2021年2019年普通高等学校招生全国统一考试理科数学(全国III卷)解析版.pdf

上传人:H****o 文档编号:56679911 上传时间:2022-11-02 格式:PDF 页数:17 大小:520.55KB
返回 下载 相关 举报
2021年2019年普通高等学校招生全国统一考试理科数学(全国III卷)解析版.pdf_第1页
第1页 / 共17页
2021年2019年普通高等学校招生全国统一考试理科数学(全国III卷)解析版.pdf_第2页
第2页 / 共17页
点击查看更多>>
资源描述

《2021年2019年普通高等学校招生全国统一考试理科数学(全国III卷)解析版.pdf》由会员分享,可在线阅读,更多相关《2021年2019年普通高等学校招生全国统一考试理科数学(全国III卷)解析版.pdf(17页珍藏版)》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。

1、2019 年普通高等学校招生全国统一考试(全国III 卷)理科数学一、选择题1、已知集合 1|,2,1,0,12xxBA,则BA()A.1,0,1B.B.0,1C.C.1,1D.D.2,1,0答案:A 解答:11|1|2xxxxB,所以 1,0,1BA.2.若iiz2)1(,则z()A.i1B.i1C.i1D.i1答案:D 解答:iiz2)1(,iiiiiiiiiz1)1()1)(1()1(212.3.西游记三国演义 水浒传和红楼梦是中国古典文学瑰宝,并称为中国古典小说四大名著,某中学为了解本校学生阅读四大名著的情况,随机调查了100 位学生,其中阅读过西游记或红楼梦的学生共有90 位,阅读过

2、红楼梦的学生共有80 位,阅读过西游记且阅读过红楼梦的学生共有60 位,则该校阅读过西游记的学生人数与该校学生总数比值的估计值为()A.5.0B.6.0C.7.0D.8.0答案:C 解答:|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 1 页,共 17 页7.01006080904.42)1)(21(xx的展开式中3x的系数为()A.12B.16C.20D.24答案:A 解答:由题意可知含3x的项为33142334121211xxCxxC,所以系数为12.5.已知各项均为正数的等比数列na的前4项和为15,且53134aaa,则3a()A.16B

3、.8C.4D.2答案:C 解答:设该等比数列的首项1a,公比q,由已知得,4211134a qa qa,因为10a且0q,则可解得2q,又因为231(1)15aqqq,即可解得11a,则2314aa q.6.已知曲线xxaeyxln在点)1(ae,处的切线方程为bxy2,则()A.ea,1bB.ea,1bC.1ea,1bD.1ea,1b答案:D 解析:令xxaexfxln)(,则1ln)(xaexfx,21)1(aef,得11eea.baef2)1(,可得1b.故选 D.|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 2 页,共 17 页文档编码

4、:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7

5、HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 Z

6、V9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档

7、编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J

8、7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9

9、 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1

10、文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L1文档编码:CR3W2G7Z5J7 HB9N8L8W7N9 ZV9P3F10Z2L17.函数3222xxxy在 6,6的图像大致为()A.B.C.D.答案:B 解析:32()22xxxyf x,332()2()()2222xxxxxxfxf x,()f x为奇函数,排除选项C.又334442424(4)8222f,根据图像进行判断,可知选项B 符合题意.

11、8.如图,点N为正方形ABCD的中心,ECD为正三角形,平面ECD平面ABCD,M是线段ED的中点,则()A.ENBM,且直线ENBM,是相交直线B.ENBM,且直线ENBM,是相交直线C.ENBM,且直线ENBM,是异面直线|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 3 页,共 17 页文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编

12、码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y

13、1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R

14、9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K

15、9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M

16、10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8

17、P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V

18、8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5D.ENBM,且直线ENBM,是异面直线答案:B 解析:连结BD,因为点N为正方形ABCD的中心,所以点N为BD的中点,可知直线ENBM,都是平面BED内的直线,且不平行,即直线ENBM,是相交直线,设正方形ABCD的边长为a2,则由题意可得:aDBaDNaDMaDE22,2,2,根据余弦定理可得:BDEaaBDEDMDBDMDBBMcos249cos222222,BDEaaBDEDNDEDNDEENcos246cos22

19、2222,所以ENBM,故选 B.9.执行右边的程序框图,如果输出为01.0,则输出s的值等于()A.4212B.5212C.6212D.7212答案:C 解析:|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 4 页,共 17 页文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P1

20、0Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S

21、5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:

22、CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y

23、3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9

24、HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P

25、9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10

26、 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5第一次循环:21,1 xs;第二次循环:221,211xs;第三次循环:3221,21211xs;第四次循环:43221,2121211xs;第七次循环:76221,21.21211xs,此时x成立,循环结束,可得输出的66221221.21211s.故选 C.10.双曲线C:22142xy的右焦点为F,点P为C的一条渐近线的点,O为坐标原点.若|POPF则PFO的面积为()A:3 24B:3 22C:2 2D:3 2答案:A 解析:由双曲线的方程22042xy可得一条渐近线方程为22

27、yx;在PFO中|POPF过点P做PH垂直OF因为2t a nP O F=2得到32PH;所以13326224SP FO;故选 A;11.若()f x是定义域为R的偶函数,且在(0,)单调递减,则()A.233231(log)(2)(2)4fffB.233231(log)(2)(2)4fffC.233231(2)(2)(log)4fff|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 5 页,共 17 页文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 Z

28、F8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z

29、9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文

30、档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA

31、8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D

32、7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX

33、5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S

34、5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5D.233231(2)(2)(log)4fff答案:C 解析:依据题意函数为偶函数且函数在(0,)单调递减,则函数在(,0)上单调递增;因为3331(log)(log 4)(log 4)4fff;又 因为233230221l o g4;所以233231(2)(2)(log)4fff;故选 C.12.设函数()si

35、n05f xx,已知()f x在0 2,有且仅有5个零点,下述四个结论:1()f x在0,2有且仅有3个极大值点2()f x在0,2有且仅有2个极小值点3()f x在0,10单调递增4的取值范围是12 29,510其中所有正确结论的编号是A.14 B.23 C.123 D.134答案:D 解析:根据题意,画出草图,由图可知122,x x,|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 6 页,共 17 页文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10

36、ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10

37、Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5

38、文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:C

39、A8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3

40、D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 H

41、X5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9

42、S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5由题意可得,125565xx,解得12245295xx,所以2429255,解得1229510,故4 对;令52x得3010 x,图像中y轴右侧第一个最值点为最大值点,故1 对;122,x x,()f x在0,2有2个或3个极小值点,故2 错;1229510,1149251051002,故3 对.二.填空题13

43、.已知a,b为单位向量,且0a b,若25cab,则cos,a c .答案:23解析:222225454 59cababa b,3c,225252a caabaa b,22cos,1 33a ca cac.14.记nS为等差数列na的前n项和,若10a,213aa,则105SS .答案:4解析:设该等差数列的公差为d,213aa,113ada,故1120,0daad,1101101551102 292 102452452aaadSdaaSadd.15.设1F、2F为椭圆1203622yxC:的两个焦点,M为C上一点且在第一象限,若21FMF为等腰三角形,则M的坐标为 _.答案:)15,3(|精

44、.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 7 页,共 17 页文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P

45、10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8

46、S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码

47、:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1

48、Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9

49、 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9

50、P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5文档编码:CA8Y1Y3D7R9 HX5K9P9S5M10 ZF8P10Z9V8S5解析:已知椭圆1203622yxC:可知,6a,4c,由

展开阅读全文
相关资源
相关搜索

当前位置:首页 > 教育专区 > 高考资料

本站为文档C TO C交易模式,本站只提供存储空间、用户上传的文档直接被用户下载,本站只是中间服务平台,本站所有文档下载所得的收益归上传人(含作者)所有。本站仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。若文档所含内容侵犯了您的版权或隐私,请立即通知淘文阁网,我们立即给予删除!客服QQ:136780468 微信:18945177775 电话:18904686070

工信部备案号:黑ICP备15003705号© 2020-2023 www.taowenge.com 淘文阁