《第一节系统的稳定性PPT讲稿.ppt》由会员分享，可在线阅读，更多相关《第一节系统的稳定性PPT讲稿.ppt（44页珍藏版）》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。
1、第一节系统的稳定性第1页，共44页，编辑于2022年，星期一稳定性和代数稳定判据(Stability of the system and the algebra criteria)典型输入作用和时域性能指标(Typical input and time performance index)一阶系统的瞬态响应(Transient response of one order dynamical system)二阶系统的瞬态响应(Transient response of two order dynamical system)稳态误差分析(Steady error analyse)主要内容(Main
2、 issues)第2页，共44页，编辑于2022年，星期一第一节 系统的稳定性和 代数稳定判据Section 1 Stability of the control system and the its algebra evaluation criteria第3页，共44页，编辑于2022年，星期一1.稳定的基本概念和线性系统稳定的充要条件(Basic concept of system stability and its the sufficient,necessary condition of the linear control system)1)Stabilizing of contro
3、l system is the most important condition for system to run properly.2)In fact,the real system is always affected by the outside or inside disturbances,such as load varying,energy wave,system parameter changing,environment changing etc.3)If the system is unstable,system will departure the initial bal
4、ance state under any small wave,and will disperse with the time going.4)To analyze the system stability and to make out the plan to ensure the system stable is the basic goal of control theory.稳定的充要条件和属性第4页，共44页，编辑于2022年，星期一q 稳定的基本概念(Basic concept of stability)：If the system is in the state of balan
5、ce,it will depart the state under the effect of outside exciting.when the outside exciting is disappeared,the system will return to the original state as it runs for so long time.The system is stable,or the system is off stability.Or else the system is unstable,or the system is of instability.第5页，共4
6、4页，编辑于2022年，星期一Consider the follow differential equation：+polynomial relative with initial value稳定的充要条件和属性Do Laplace transform：where：x(t)input y(t)output;is constants.第6页，共44页，编辑于2022年，星期一1.The first item is zero state solution,and is related with the response excited by the input.2.The second item
7、is zero input solution,and is related with the response excited by the initial value.第7页，共44页，编辑于2022年，星期一q necessary and sufficient condition of linear system stabilizing is:all the system characteristic roots are of negative real part(Eigenvalue),or all the system characteristic roots are lain on
8、the left half plane of s complex plane.稳定的充要条件和属性第8页，共44页，编辑于2022年，星期一充要条件说明 if there is a positive real root for a system,it means the system response is dispersive.if there is a pair of positive real part complex root for a system,it means the system response is period dispersive oscillation.both
9、cases are unstable.if there is a zero root for a system,it means the system response is random balance state.if there is a pair of imaginary roots for a system,it means the system response is oscillating state in a constant size.Stable zoneNonstable zoneCriticalStable zoneS plane第9页，共44页，编辑于2022年，星期
10、一For the one order system,if and only if are positive,the system is stable.If and only if are positive,the system is stable.For 3 or more order system,it is more difficult to get the roots of a algebra equation.How can we do?充要条件说明Notice：System stability is a quality of linear system,and is just rel
11、ated with the system structure and parameter,but not related with the input signal.not related with the initial condition.System stability is just related with the polar,not related with the zero.For the 2 order system第10页，共44页，编辑于2022年，星期一2.Routh-Hurwitz criterion Considering the characteristic equ
12、ation of the linear system 劳斯判据1).Routh criterion：The necessary and sufficient condition of the system is as follow:b.All the elements which are lain on the first column of the Routh array,and are composed of the coefficients of the characteristic equation should be positive.a.All the polynomial coe
13、fficients of the characteristic equation should be positive;第11页，共44页，编辑于2022年，星期一The first two line elements of the Routh array consist of the coefficients of characteristic equation.The first row elements are composed of the coefficients an,an-2,an-4,.;The second row elements are composed of the c
14、oefficients an-1,an-3,an-5,.How to construct the Routh table?第12页，共44页，编辑于2022年，星期一劳斯判据The rules to calculate the 3th row elements is as follow：第13页，共44页，编辑于2022年，星期一劳斯判据The rules to calculate the 4th row elements is as follow：第14页，共44页，编辑于2022年，星期一According to the above similar method,the remain el
15、ements can also be lead.The rules to calculate the 5th row elements is as follow：第15页，共44页，编辑于2022年，星期一劳斯判据例子example considering the system which characteristic equation is:To write down the Routh array as right position According to the necessary and sufficient condition of a stable system,we can g
16、et：andTry to determine the system stability.product of 2 inner coefficients minus product of 2 out coefficients is positive.第16页，共44页，编辑于2022年，星期一2)Discussion of the special condition of the Routh array and some conclusionb.The system is unstable if all the elements in the first column of Routh arra
17、y are not zero but not all are positive.劳斯判据特殊情况a.It will not affect the system stability to multiple or divide all elements in a row of the Routh array with a positive number;c.It also indicate that there are some characteristic roots in the right half plan of complex number plane s.d.The number of
18、 the unstable roots is equal to the changed sign number of elements in the first rank of Routh array.第17页，共44页，编辑于2022年，星期一example Assume that the system characteristic equation is:-1 3 0（2）1 0 0（）There is 2 sign changes in the first column.Try to find the number of unstable root of the system.Discu
19、ss:To list the Routh array;There is a negative number in the first column.The system is unstable.2 unstable characteristic roots are in the right half s plane.第18页，共44页，编辑于2022年，星期一劳斯判据特殊情况 e.If the first element is zero but the others in one line of the Routh table are not all zero,A new method sho
20、uld be considered.Solution：to substitute the element 0 with a very small positive number .At last counting the sign-changed number.After then to calculate the other elements on the line or below the line.第19页，共44页，编辑于2022年，星期一example Considering the characteristic equation:Let ,then There is 2 sign
21、changes that means 2 unstable roots in the right half plane of complex number plane s.to analyse：Try to find the number of unstable root of the system.Discuss:to list the Routh array;Clearly,there is a negative number in first column.The system is unstable.第20页，共44页，编辑于2022年，星期一f.All the numbers in
22、a Routh array row are zero.It means that there is a pair of characteristic roots which are equal in size and opposite in sign.劳斯判据特殊情况There are 3 cases as:a pair of real roots which are equal in size and opposite in sign;or a pair of conjugate imaginary roots;or 2 pair of conjugate complex number ro
23、ots which are symmetric to the imaginary axis.第21页，共44页，编辑于2022年，星期一exampleSolution：a.to construct an assistant algebra equation of complex number variable s according to the coefficients of the last row in which the coefficients are nonzero.b.To differentiate the assistant equation and get the new
24、equationc.To substitute the coefficients of the zero row with the coefficients of the new equation.Notice:the assistant equation must be even order.第22页，共44页，编辑于2022年，星期一example to discuss the stability of the below system.1 6 81 6 81 3 03 8 0劳斯判据特殊情况 to simplify it;Analyse:to list the Routh array;t
25、o build the assistant equation;to differentiate the above equation to get a new one;to substitute the coefficients with the new coefficients from the simplified equation.to continue the list the Routh array to determine the unstable roots.第23页，共44页，编辑于2022年，星期一It seems that the system is stable beca
26、use the elements are bigger than or equal to zero.Clearly the system is critical stable that means unstable in an engineering meaning.1 6 81 6 81 3 03 8 0To build an assistant equation as below and to solve it,we may get:第24页，共44页，编辑于2022年，星期一 Each of the host diagonal elements is the coefficients o
27、f characteristic polynomial from the second to the last .Problem 1.How to construct the Hurwitz array?Each element of each row below the host diagonal is some coefficients according to subscript increasing.Each element of each row above the host diagonal is some coefficients according to subscript d
28、ecreasing.All the element is 0 when the subscript is bigger than n or smaller than 0.subscript decreasingsubscript increasing第26页，共44页，编辑于2022年，星期一Problem 2.How to construct the host sub-determinant?第27页，共44页，编辑于2022年，星期一3.Application of Routh Hurwitz criterion1)To determine the system stabilityexam
29、ple if the system characteristic equation is：,try to determine the system stability.Analyse:To list the Routh array as below：2 unstable roots are in the right half plane.The system is unstable.There is 2 sign changes第30页，共44页，编辑于2022年，星期一2)To analyze the influence of system parameter changingexample
30、 the system block diagram is given as below,try to determine the critical amplifying coefficient.Solution closed loop transfer function is：The characteristic equation is：An important effect of the Routh-Hurwitz criterion is to analyze the influence of some system parameters varying such as the open-
31、loop system amplifying coefficient K.We can use the criterion to determine the maximum critical amplifying coefficient.第32页，共44页，编辑于2022年，星期一To write out the Routh array as below：According to the necessary and sufficient condition:all the coefficients must be bigger than 0.the elements lain on the f
32、irst column of the Routh array should be positive.Then we may get:The critical amplifying coefficient is .The characteristic equation is：第33页，共44页，编辑于2022年，星期一3)To determine the relative system stability (stabilization abundance)As we know,we can use the Routh-Hurwitz criterion to determine whether
33、a control system is stable or unstable.It is a absolute stability.if we want to know the relative stability of a control system,or how can it be determined?Usually,the distance between the characteristic root p of the maximum real part and the imaginary axis is used virtually to express the system s
34、tabilization abundance.Clearly,if p is lain on the imaginary axis,that means the system stabilization abundance is 0.How do we determine the system stabilization abundance?第34页，共44页，编辑于2022年，星期一To draw a vertical line on the complex plane s which is parallel to the imaginary axis,and if all the char
35、acteristic roots are on the left of the line,the system is called of stabilization abundance.The bigger the is,the more stable the system is.Problem:How to find the in a control system?Let ,and substitute the complex variable s with in the characteristic equation,then lead a new characteristic equat
36、ion with a new complex variable z.Use Routh-Hurwitz criterion to analyze the system stability according to the new characteristic equation.If the new system is stable,the original system is called of stabilization abundance.第35页，共44页，编辑于2022年，星期一example a system characteristic equation is ,There is
37、a pair of imaginary roots.The new system is critical stable.And the original system is of 1 abundance stability.How about the relative system stability?solution clearly,And The system is stable.Let ,substitute the s with z-1,the new equation is:or第36页，共44页，编辑于2022年，星期一Usually,the real part of the co
38、gent complex root represents the attenuation speed of system response,whereas the imaginary part of the cogent complex root represents the oscillating of system response.is the angle between the polar and the negative real axis.The smaller the angle is,the better the system quality is.Another form t
39、o discuss the relative stability,the relative stability is worst.第37页，共44页，编辑于2022年，星期一3.Essential unstable system and the plan to improve1)What is the essential unstable system?It is the system whose performance can not be improved just by adjusting the system parameters.结构不稳定系统及其改进措施-杠杆和放大器的传递函数执行
40、电机的传递函数进水阀门的传递函数控制对象水箱的传递函数2)Example:liquid height control system第38页，共44页，编辑于2022年，星期一结构不稳定系统及其改进措施Closed loop transfer function：let：Characteristic equation：or：clearly：Routh array：No matter how to change the parameter K and T,can the system not be stable?What should we do to make the system to be s
41、table?The system is unstable.第39页，共44页，编辑于2022年，星期一结构不稳定系统及其改进措施cause:There are 2 integral components in the forward access.The numerator of the closed loop transfer function is a constant,The closed-loop characteristic equation lack of some item.-2 methods:To change the integral component;To introd
42、uce a open loop zero.第40页，共44页，编辑于2022年，星期一结构不稳定系统及其改进措施 to change the integral property feedback is used in the component.The advantage is to improve the system stability,but the disadvantage is to cut down the steady accuracy.第41页，共44页，编辑于2022年，星期一结构不稳定系统及其改进措施 introduce the open loop zero speed f
43、eedback proportional+differential control第42页，共44页，编辑于2022年，星期一结构不稳定系统及其改进措施Closed loop transfer function：Characteristic equation：Clearly：Routh array：Necessary and sufficient condition：ie.ie.To introduce the proportional+differential control,is to increase the lack coefficient in the characteristic
44、equation.If the parameter is properly adjusted(),the system is stable.第43页，共44页，编辑于2022年，星期一summaryqNecessary and sufficient condition of linear systemqRouth-Hurwitz criterionqThe application of Routh-Hurwitz criterion to determine the system stability to analyze the effect of system parameter changingto analyze the relative system stabilityqEssential unstable system and the plan to improveassignments：3-1(1),(3),3-2(1),(3),(5),3-3第44页，共44页，编辑于2022年，星期一