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1、1 2019 年高考（理科）数学真题专题 11 算法初步1【2019 年高考天津卷理数】阅读下边的程序框图，运行相应的程序，输出S的值为A5B8C24D29【答案】B【分析】根据程序框图，逐步写出运算结果即可【解析】1,2Si；11,1225,3jSi；8,4Si，结束循环，输出8S故选B【名师点睛】解答本题要注意要明确循环体终止的条件是什么，会判断什么时候终止循环体2【2019 年高考北京卷理数】执行如图所示的程序框图，输出的s值为2 A1B2C3D4【答案】B【分析】根据程序框图中的条件逐次运算即可【解析】初始：1s，1k，运行第一次，22 123 12s，2k，运行第二次，2222322
2、s，3k，运行第三次，2222322s，结束循环，输出2s，故选 B【名师点睛】本题考查程序框图，属于容易题，注重基础知识、基本运算能力的考查3【2019 年高考全国卷理数】如图是求112122的程序框图，图中空白框中应填入文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ1
3、0P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F
4、6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7
5、D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ1
6、0P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F
7、6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7
8、D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ1
9、0P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L33 A12AAB12AAC112AAD112AA【答案】A【分析】本题主要考查算法中的程序框图，渗透阅读、分析与解决问题等素养，认真分析式子结构特征与程序框图结构，即可找出作出选择【解析】初始：1,122Ak，因为第一次应该计算1122=12A，1kk=2
10、；执行第 2次，22k，因为第二次应该计算112122=12A，1kk=3，结束循环，故循环体为12AA，故选 A【秒杀速解】认真观察计算式子的结构特点，可知循环体为12AA4【2019 年高考全国卷理数】执行下边的程序框图，如果输入的为 001，则输出s的值等于文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10
11、 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J1
12、0 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编
13、码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10
14、 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J1
15、0 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编
16、码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10
17、 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L34 A4122B5122C6122D7122【答案】C【分析】根据程序框图，结合循环关系进行运算，可得结果【解析】输入的为0.01，11,01,0.01?2xsx不满足条件；1101,0.01?24sx不满足条件；6
18、11101,0.00781250.01?22128SxL满足条件，结束循环；输出676111112(1)22222SL，故选 C【名师点睛】解答本题关键是利用循环运算，根据计算精确度确定数据分析5【2019 年高考江苏卷】下图是一个算法流程图，则输出的S的值是 _文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10
19、 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J1
20、0 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编
21、码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10
22、 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J1
23、0 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编
24、码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10
25、 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L35【答案】5【分析】结合所给的流程图运行程序确定输出的值即可【解析】执行第一次，1,1422xSSx不成立，继续循环，12xx；执行第二次，3,2422xSSx不成立，继续循环，13xx；执行第三次，3,342xSS
26、x不成立，继续循环，14xx；执行第四次，5,442xSSx成立，输出5.S【名师点睛】识别、运行程序框图和完善程序框图的思路：（1）要明确程序框图的顺序结构、条件结构和循环结构；（2）要识别、运行程序框图，理解框图所解决的实际问题；（3）按照题目的要求完成解答并验证文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K
27、10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6
28、J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文
29、档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K
30、10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6
31、J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文
32、档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3文档编码:CJ10P6Z10B6J10 HX7D10O8Z2K10 ZB1F6O3I1L3