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1、学业分层测评(建议用时：45 分钟)学业达标 一、选择题1某一随机变量的概率分布列如下表，且m2n1.2，则 mn2的值为()0123 P m n A.0.2C0.1【解析】由离散型随机变量分布列的性质可得mn0.21，又 m2n1.2，解得 mn0.4，可得 mn20.2.【答案】B 2以下问题中的随机变量不服从两点分布的是()A抛掷一枚骰子，所得点数为随机变量XB某射手射击一次，击中目标的次数为随机变量XC从装有5 个红球，3 个白球的袋中取1 个球，令随机变量X1，取出白球0，取出红球D某医生做一次手术，手术成功的次数为随机变量X【解析】A 中随机变量 X 的取值有 6 个，不服从两点分
2、布，故选A.【答案】A 3在 15 个村庄中，有 7 个村庄交通不太方便，现从中任意选10 个村庄，用 表示 10个村庄中交通不太方便的村庄数，以下概率中等于C47C68C1015的是()AP(2)BP(2)CP(4)DP(4)【解析】A 项，P(2)C27C88C1015；B 项，P(2)P(2)C47C68C1015；C 项，P(4)C47C68C1015；D 项，P(4)P(2)P(3)P(4)C47C68C1015.【答案】C 4抛掷两颗骰子，所得点数之和X 是一个随机变量，则P(X4)等于()A.16B.13C.12D.23【解析】根据题意，有 P(X4)P(X2)P(X3)P(X4
3、)抛掷两颗骰子，按所得的点数共 36 个基本领件，而 X2 对应(1,1)，X3 对应(1,2)，(2,1)，X4 对应(1,3)，(3,1)，(2,2)，故 P(X2)136，P(X3)236118，P(X4)336112，所以 P(X4)13611811216.【答案】A 5随机变量 的概率分布列为P(n)an n1，n1,2,3,4，其中 a 是常数，则 P12 52的值为()A.23B.34C.45D.56【解析】a12a23a34a45a11212131314141545a1.a54.文档编码:CL5J5U8P9J6 HN2J6J7Z2X2 ZP5Z4Z1W4I9文档编码:CL5J5
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