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1、1/7 黄冈市 2018 年初中毕业生学业水平考试数学试题考试时间 120分钟满分 120分）注意事项：1答卷前，考生务必将自己的姓名、准考证号填写在试题卷和答题卡上，并将准考证号条形码粘贴在答题卡上的指定位置u8sSEh2pgs 2选择题每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑如需改动，用橡皮擦干净后，再选涂其他答案标号答在试题卷上无效u8sSEh2pgs 3 非选择题的作答：用0.5 毫 M 黑色墨水签字笔直接答在答题卡上对应的答题区域内答在试题卷上无效4 考生必须保持答题卡整洁考试结束后，请将本试题卷和答题卡一并上交一、填空题 共 8 道题，每小题3 分，共 24
2、分）112的倒数是 _2分解因式8a2 2=_ 3要使式子2aa有意义，则a 的取值范围为 _4如图：点A 在双曲线kyx上，AB x 轴于B，且 AOB 的面积SAOB=2，则k=_5如图：矩形ABCD 的对角线AC=10，BC=8，则图中五个小矩形的周长之和为_6如图，在 ABC 中 E 是 BC 上的一点，EC=2BE，点 D 是 AC 的中点，设 ABC、ADF、BEF 的面积分别为SABC，SADF，SBEF，且SABC=12，则SADF SBEF=_ u8sSEh2pgs 7若关于x，y 的二元一次方程组3133xyaxy的解满足2xy，则 a 的取值范围为 _8如图，ABC 的外
3、角 ACD 的平分线CP 的内角A B O x y 第 4题图A B C D 第 5 题图第 5 题图A B C E F D A B C P D 第 8 题图2/7 ABC 平分线 BP 交于点 P，若 BPC=40，则 CAP=_u8sSEh2pgs 二、选择题 A，B，C，D四个答案中，有且只有一个是正确的，每小题3 分，共 21 分）9cos30=A12B22C32D310计算221222-1（-）A2 B2 C6 D10 11下列说法中一个角的两边分别垂直于另一个角的两边，则这两个角相等数据 5，2，7，1，2，4 的中位数是3，众数是2 等腰梯形既是中心对称图形，又是轴对称图形RtA
4、BC 中，C=90，两直角边a，b 分别是方程x27x7=0 的两个根，则AB边上的中线长为1352u8sSEh2pgs 正确命题有A0 个B1 个C2 个D3 个12一个几何体的三视图如下：其中主视图都是腰长为4、底边为2 的 等 腰 三 角 形，则 这 个 几 何 体 的 侧 面 展 开 图 的 面 积 为u8sSEh2pgs A2B12C4D813如图，AB 为 O 的直径，PD 切 O 于点 C，交 AB 的延长线于D，且 CO=C D，则PCA=A30B45C60D67.514如图，把RtABC 放在直角坐标系内，其中CAB=90，BC=5，点A、B 的坐 标分别为 1，0）、4，0
5、），将 ABC 沿 x 轴向右平移，当点C 落在直线y=2x6 上时，线段 BC 扫过的面积为u8sSEh2pgs A4 B8 C16 D8 215已知函数22113513xxyxx，则使 y=k 成立的 x值恰好有三个，则k 的值为A0 B1 C2 D3 三、解答题 共 9 道大题，共75 分）第12 题4 2 2 4 左视图右视图俯视图C D A O P B 第13 题第14 题A B C O y x 文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D
6、8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S1
7、0H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7
8、Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y
9、3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4
10、S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2
11、M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R
12、7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z73/7 第18 题B A E D F C 165 分）解方程：213xxx176 分）为了加强食品安全管理，有关部门对某大型超市的甲、乙两种品牌食用油共抽取 18 瓶进行检测，检测结果分成“优秀”、“合格”、“不合格”三个等级，数据处理后制成以下折线统计图和扇形统计图u8sSEh2pgs 甲、乙两种品牌食用油各被抽取了多少瓶用于检测？在该超市购买一瓶乙品牌食用油，请估计能买到“优秀”等级的概率是多少？u8sSEh2pgs 187 分）如图，在等腰三角
13、形ABC 中，ABC=90，D 为 AC 边上中点，过D 点作 DEDF，交 AB于 E，交 BC 于 F，若 AE=4，FC=3，求 EF 长u8sSEh2pgs 197 分）有3 张扑克牌，分别是红桃3、红桃4 和黑桃5把牌洗匀后甲先抽取一张，记下花色和数字后将牌放回，洗匀后乙再抽取一张u8sSEh2pgs 先后两次抽得的数字分别记为s和 t，则 st 1 的概率甲、乙两人做游戏，现有两种方案A 方案：若两次抽得相同花色则甲胜，否则乙胜 B 方案：若两次抽得数字和为奇数则甲胜，否则乙胜u8sSEh2pgs 请问甲选择哪种方案胜率更高？208 分）今年我省干旱灾情严重，甲地急需要抗旱用水15
14、 万吨，乙地13 万吨现有A、B 两水库各调出14 万吨水支援甲、乙两地抗旱从A 地到甲地50千 M，到乙地30千 M；从 B 地到甲地60千 M，到乙地45 千 Mu8sSEh2pgs 设从 A 水库调往甲地的水量为x 万吨，完成下表甲乙总计Ax14 B14 总计15 13 28 请设计一个调运方案，使水的调运量尽可能小调运量=调运水的重量调运的距离，单位：万吨?千M）21如图，防洪大堤的横断面是梯形，背水坡AB 的坡比1:3i指坡面的铅直高度与水平宽度的比）且AB=20 m身高为1.7 m的小明站在大堤A 点，测得高压电线杆端点D 的仰角为30已知地面CB 宽 30 m，求高压电线杆CD
15、的高度 结果保留三个有效数字，31.732）.u8sSEh2pgs 两种品牌食用没检测结果折线图瓶数优秀合格不合格7 10 0 1 等级不合格的 10%合格的 30%优秀 60%甲种品牌食用没检测结果扇形分布图图图第16 题调入地水量/万吨调出地文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D
16、8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S1
17、0H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7
18、Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y
19、3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4
20、S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2
21、M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z74/7 228 分
22、）在圆内接四边形ABCD 中，CD 为 BCA 外角的平分线，F 为弧 AD 上一点，BC=AF，延长 DF 与 BA的延长线交于Eu8sSEh2pgs 求证 ABD 为等腰三角形求证 AC?AF=DF?FE2312 分）我市某镇的一种特产由于运输原因，长期只能在当地销售当地政府对该特产的销售投资收益为：每投入x 万元，可获得利润216041100Px 万元）当地政府拟在“十二?五”规划中加快开发该特产的销售，其规划方案为：在规划前后对该项目每年最多可投入100万元的销售投资，在实施规划5 年的前两年中，每年都从100 万元中拨出50 万元用于修建一条公路，两年修成，通车前该特产只能在当地销售
23、；公路通车后的3 年中，该特产既在本地销售，也在外地销售在外地销售的投资收益为：每投入x 万元，可获利润299294101001601005Qxx万元）u8sSEh2pgs 若不进行开发，求5 年所获利润的最大值是多少？若按规划实施，求5 年所获利润 扣除修路后）的最大值是多少？根据、，该方案是否具有实施价值？2414 分）如图所示，过点 F0，1）的直线y=kxb 与抛物线214yx交于 M x1，y1）和N x2，y2）两 点 其 中x1 0，x20）u8sSEh2pgs 求 b 的值求 x1?x2的值分别过M、N 作直线l：y=1 的垂线，垂足分别是M1、N1，判断 M1FN1的形状，并
24、证明你的结论u8sSEh2pgs 对于过点F 的任意直线MN，是否存在一条定直线 m，使 m 与以 MN 为直径的圆相切如果有，请法度出这条直线m 的解读式；如果没有，请说明理由u8sSEh2pgs 黄冈市 2018 年初中毕业生学业水平考试12 222a1）2a1）3a 2 且 a0 44 528 62 7a4 850C D N M A B 第21 题第22 题B A F E D C M F M N N1M1F1O y x l 第24 题文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2
25、M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R
26、7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3
27、J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9
28、A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE
29、6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2
30、X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7
31、H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z75/7 9C 10A 11C 12C 13D 14C 15D 16x=6 17由不合格瓶数为1 知道甲不合格的瓶数为1）甲、乙分别被抽取了10 瓶、8 瓶P优秀）=1218连结 BD，证 BED CFD 和 AED BFD，求得 EF=5 1923A 方案 P甲胜）=59，B 方案 P甲胜）=49故选择 A 方案甲的胜率更高20从左至右，从上至下）14 x 15xx1 y=50 x+14x）30+6015x）+x1）
32、45=5x+1275 解不等式1x14 所以 x=1 时 y 取得最小值ymin=1280 2121.7 10 336.0 22由圆的性质知MCD=DAB、DCA=DBA，而 MCD=DCA，所以DBA=DAB，故 ABD 为等腰三角形u8sSEh2pgs DBA=DAB弧 AD=弧 BD又 BC=AF弧 BC=弧 AF、CDB=FDA弧 CD=弧 DF CD=DF再由“圆的内接四边形外角等于它的内对角”知AFE=DBA=DCA ，FAE=BDE CDA=CDB BDA=FDA BDA=BDE=FAE 由得 DCA FAEAC：FE=CD：AFAC?AF=CD?FE而 CD=DF，AC?AF=
33、DF?FE文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6
34、R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X
35、3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H
36、9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:C
37、E6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB
38、2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT
39、7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z76/7 23解：当x=60 时，P 最大且为41，故五年获利最大值是415=205 万元前两年：0 x50，此时因为P 随 x 增大而增大，所以x=50 时，P 值最大且为40 万元，所以这两年获利最大为40 2=80 万元u8sSEh2pgs 后三年：
40、设每年获利为y，设当地投资额为x,则外地投资额为100 x，所以 y=PQ=216041100 x+2992941601005xx=260165xx=2301065x，表明x=30 时，y 最大且为1065，那么三年获利最大为10653=3495万元，故五年获利最大值为803495502=3475 万元有极大的实施价值来源:学*科*网 Z*X*X*K24解：b=1 显 然11xxyy和22xxyy是 方 程 组2114yk xyx的 两 组 解，解 方 程 组 消 元 得21104xkx，依据“根与系数关系”得12x x=4 M1FN1是直角三角形是直角三角形，理由如下：由题知 M1的横坐标为
41、x1，N1的横坐标为x2，设 M1N1交 y 轴于 F1，则 F1M1?F1N1=x1?x2=4，而 FF1=2，所以 F1M1?F1N1=F1F2，另有 M1F1F=FF1N1=90，易证RtM1FF1RtN1FF1，得 M1FF1=FN1F1，故 M1FN1=M1FF1 F1FN1=FN1F1F1FN1=90，所以 M1FN1是直角三角形u8sSEh2pgs 存在，该直线为y=1理由如下：直线 y=1即为直线M1N1如图，设N 点横坐标为m，则 N 点纵坐标为214m,计算知 NN1=2114m，NF=2221(1)4mm2114m，得NN1=NFu8sSEh2pgs 同理 MM1=MF那
42、么 MN=MM1NN1，作梯形MM1N1N 的中位线PQ，由中位线性质知PQ=12MM1NN1）=12MN，即圆心到直线y=1 的距离等于圆的半径，所以y=1总与该圆相切u8sSEh2pgs 申明：所有资料为本人收集整理，仅限个人学习使用，勿做商业用F M N N1M1F1O y x l 第 24 题解答用图P Q 文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 H
43、B2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 Z
44、T7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编
45、码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8
46、 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8
47、 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文
48、档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8
49、Z8 HB2X3J4S10H8 ZT7H9A2M7Z77/7 途。文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X
50、3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H9A2M7Z7文档编码:CE6R7Y3D8Z8 HB2X3J4S10H8 ZT7H