对应相等,则这两个三角形全等其中正确的是()ABCD二、解答题4已知 AC=BD,AF=BE,AEAD,FDAD求证:CE=DF 考点 8 角平分线的性质(1)一、选择题1用尺规作已知角的平分线的理论依据是()ASAS BAAS CSSS D ASA FEDCBAC A E B
30、 F D A B C D E F(第 6 题)文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6
31、H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 Z
32、D2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8
33、B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文
34、档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV
35、4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10
36、T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9精编学习资料欢迎下载二、解答题4已知:如图,AM 是 BAC 的平分线,O 是 AM 上一点,过点O 分别作 AB,AC
37、的垂线,垂足为F,D,且分别交AC、AB 于点 G,E求证:OE=OG 6如图,ABC 中,C=90,AD 是 ABC 的角平分线,DEAB 于 E,AD=BD(1)求证:AC=BE;(2)求 B 的度数。考点 9 角平分线的性质(2)一、选择题1三角形中到三边距离相等的点是()A三条边的垂直平分线的交点B三条高的交点C三条中线的交点D三条角平分线的交点二、填空题3如图,在 ABC 中,AD 为 BAC 的平分线,DEAB 于 E,DFAC 于 F,ABC 面积是 28 cm2,AB=20cm,AC=8cm,则 DE 的长为 _ cm三、解答题5如图,AD BC,DAB 的平分线与CBA 的平
38、分线交于点P,过点 P 的直线垂直于AD,垂足为点D,交 BC 于点 C试问:(1)点 P 是线段 CD 的中点吗?为什么?(2)线段 AD 与线段 BC 的和等于图中哪一条线段的长度?为什么?M A C B E O F D G(第 4 题)E A C D B(第 6 题)A B C D P(第 5 题)文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1
39、V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2
40、V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2
41、W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B1
42、0G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编
43、码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K
44、6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9文档编码:CV4K6H10T1E1 HW1V8K6H2V5 ZD2W4F8B10G9