第四章理想气体的热力过程精选PPT.ppt

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1、第四章理想气体的热力过程第1页,此课件共45页哦 A.It is to determine the change in the properties of working fluid during a process;(在于确定在一个过程中工质状态参数的变化量在于确定在一个过程中工质状态参数的变化量)B.It is to determine the amount of heat,work interaction between the system and its surroundings during a process.(确定在一个过程中系统与外界所交换的功量和热量的多少确定在一个过程中系

2、统与外界所交换的功量和热量的多少)2.本章研究的对象本章研究的对象 The object of this chapterReversible processes of Ideal Gases in closed systems(闭口系统中理想气体的可逆过程闭口系统中理想气体的可逆过程)1.本章的研究任务本章的研究任务The task of this chapter 第2页,此课件共45页哦3.所采取的步骤所采取的步骤 The procedures adoptedPv=RT第3页,此课件共45页哦4.1 Basic Thermodynamic Process(4.1 基本热力过程基本热力过程)1

3、.等容过程等容过程Isochoric-Constant Volume process 第4页,此课件共45页哦 For a constant volume process,the addition or removal of heat will lead to a change in the temperature and pressure of the gas,as shown on the two graphs above.Substitute into(1)过程方程过程方程(Process equation)第5页,此课件共45页哦(2)内能、焓及熵的变化量内能、焓及熵的变化量The c

4、hange in Internal Energy,Enthalpy and Entropy The amount of heat added to a closed system during a constant volume process equals to the increase in internal energy.定容过程中加入闭口系统的热量等于系统的内能的增加量定容过程中加入闭口系统的热量等于系统的内能的增加量第6页,此课件共45页哦Entropy Change To find the Entropy change,start with the expression deriv

5、ed from the first law,replacing dU using the definition of specific heat at constant volume and using the definition of entropy(3)Work done and Heat Transferred(功量和热量功量和热量)Applying the first law of thermodynamics to the process Replacing W with the reversible worksince the volume is constant dV=0 第7

6、页,此课件共45页哦using the definition of the specific heat at constant volumeto replace dU in the first law.The technical work done 第8页,此课件共45页哦2.等压过程等压过程 Isobaric-Constant Pressureo第9页,此课件共45页哦(1)过程方程过程方程 Process equationFor a constant pressure process,the addition or removal of heat will lead to a change

7、 in the temperature and volume of the gas,as shown on the two graphs above.Substitute into第10页,此课件共45页哦 The amount of heat added to a closed system during a constant pressure process equals to the increase in enthalpy.(2)内能、焓及熵的变化量内能、焓及熵的变化量The change in Internal Energy,Enthalpy and Entropy 第11页,此课件

8、共45页哦 The amount of heat added to a closed system during a constant pressure process equals to the increase in enthalpy.(3)Work done and Heat Transferred 第12页,此课件共45页哦 During a constant pressure process,heat is added or removed and the temperature and volume changes.The volume at the end of the proc

9、ess can be found using the ideal gas law and the work calculated from第13页,此课件共45页哦3.等温压缩和膨胀等温压缩和膨胀Isothermal Compression and Expansion第14页,此课件共45页哦 For a constant temperature process,the addition or removal of heat will lead to a change in the volume and pressure of the gas,as shown on the two graph

10、s above.Substitute into (1)过程方程过程方程(Process equation)第15页,此课件共45页哦(2)内能、焓及熵的变化量内能、焓及熵的变化量 The change in Internal Energy,Enthalpy and Entropy 第16页,此课件共45页哦(3)功量和热量功量和热量Work Done and Heat Transferred In an isothermal process,the temperature is constant.Applying the first law of thermodynamics to this

11、closed process For an ideal gas,the internal energy is a function of temperature only,and since the temperature is constant,then dU is zero and第17页,此课件共45页哦 using the ideal gas law and integrating between the start and end of the process During an isothermal process,the work done by the system is eq

12、ual to the heat added to the system,and all the work is technically usable.第18页,此课件共45页哦4.绝热过程绝热过程 Adiabatic Process 第19页,此课件共45页哦(1)Process equation(过程方程过程方程)orQuasi-static,adiabatic process for an ideal gasq=cvdT+pdv and q=cpdT vdp then cvdT=-pdv and cp dT=vdp therefore thenfinally,we arrive at th

13、e very useful expressionfrom which it can also be shown thator第20页,此课件共45页哦 When the temperatures at the start and end of the process are known,the pressure is calculated from(2)The change in Internal Energy,Enthalpy and Entropy(内能、焓及熵的变化量)内能、焓及熵的变化量)Entropy ChangeThere is no heat transfer to or fro

14、m the gas and the process is reversible so that第21页,此课件共45页哦 When the temperatures at the start and end of the process are known,the work done is calculated from(3)Work Done and Heat Transferred(功量和热量功量和热量)第22页,此课件共45页哦5.多变过程多变过程Polytropic Process oMany processes can be approximated by the law:owher

15、e,P Pressure,v Volume,n an index depending on the process type.第23页,此课件共45页哦on=0,results in P=constant i.e.isobaric process.on=infinity,results in v=constant i.e.isochoric process.on=1,results in P v=constant,which is an isothermal process for a perfect gas.on=k,which is a reversible adiabatic proce

16、ss for a perfect gas.Polytropic processes are internally reversible.Some examples are vapors and ideal gas in many non-flow processes,such as:第24页,此课件共45页哦oSome polytropic processes are shown in figure below:The initial state of working fluid is shown by point 0 on the P-V diagram.The polytropic sta

17、te changes are:0 to 1=constant pressure heating,0 to 2=constant volume heating,0 to 3=reversible adiabatic compression,0 to 4=isothermal compression,0 to 5=constant pressure cooling,0 to 6=constant volume cooling,0 to 7=reversible adiabatic expansion,0 to 8=isothermal expansion.第25页,此课件共45页哦 When th

18、e temperatures at the start and end of the process are known,the pressure is calculated from(2)内能、焓及熵的变化量内能、焓及熵的变化量The change in Internal Energy,Enthalpy and Entropy Entropy ChangeThere is no heat transfer to or from the gas and the process is reversible so that第26页,此课件共45页哦 When the temperatures at

19、 the start and end of the process are known,the work done is calculated from(3)Work Done and Heat Transferred(功量和热量功量和热量)第27页,此课件共45页哦第28页,此课件共45页哦29 第29页,此课件共45页哦4.34.3活塞式压气机的工作过程活塞式压气机的工作过程Working Process of gas piston compressor第30页,此课件共45页哦1.Theoretical processes of single-staged piston compress

20、or (理想单级活塞式压气机的工作原理理想单级活塞式压气机的工作原理)第31页,此课件共45页哦 let the initial pressure of the gas is (令气体初态压力为令气体初态压力为 )the final pressure is (终态压力为 ),pressure ratio is (升压比)(1)b-1:charge stroke(吸气冲程),吸气量增大,吸入气体的状态(吸气量增大,吸入气体的状态(P,T)不变不变;(3)2-a:discharge process(排气过程),气缸内的气体减少,气体状态不变化气缸内的气体减少,气体状态不变化(2)1-2:compr

21、ession stroke(压缩冲程),吸气量不变,压力升高吸气量不变,压力升高.第32页,此课件共45页哦2.Analysis on theoretical work consumed by these processes(压气机的理论耗功量分析压气机的理论耗功量分析)o取活塞右行一次的吸气量为控制质量,并忽略动能差取活塞右行一次的吸气量为控制质量,并忽略动能差及位能差进行分析。及位能差进行分析。吸气过程:气体推动活塞移动,做推挤功吸气过程:气体推动活塞移动,做推挤功 ;压缩过程:气体向活塞做膨胀功压缩过程:气体向活塞做膨胀功 排气过程:气体向活塞做推挤功排气过程:气体向活塞做推挤功 第33

22、页,此课件共45页哦压缩过程功压缩过程功:指指1-2,闭口系的膨胀功,是可逆过程;,闭口系的膨胀功,是可逆过程;压气机耗功:指压气机耗功:指a-1-2-b,全过程是开口系,包括流动功。全过程是开口系,包括流动功。气体在全过程中所做的总功为:气体在全过程中所做的总功为:3.三种不同压缩过程的比较三种不同压缩过程的比较(Comparison of three kinds of compression processes)Adiabatic process(绝热过程绝热过程):压缩过程进行的很快,热量来不及释放;压缩过程进行的很快,热量来不及释放;Isothermal process(等温过程等温过

23、程):压缩过程中,理想的冷:压缩过程中,理想的冷却条件,压缩产生的热量可及时排出;却条件,压缩产生的热量可及时排出;Polytropic process(多变过程多变过程):采用了一定的冷却措施,但:采用了一定的冷却措施,但压缩期间压缩期间,温度仍继续升高。温度仍继续升高。第34页,此课件共45页哦(1)Work consumption(耗功量)耗功量)If it is isothermal compression,then若压缩过程为可逆定温过程,则:若压缩过程为可逆定温过程,则:If it is isentropic compression,then若压缩过程为可逆绝热压缩,则:第35页,

24、此课件共45页哦If it is polytropic compression,then 若压缩过程为可逆多变过程,则:(2)Discharge Temperature(排气温度)排气温度)第36页,此课件共45页哦4.余隙容积的影响余隙容积的影响The influence of residual volume of inter-space.(1)The influence on discharge volume(对排气量的影响)对排气量的影响)Residual Volume(余隙容积):余隙容积):V3We note that if the pressure ratio is too hig

25、h,then it can not work normally.(压缩压力不能太高,压力升高,效率下降,在极限情况下容积效率可达零)第37页,此课件共45页哦The discharge volume will decrease.(余隙存在将使排气量减少)余隙存在将使排气量减少)(2)The influence on compression work(对耗功量的影响)(对耗功量的影响)There is no influence on compression work.(对耗功量无影响对耗功量无影响)Let thenVolume efficiency is defined as 第38页,此课件共

26、45页哦Multistage compression with intercooler is especially attractive when a gas is to be compressed to very high pressures.1.two stage compression(两级压缩)(两级压缩)intercooler4.4 Multistage Compression with inter-cooling(多级压缩、中间冷却)(多级压缩、中间冷却)第39页,此课件共45页哦Assumed that the compression process 1-2 and 3-4 ar

27、e with the same polytropic index n (假设假设1-2和和3-4的多变指数相等。的多变指数相等。)Assumed(假设假设)To minimize the total compression work,the optimal pressure ratio can be determined by (为了使压缩过程的耗功量最小为了使压缩过程的耗功量最小,可以采用如下方法确定最佳中间可以采用如下方法确定最佳中间压力)压力)We obtain第40页,此课件共45页哦 That is,to minimize the compression work during tw

28、o stage compression,the pressure ratio across each stage of the compressor must be the same.(各级压缩比都相等时多级压缩最省功。)(各级压缩比都相等时多级压缩最省功。)When this condition is satisfied,the compression work at each stage becomes identical.(当满足上述条件时,每一级压缩的耗功量都相等)当满足上述条件时,每一级压缩的耗功量都相等)第41页,此课件共45页哦2.Z-Stage Compression(n级压缩

29、)级压缩)Optimal compression ration is 3.Isentropic Efficiency and Isothermal Efficiency (等熵效率和等温效率)第42页,此课件共45页哦oIsentropic efficiency is defined as the ratio of the work input is required to raise the pressure of a gas to a specified value in an isentropic manner to the actual work input.Isothermal Ef

30、ficiency(等温效率)等温效率)o Isothermal efficiency is defined as the ratio of the work input is required to raise the pressure of a gas to a specified value in a reversible isothermal manner to the actual work input.第43页,此课件共45页哦Exercise(练习)oDraw the following polytropic process of air on p-v and T-s diagra

31、m.(1)Pressure rises,temperature increases and with heat rejection(2)Working medium expands and the temperature drops with heat rejection at the same time第44页,此课件共45页哦Exercise(练习)(3)Expansion process with n=1.6,please judge the sign of (4)Compression process with n=1.3,please judge the sign ofDraw the following process on the T-s Diagram.第45页,此课件共45页哦

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