《工程力学习题答案第4章 轴向拉伸和压缩.docx》由会员分享，可在线阅读，更多相关《工程力学习题答案第4章 轴向拉伸和压缩.docx（2页珍藏版）》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。
1、第4章轴向拉伸和压缩习题答案4-1(a) Fni =50kN FN2 =10kN FN3 =-20kN(b) FN1 = F FN2 =0 FN3 = FFN1 =0 FN2 = 4F Fn3 = 3F(c) FN1 FN2 =10kN FN3 = -2F4-2 FN1 =-20kN。= -50 MPaFN2 =-10kN b = 25MPaFN3 =10 kN b = 25MPa巧=127 MPa, cr2 =63.7MPa4-44-54-64-74-8o = -0.34 MPacr()二 100 MPa r()= 0 ;。3()= 75 MPa, r3() = 43.3MPacr45 =
2、50MPa, Q5 = 50MPa ； cr60 = 25 MPa,r60 = 43.3MPa。90 = ，790 = A FlAD =D 3EAA/ = 0.075 mm(1) a = 135MPaA = 83.7mm(3)/= 96.4N4-9(1) = 5x107, o- = 100MPa, P=7.85kN3.06 mm4-10水平位移是：0.6mm 垂直位移是：3mm A点的位移是:4-11 6Cx = 0.476 mm, 8Cy = 0.476 mm4-12 b = 37.1MPa Y b安全4-13 d 22.6 mm4-14 p - 2.5 MPa 4-15 F = 40.4
3、kN4-16 (lKax833 mm2； (3)Fmax 15.7kN 4-17 b = 32.7MPa Y cr安全4-18 F 17.2mm dRr = dRn 17.2mm AooCbU4-20 杆 AB：两根 lOOmnpc lOOmrnxlOmm等边角钢 杆AD：两根80mmx80mmx6mm等边角钢4-21 6 = 54.8。4-224-23Fn1=f，Fn2 =:/,然3 =一:/；。3o4-24 FN1 = 3.6kN, FN2 = 7.2kN, FN3 = 4.8kN 4-25 F=698kN4-26 P-r,销钉强度不够，应改为dN32.6mm4-33F177N,r = 17.6MPa,4-34 F236kN4-35 t = 0.952 MPa, cr, = 7.41 MPa J4-36- = 2.4h4-37 t = 66.3MPa, a, = 102 MPa 4-38 r = 28.6 MPa, a, = 95.3 MPaU o4-39 r = 43.3 MPa, a. = 59.5 MPaLzo4-40 t = 52.6 MPa, a. = 90.9 MPa, o- = 166.7 MPa us