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1、2011年学业考试数学模拟卷一、选择题：（本大题共6 题，每题4 分，满分24 分）1下列根式中，与2为同类二次根式的是（）（A）21；（B）a2；（C）2.0；（D）12.2关于二次函数2)1(2xy的图像，下列判断正确的是（）（A）图像开口向上；（B）图像的对称轴为直线1x；（C）图像有最低点；（D）图像的顶点坐标为(1，2).3关于等边三角形，下列说法不正确的是（）（A）等边三角形是轴对称图形；（B）等边三角形是中心对称图形；（C）等边三角形是旋转对称图形；（D）等边三角形都相似.4把一块周长为20cm，面积为202cm的纸片裁成四块形状、大小完全相同的小三角形纸片（如图1），则每块小三
2、角形纸片的周长和面积分别为（）（A）10cm，52cm；（B）10cm，102cm；（C）5cm，52cm；（D）5cm，102cm.5 已知1e、2e是两个单位向量，向量12ea，22eb，那么下列结论中正确的是（）（A）21ee；（B）ba；（C）ba；（D）ba.6图 2 反映了一辆汽车从甲地开往乙地的过程中，汽车离开甲地的距离s（千米）与所用时间 t（分）之间的函数关系已知汽车在途中停车加油一次，根据图像，下列描述中，不正确的是（）（A）汽车在途中加油用了10 分钟；（B）汽车在加油前后，速度没有变化；（C）汽车加油后的速度为每小时90 千米；（D）甲乙两地相距60 千米.二、填空题：
3、（本大题共12 题，每题4 分，满分48 分）在答题纸相应题号后的空格内直接填写答案 7计算：aa2)(8计算：112mmmm9在实数范围内分解因式：222xx=10方程xx32的解为：11已知12)(3xxf，且3)(af，则a12已知函数2kkxy的图像经过第一、三、四象限，则k的取值范围是13把抛物线xxy22向左平移一个单位，所得抛物线的表达式为：14已知关于x的方程042mxx，如果从1、2、3、4、5、6 六个数中任取一个数作为(图 1)S(千米)t(分)60 30 55 35 25 0(图 2)方程的常数项m，那么所得方程有实数根的概率是15 如图 3，已知梯形ABCD 中，AB
4、CD，AB=5，CD=3，AD=BC=4，则DABcos16如图4，小芳与路灯相距3 米，她发现自己在地面上的影子（DE）长 2 米，如果小芳的身高为 1.6 米，那么路灯离地面的高度（AB）是米.17如图 5，已知 AB 是 O 的直径，O1、O2的直径分别是OA、OB，O3与 O、O1、O2均相切，则O3与 O 的半径之比为18已知 A 是平面直角坐标系内一点，先把点A 向上平移3 个单位得到点B，再把点A 绕点 B 顺时针方向旋转90得到点 C，若点 C 关于 y 轴的对称点为（1,2），那么点A 的坐标是三、解答题：（本大题共7 题，满分78 分）19（本题满分10 分）计算：1312
5、)23(6)8()13(20（本题满分10 分，每小题满分5 分）如图 6，已知一个正比例函数与一个反比例函数的图像在第一象限的交点为A（2，4）.（1）求正比例函数与反比例函数的解析式；（2）平移直线OA，平移后的直线与x 轴交于点B，与反比例函数的图像在第一象限的交点为C（4，n）.求 B、C 两点的距离(图 4)C B E D A(图 5)A B O O1O2O3C D(图 3)B A A（2，4）y x O(图 6)文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码
6、:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2
7、HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3
8、ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档
9、编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C
10、2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E
11、3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9
12、文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G921（本题满分10 分，第(1)小题满分6 分，第(2)小题满分4 分）如图 7，ABC 中，AB=AC，54cosABC，点 D 在边 BC 上，BD=6，CD=AB.(1)求 AB 的长；(2)求ADC 的正切值.22（本题满分10 分，每小题各5 分）如图 8，已知B是线段AE上一点，ABCD和 BEFG 都是正方形，联结AG、CE(1)求证：AG=CE；(2)设CE与GF的交点为P，求证：AGPECGPG.A B C D E
13、 F G P(图 8)D C B A(图 7)文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 Z
14、Z4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编
15、码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2
16、 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3
17、 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文
18、档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8
19、C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G923（本题满分12 分，每小题各4 分）为了了解学生关注热点新闻的情况，“两会”期间，小明对班级同学一周内收看“两会”新闻的次数情况作了调查，调查结果统计如图9 所示（其中男生收看3 次的人数没有标出）.根据上述信息，
20、解答下列各题：(1)该班级女生人数是，女生收看“两会”新闻次数的中位数是；(2)对于某个群体，我们把一周内收看某热点新闻次数不低于3 次的人数占其所在群体总人数的百分比叫做该群体对某热点新闻的“关注指数”.如果该班级男生对“两会”新闻的“关注指数”比女生低5%，试求该班级男生人数；(3)为进一步分析该班级男、女生收看“两会”新闻次数的特点，小明给出了男生的部分统计量（如表1）.根据你所学过的统计知识，适当计算女生的有关统计量，进而比较该班级男、女生收看“两会”新闻次数的波动大小.24（本题满分12 分，每小题各4 分）如图 10，已知抛物线cbxxy2与x轴负半轴交于点A，与y轴正半轴交于点B
21、，且OBOA.(1)求cb的值；(2)若点 C 在抛物线上，且四边形OABC 是平行四边形，试求抛物线的解析式；(3)在(2)的条件下，作OBC 的角平分线，与抛物线交于点P，求点 P 的坐标.统计量平均数（次）中 位 数（次）众 数（次）方差该班级男生3 3 4 2 C B A O y x(图 10)0 1 4 23 次数(次)2 3 5 6 7 人数(人)O 5(图 9)1 女生男生4（表 1）文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2
22、HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3
23、ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档
24、编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C
25、2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E
26、3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9
27、文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D
28、8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G925（本题满分14 分，第(1)小题满分4 分，第(2)小题满分5 分，第(3)小题满分5 分）如图 11，已知 O 的半径长为1，PQ 是 O 的直径，点M 是 PQ 延长线上一点，以点M 为圆心作圆，与O 交于 A、B 两点，联结PA 并延长，交M 于另外一点C.(1)若 AB 恰好是 O 的直径，设OM=x，AC=y，试在图12 中画出符合要求的大致图形，并求 y 关于 x 的函数解析式；(2)联结 OA、MA、MC，若 OAMA，且 OMA 与 PM
29、C 相似，求OM 的长度和 M的半径长；(3)是否存在 M，使得 AB、AC 恰好是一个正五边形的两条边？若存在，试求OM 的长度和 M 的半径长；若不存在，试说明理由.图 12 Q P O M 备用图Q P O A B 图 11 C Q P O M 文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3
30、C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A
31、10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D
32、8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9
33、C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L
34、2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W
35、1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G92011年九
36、年级数学模拟测试评分参考一、1.A；2.D；3.B；4.A；5.C；6.B.二、7.3a；8.m；9.)31)(31(xx；10.1x；11.32；12.20k；13.12xy；14.32；15.41；16.4；17.3:1；18.)1,2(.三、19解：原式=2362324=)23(6322=3223322=23220.解（1）设正比例函数的解析式为xky1，反比例函数的解析式为xky2根据题意得：241k，242k解得：21k，82k所以，正比例函数的解析式为xy2，反比例函数的解析式为xy8.（2）因为点 C（4，n）在反比例函数xy8的图像上所以，248n，即点 C 的坐标为)2,4(
37、因为 AOBC，所以可设直线BC 的表达式为bxy2又点 C 的坐标为)2,4(在直线 BC 上所以，b422，解得6b，直线 BC 的表达式为62xy直线 BC 与 x 轴交于点 B，设点 B 的坐标为)0,(m可以得：620m，解得3m，所以点 B 的坐标为)0,3(5BC文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C
38、2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3
39、C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A
40、10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D
41、8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9
42、C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L
43、2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W
44、1D8C2G921.解：（1）过点 A 作 AHBC，垂足为 H ACABBCHCBH21设xCDACAB6BD6xBC，26xBH在 RtAHB中，ABBHABCcos，又54cosABC5426xx解得：10 x，所以10AB（2）821BCHCBH2810CHCDDH在 RtAHB中，222ABBHAH，又10AB，6AH在 RtAHD中，326tanDHAHADCADC的正切值是322.证明：（1）四边形ABCD和BEFG是正方形CBAB，BEBG，90CBEABGABGCBECEAG（2）PGBECBCGBEPG，CEPECBBGBEBG，CEAGCBBGCGPG，AGPECBBGA
45、GPECGPG23.（1）20，3（2）由题意：该班女生对“两会”新闻的“关注指数”为%65%1002013文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9
46、文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D
47、8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K
48、5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2
49、G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C
50、2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A10K5E3 ZZ4W1D8C2G9文档编码:CM9C3C2D8C2 HD8L2A1