(完整word版)概率论与数理统计试卷A及答案.pdf

上传人:H****o 文档编号:55120462 上传时间:2022-10-29 格式:PDF 页数:7 大小:151.04KB
返回 下载 相关 举报
(完整word版)概率论与数理统计试卷A及答案.pdf_第1页
第1页 / 共7页
(完整word版)概率论与数理统计试卷A及答案.pdf_第2页
第2页 / 共7页
点击查看更多>>
资源描述

《(完整word版)概率论与数理统计试卷A及答案.pdf》由会员分享,可在线阅读,更多相关《(完整word版)概率论与数理统计试卷A及答案.pdf(7页珍藏版)》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。

1、第 1 页(共 4 页)绝密启用前黑龙江外国语学院继续教育学院2014 年 秋 季学期概率论与数理统计试卷(A 卷)题号一二三四五六总分评卷人审核人得分一、选择题(本大题共 5 小题,每空 2 分,共 30 分)1、A、B 是两个随机事件,已知0.3)B(p,5.0)(,4.0)A(pABP,则)BA(p ,)B-A(p,)(BAP=,)BA(p。2、一个袋子中有大小相同的红球6 只、黑球 4 只。(1)从中不放回地任取2 只,则第一次、第二次取红色球的概率为:。(2)若有放回地任取2 只,则第一次、第二次取红色球的概率为:。(3)若第一次取一只球观查球颜色后,追加一只与其颜色相同的球一并放入

2、袋中后,再取第二只,则第一次、第二次取红色球的概率为:。3、设随机变量X服从 B(2,0.5)的二项分布,则1Xp ,Y 服从二项分布B(98,0.5),X与 Y相互独立,则 X+Y服从,E(X+Y)=,方差 D(X+Y)=。4、甲、乙两个工厂生产同一种零件,设甲厂、乙厂的次品率分别为0.1、0.15 现从由甲厂、乙厂的产品分别占60%、40%的一批产品中随机抽取一件。(1)抽到次品的概率为:。(2)若发现该件是次品,则该次品为甲厂生产的概率为:5、设 二 维 随 机 向 量),(YX的 分 布 律 如 右,则a,)(XE。2YXZ的分布律为:本题得分XY0 1 -1 1 0.2 0.3 0.

3、4 az 1 2 概率0.6 0.4 第 2 页(共 4 页)二、(本大题共 1 小题,10 分)已知随机变量X的密度函数其它,010,)(2xaxxf求:(1)常数a,(2))5.15.0(Xp(3)X的分布函数F(x)。三、(本大题共 1 小题,10 分)设随机变量(X,Y)的联合概率密度为:其它,010,10,2),(yxyyxf求:(1)X,Y的边缘密度,(2)讨论 X与 Y的独立性。四、(本大题共 1 小题,10 分)设总体 XN(0,2),。nXX,.,1是一个样本,求2的矩估计量,并证明它为2的无偏估计。本题得分本题得分本题得分文档编码:CX5F2H7E10I3 HI9M3V5R

4、8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5

5、R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V

6、5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3

7、V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M

8、3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9

9、M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI

10、9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10第 3 页(共 4 页)五、(本大题共 1 小题,20 分)从总体X),(2uN中抽取容量为16 的一个样本,样本均值和样本

11、方差分别是4,752SX,5.27)15(,26.6)15(,1315.2)15(2597.02502.0597.0 xxt求u的置信度为0.95 的置信区间和2的置信度为0.95 的置信区间。本题得分文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8

12、H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R

13、8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5

14、R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V

15、5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3

16、V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M

17、3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9

18、M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10第 4 页(共 4 页)六、(本大题共 1 小题,20 分)设某工厂生产工件的直径服从正态分布,要求它们的均值25.0,82u,现检验了一组由16 只工件,计算得样本均值、样本方差分别49.0,65.72sx,试在显著水平05.0下,对该厂生产的工件的均值和方差进行检验,看它们是否符合标准。此题中,,5.27)15(,25)15(,13.2)15(,76.1)15(2025.0205.0025.05.0tt本题得分文档编码:CX5F2H7E10I3 HI9M3V5R

19、8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5

20、R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V

21、5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3

22、V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M

23、3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9

24、M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI

25、9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10第 4 页(共 4 页)答:一.填空题1、A、B 是两个随机事件,已知0.3)B(p,5.0)(,4.0)A(pABP,则)

26、BA(p0.6,)B-A(p0.1,)(BAP=0.4,)BA(p0.6。2、一个袋子中有大小相同的红球6 只、黑球 4 只。(1)从中不放回地任取2 只,则第一次、第二次取红色球的概率为:1/3。(2)若有放回地任取2 只,则第一次、第二次取红色球的概率为:9/25。(3)若第一次取一只球观查球颜色后,追加一只与其颜色相同的球一并放入袋中后,再取第二只,则第一次、第二次取红色球的概率为:21/55。3、设随机变量X 服从 B(2,0.5)的二项分布,则1Xp0.75,Y 服从二项分布B(98,0.5),X与 Y 相互独立,则 X+Y 服从B(100,0.5),E(X+Y)=50,方差 D(X

27、+Y)=25。4、甲、乙两个工厂生产同一种零件,设甲厂、乙厂的次品率分别为0.1、0.15现从由甲厂、乙厂的产品分别占60%、40%的一批产品中随机抽取一件。(1)抽到次品的概率为:0.12。(2)若发现该件是次品,则该次品为甲厂生产的概率为:0.5 5、设二维随机向量),(YX的分布律如右,则a0.1,)(XE0.4。2YXZ的分布律为:二、已知随机变量X 的密度函数其它,010,)(2xaxxf求:(1)常数a,(2))5.15.0(Xp(3)X 的分布函数F(x)。解:(1)由3,1)(adxxf得2(2)515.0(Xp=5.15.015.02875.03)(dxxdxxf2(3)xx

28、x0 xxF1,110,0)(32三、设随机变量(X,Y)的联合概率密度为:其它,010,10,2),(yxyyxf求:(1)X,Y 的边缘密度,(2)讨论 X 与 Y 的独立性。XY0 1-1 1 0.2 0.3 0.4 az1 2 概率0.6 0.4 文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10

29、文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G1

30、0文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G

31、10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9

32、G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E

33、9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9

34、E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T

35、9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10第 4 页(共 4 页)解:(1)X,Y 的边缘密度分别为:其他,其他01022)()(01012)(1010yyydxdxyxfyfxydyxfYX4(2)由(1)可见)()(),(yfxfyxfYX,可知:X,Y 相互独立2四、设总体X N(0,2),。nXX,.,1是一个样本,求2的矩估计量,并证明它为2的无偏估计。解:X 的二阶矩为:22)(XE1X 的二阶样本矩为nkiXnA12211令:22)(AXE

36、,1解得:2121inkXn,2的矩估计量2121inkXn2)1()?(212inkXnEE,它为2的无偏估计量.3五、从 总 体X),(2uN中 抽 取 容 量 为16 的 一 个 样 本,样 本 均 值 和 样 本 方 差 分 别 是4,752SX,5.27)15(,26.6)15(,1315.2)15(2597.02502.0597.0 xxt求 u 的置信度为0.95 的置信区间和2的置信度为0.95 的置信区间。解:(1)n=16,置信水平025.02/,95.01,1315.2)15(597.0t4,752SX由此 u的置信水平为0.95 的置信区间为:)1315.216275(

37、,即)0658.175(5(2)n=16,置信水平025.02/,95.01,5.27)15(,26.6)15(2597.02502.0 xx42S由此2的置信水平为0.95 的置信区间为:文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV

38、4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 Z

39、V4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10

40、ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10

41、 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H1

42、0 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H

43、10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8

44、H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10第 4 页(共 4 页)585.9,182.2()15(415,)15(415(2025.02597.05六、设某工厂生产工件的直径服从正态分布,要求它们的均值25.0,82u,现检验了一组由16 只工件,计算得样本均值、样本方差分别49.0,65.72sx,试在显著水平05.0下,对该厂生产的工件的均值和方差进行检验,看它们是否符合标准。此题中,,5.27)15(,25)15(,13.2)15(,76.1)15(2025.0205.0025.05.0tt解:(1)首先对工件的

45、均值进行检验:H0:8:,81uHu1 分取统计量为16/8sXt,可得拒绝域为:13.2)15(16/8025.0tsXt,2 分经计算,13.224/7.0865.716/8sxt,不在拒绝域内,因此接受H0.认为这批工件的均值符合标准。2 分其次首先对工件的方差进行检验:H0:221225.0:,5.0H1 分取统计量为2225.0)116(s,可得拒绝域为:25)15(5.049.015205.0222 分经计算,254.295.0)116(222s,在拒绝域内,因此拒绝H0.认为这批工件的方差不符合标准。2 分文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T

46、9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1

47、T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V

48、1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4

49、V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV

50、4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 ZV4V1T9E9G10文档编码:CX5F2H7E10I3 HI9M3V5R8H10 Z

展开阅读全文
相关资源
相关搜索

当前位置:首页 > 教育专区 > 高考资料

本站为文档C TO C交易模式,本站只提供存储空间、用户上传的文档直接被用户下载,本站只是中间服务平台,本站所有文档下载所得的收益归上传人(含作者)所有。本站仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。若文档所含内容侵犯了您的版权或隐私,请立即通知淘文阁网,我们立即给予删除!客服QQ:136780468 微信:18945177775 电话:18904686070

工信部备案号:黑ICP备15003705号© 2020-2023 www.taowenge.com 淘文阁