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1、学习好资料欢迎下载选修四期中考试题（合肥一中考题)第 I 卷（共 46 分）一、单选题(本题共 46 分。1-8 每题 2 分，9-18 每题 3 分)1、下列条件一定能使反应速率加快的是 ()增加反应物的物质的量升高温度增大反应体系的压强不断分离出生成物加入MnO2A全部BC D2、实验测得：101 kPa 时，1 mol H2完全燃烧生成液态水，放出285.8 kJ 的热量；1 mol CH4完全燃烧生成液态水和CO2，放出 890.3 kJ 的热量。下列热化学方程式的书写正确的是()CH4(g)2O2(g)=CO2(g)2H2O(l)H890.3 kJmol1CH4(g)2O2(g)=C
2、O2(g)2H2O(l)H890.3 kJmol1CH4(g)2O2(g)=CO2(g)2H2O(g)H 890.3 kJmol12H2(g)O2(g)=2H2O(l)H 571.6 kJmol1A仅有 B仅有C仅有D全部符合要求3、H2S水溶液中存在电离平衡H2SH+HS-和 HS-H+S2-。若向 H2S溶液中（）A.加水，平衡向右移动，溶液中氢离子浓度增大B.通入过量 SO2气体，平衡向左移动，溶液pH 值增大C.滴加新制氯水，平衡向左移动，溶液pH 值减小D.加入少量硫酸铜固体（忽略体积变化），溶液中所有离子浓度都减小4、下列依据热化学方程式得出的结论正确的是 ()A已知 2H2(g)
3、O2(g)=2H2O(g)H=483.6 kJmol1，则氢气的燃烧热（H）为-241.8 kJ mol1B已知 NaOH(aq)HCl(aq)=NaCl(aq)H2O(l)H=57.3 kJmol1，则含 40.0g NaOH 的稀溶液与稀醋酸完全中和，放出小于57.3kJ的热量C己知 2C(s)2O2(g)=2CO2(g)H=a；2C(s)O2(g)=2CO(g)；H=b，则 ab D已知 C(石墨，s)=C(金刚石，s)H0，则金刚石比石墨稳定5、在一定条件下，向一带活塞的密闭容器中充入2mol NO2，发生下列反应2NO2（g）N2O4（g）H 0，达到平衡状态后，在t1时刻改变条件，
4、化学反应速率随时间变化关系如图。下列对t1时刻改变条件的推测中正确的是()A保持压强不变，升高反应温度B保持温度和容器体积不变，充入1mol N2（g）C保持温度和容器体积不变，充入1mol N2O4（g）D保持温度和压强不变，充入1mol N2O4（g 6、高温下，某反应达平衡，化学平衡常数表达式为：，恒容时，温度升高H2浓度减小。下列说法正确的是 ()A该反应化学方程式为：CO(g)H2O(g)CO2(g)H2(g)B恒温恒容下，反应达平衡时，再通入一定量的CO2，CO的体积分数一定增大C升高温度，正反应速率增大，逆反应速率减小D该反应的焓变为正值7、已知 2SO2(g)+O2(g)2SO
5、3(g)；H 197 kJ m ol1。向同温、同体积的三个密闭容器中分别充入气体：(甲)2 mo l SO2和 1 m ol O2；精品资料-欢迎下载-欢迎下载 名师归纳-第 1 页，共 7 页 -学习好资料欢迎下载(乙)1 mo l SO2和 0.5 m ol O2；(丙)2 mo l SO3。恒温、恒容下反应达平衡时，下列关系一定正确的是（）A容器内压强P：P甲P丙 2P乙BSO3的质量 m：m甲m丙 2m乙Cc(SO2)与 c(O2)之比 k：k甲k丙 k乙D反应放出或吸收热量的数值Q：Q甲G丙 2Q乙8、向绝热恒容密闭容器中通入SO2和 NO2，一定条件下使反应：SO2(g)+NO2
6、(g)SO3(g)+NO(g)达到平衡，正反应速率随时间变化如图所示。则正确的结论是()A逆反应速率：a 点小于点 c B反应物浓度：a 点小于点 b C反应在c 点时 SO2的转化率最大D反应物的总能量低于生成物的总能量9、在 25时，密闭容器中X、Y、Z 三种气体的浓度变化情况如图：下列说法错误的是（）A反应可表示为3X+Y2Z B从反应开始到0.4s 时，以 Y表示的化学反应速率为：0.25mol L1 s1C增大压强使平衡向生成Z的方向移动，平衡常数增大D升高温度，平衡常数可能增大也可能减小10、使 2 mol N2和 6 mol H2混合发生下列反应：N2(g)+3H2(g)2NH3
7、(g)（正反应为放热反应）。下列说法错误的是 ()A升高平衡体系的温度（保持体积不变），混合气体的平均相对分子质量变大B升高平衡体系的温度（保持体积不变），混合气体的密度不变C当反应达到平衡时，N2和 H2的浓度比是13 D当达到平衡时，充入氩气，并保持压强不变，平衡将逆向移动11、在一固定体积的密闭容器中，充入2molA 和 1molB，发生如下反应：2A（g）+B（g）xC（g），平衡后，C 的体积分数为W%，若维持容器容积和温度不变，0.6molA、0.3molB 和 1.4molC为起始物质，达到平衡后，C的体积分数也为W%。平衡后若缩小容器体积，C的浓度 c（C）、C的体积分数C%、
8、混合气体平均相对分子质量（M）和正反应速率V（正），随压强（P）的变化，一定符合的是()A B C D 12、将 E和 F加入密闭容器中，在一定条件下发生反应：E(g)+F(s)2G(g)。忽略固体体积，平衡时G的体积分数(%)随温度和压强的变化如下表所示：精品资料-欢迎下载-欢迎下载 名师归纳-第 2 页，共 7 页 -文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 H
9、A2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2
10、A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 H
11、A2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2
12、A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 H
13、A2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2
14、A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3学习好资料欢迎下载压强/MPa 体积
15、分数/%温度/1.0 2.0 3.0 810 54.0 a b 915 c 75.0 d 1000 e f 83.0 bf 915、2.0MPa 时 E的转化率为60%该反应的S 0 K(1000)K(810)上述 中正确的有（）A 4 个B3 个C2个D1 个13、一定条件下，通过下列反应可以制备特种陶瓷的原料MgO，MgSO4(s)+CO(g)MgO(s)+CO2(g)+SO2(g)H0 该反应在恒容的密闭容器中达到平衡后，若仅改变图中横坐标x 的值，重新达到平衡后，纵坐标y 随x 变化趋势合理的是 ()选项x y A 温度容器内混合气体的密度B CO的物质的量CO2与 CO的物质的量之比
16、C SO2的浓度平衡常数 K D MgSO4的质量（忽略体积）CO的转化率14、对于可逆反应N2(g)3H2(g)2NH3(g)Hp1)图示15、室温下向10 mL pH=3 的醋酸溶液中加入水稀释后，下列说法正确的是()A溶液中导电粒子的数目增加，导电性增强B醋酸的电离程度增大，c(H+)亦增大C再加入 10 m L pH=11 NaOH溶液，混合液pH=7 D溶液中不变16、25时，用浓度为 0.1000 mol/L 的 NaOH溶液滴定 20.00 mL 浓度均为 0.1000 mol/L 的三种酸 HX、HY、HZ，滴定曲线如图所示。下列说法正确的是（）A在相同温度下，同浓度的三种酸溶
17、液的导电能力顺序：HZHYHX B根据滴定曲线，可得Ka(HY)105 C将上述 HX、HY溶液等体积混合后，用NaOH 溶液滴定至HX 恰好完全反应时：c(X)c(Y)c(OH)c(H+)DHY与 HZ 混合，达到平衡时：c(H+)=+c(Z)+c(OH)Ka(HY)c(HY)c(Y)精品资料-欢迎下载-欢迎下载 名师归纳-第 3 页，共 7 页 -文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编
18、码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S
19、7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编
20、码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S
21、7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编
22、码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S
23、7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3学习好
24、资料欢迎下载17、某温度下，向一定体积0.1mol/L醋酸溶液中逐滴加入等浓度的NaOH 溶液，溶液中pOH(pOH=-lgOH-)与 pH的变化关系如图所示，则()AM点所示溶液导电能力强于Q点BN点所示溶液中c(CH3COO-)c(Na+)CM点和 N点所示溶液中水的电离程度相同DQ点消耗 NaOH溶液的体积等于醋酸溶液的体积18、今有室温下四种溶液，有关叙述不正确的是()序号pH 11 11 3 3 溶液氨水氢氧化钠溶液醋酸盐酸A 中分别加入适量的醋酸钠晶体后，两溶液的pH均增大B两溶液等体积混合，所得溶液中c(H)c(OH)C 分别加水稀释10 倍，四种溶液的pHD V1L与 V2L溶
25、液混合后，若混合后溶液pH7，则 V1V2第 II 卷（共 54 分）二、填空题(3 小题，共44 分)19、（本题 14 分）工业上采用乙苯与CO2脱氢生产重要化工原料苯乙烯(g)+CO2(g)(g)+CO(g)+H2O(g)H=166kJ mol-1(1)、乙苯与CO2反应的平衡常数表达式为:K=。若该反应在绝热、恒容的密闭体系中进行,下列示意图正确且能说明反应在进行到t1时刻达到平衡状态的是(填代号)。(2)、在 3 L密闭容器内,乙苯与 CO2的反应在三种不同的条件下进行实验,乙苯、CO2的起始浓度分别为1.0 molL-1和 3.0 mol L-1,其中实验在T1,0.3 MPa,而
26、实验、分别改变了实验其他条件;乙苯的浓度随时间的变化如图1 所示。图1 图 2、实验乙苯在050 min 时的反应速率为。、实验可能改变的条件是。精品资料-欢迎下载-欢迎下载 名师归纳-第 4 页，共 7 页 -文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2
27、P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9
28、N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2
29、P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9
30、N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2
31、P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9
32、N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3学习好资料欢迎下载、图 2 是实验中苯乙烯体积分数V%随时间 t 的变化曲线,请在图 2 中补画实验中苯乙烯体积分数 V%随时间 t 的变化曲线。(
33、3)、若实验中将乙苯的起始浓度改为1.2 molL-1,其他条件不变,乙苯的转化率将(填“增大”“减小”或“不变”),计算此时平衡常数为。20、（本题 16 分）某兴趣小组探究以芒硝Na2SO4 10H2O 和 CaO为原料制备Na2CO3。（1）将 CaO 水化后，与芒硝形成 Na2SO4Ca(OH)2H2O 三元体系，反应后过滤，向滤液中通入CO2，期望得到 Na2CO3。三元体系中反应的离子方程式为：SO42+Ca(OH)2(s)+2H2OCaSO4 2H2O(s)+2 OH该反应的平衡常数表达式K=_。往 Na2SO4Ca(OH)2H2O 三元体系中添加适量的某种酸性物质，控制 pH=
34、12.3 即 c(OH)=0.02mol/L，可使反应在常温下容易进行。反应后过滤，再向滤液中通入CO2，进一步处理得到Na2CO3。（2）在 Na2SO4Ca(OH)2H2O 三元体系中不直接通入CO2，其理由是_。（3）添加的酸性物质须满足的条件（写出两点）是_、_。（4）用平衡移动原理解释添加酸性物质的理由：_；以 HA 表示所添加的物质，则总反应的离子方程式可写为 _。（5）Na2CO3溶液中存在水解平衡：CO32H2OHCO3OH。下列说法错误的是_。a加水稀释，溶液中所有离子的浓度都减小b通入 CO2，溶液 pH 减小c加入 NaOH 固体，)()(233COcHCOc减小d稀释溶
35、液，平衡常数增大21、（本题 14 分）铁是最常见的金属之一，铁可以形成多种氧化物、氢氧化物和盐类。铁与二氧化碳、水在某一密闭体系中反应情况如下表所示：化学反应平衡常数温度973K 1173K Fe(s)+CO2(g)FeO(s)+CO(g)K11.47 2.15 Fe(s)+H2O(g)FeO(s)+H2(g)K22.38 1.67 CO(g)+H2O(g)CO2(g)+H2(g)K3?完成下列填空：（1）反应是（选填“吸热”，“放热”）反应。根据反应与可以推导出同温下 K1、K2与 K3之间的关系，则K3=（用 K1、K2表示）。（2）973K时，若反应在一个容积为 2L 的反应容器内2m
36、in 时达到平衡，有3mol 电子发生转移，则在2min 内 v(CO2)=。若压缩容器的容积为原来的一半，平衡将移动（选填“向左”，“向右”，“不”），CO2的浓度将（选填“增大”，“减小”，“不变”）。使该反应的平衡转化率及平衡常数都增大的措施有。（3）在 FeCl3稀溶液中滴加KSCN溶液后呈红色，反应的离子方程式是；若在其中加入少量KCl固体，溶液的颜色 _（选填“变深”，“变浅”，“不变”）。（4）若先往 FeCl3溶液中加入足量NaF溶液，再滴加 KSCN溶液，则不呈红色，若再加入足够量FeCl3溶液 又会呈现红色。请对上述实验现象作出解释。精品资料-欢迎下载-欢迎下载 名师归纳-
37、第 5 页，共 7 页 -文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE
38、4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A
39、9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE
40、4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A
41、9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE
42、4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A
43、9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3学习好资料欢迎下载三、实验题(2 小题，共22 分)22、（本题 8 分）甲、乙两位同学设计用实验确定某酸HA 是弱电解质，存在电离平衡，且改变条件平衡发生移动。实验方案如下：甲：准确配制0.1molL-1的 HA、HCl 溶液各 100mL；取纯度相同，质量、大小相等的锌粒放入两只试管中，同时加入0.1mol L-1的 HA、HC
44、l溶液各 100mL，按上图装好，观察现象。乙：用pH 计测定物质的量浓度均为0.1mol L-1的 HA 和 HCl 溶液的 pH；再取 0.1mol L-1的 HA和 HCl溶液各 2 滴（1滴约为）分别稀释至100mL，再用 pH 计测其 pH 变化。（1）乙方案中说明HA 是弱电解质的理由是，测得0.1mol L-1的 HA 溶液的 pH 1（填“”“（1 分）A（2 分）（2）增大（1 分）（3）A（2 分）（4）C（2 分）23.（1）5H2C2O4+2MnO4+6H+=10CO2+2 Mn2+8H2O（2 分）（2）温度计（1 分）（3）生成的Mn2+在反应中起到催化剂的作用，加
45、快了反应速率（2 分）；MnSO4(S)、秒表（2 分）（4）（4 分）试管 A 试管 B 加入试剂1mL0.05mol/L KMnO42mL0.1mol/L H2C2O41mL0.05mol/L KMnO42mL0.1mol/L H2C2O4少量MnSO4（预期）实验现象（褪色时间）褪色较慢褪色很快结论猜想正确精品资料-欢迎下载-欢迎下载 名师归纳-第 7 页，共 7 页 -文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 Z
46、O5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2
47、J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 Z
48、O5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2
49、J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 Z
50、O5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2J9T9N4 HA2O1S7V1A9 ZO5R2P7C2A3文档编码:CE4M2