2022年标准电极电位表 .pdf

上传人:H****o 文档编号:32467479 上传时间:2022-08-09 格式:PDF 页数:5 大小:86.63KB
返回 下载 相关 举报
2022年标准电极电位表 .pdf_第1页
第1页 / 共5页
2022年标准电极电位表 .pdf_第2页
第2页 / 共5页
点击查看更多>>
资源描述

《2022年标准电极电位表 .pdf》由会员分享,可在线阅读,更多相关《2022年标准电极电位表 .pdf(5页珍藏版)》请在taowenge.com淘文阁网|工程机械CAD图纸|机械工程制图|CAD装配图下载|SolidWorks_CaTia_CAD_UG_PROE_设计图分享下载上搜索。

1、标准电极电位表半反应E0(伏)F2(气 ) + 2H+ + 2e = 2HF3.06O3 + 2H+ + 2e = O2 + 2H2O2.07S2O82+ 2e = 2SO422.01H2O2 + 2H+ + 2e = 2H2O1.77MnO4+ 4H+ + 3e = MnO2(固) + 2H2O1.695PbO2(固) + SO42+ 4H+ + 2e = PbSO4(固) + 2H2O1.685HClO2 + H+ + e = HClO + H2O1.64HClO + H+ + e = 1/2 Cl2 + H2O1.63Ce4+ + e = Ce3+1.61H5IO6 + H+ + 2e

2、= IO3+ 3H2O1.60HBrO + H+ + e = 1/2 Br2 + H2O1.59BrO3+ 6H+ + 5e = 1/2 Br2 + 3H2O1.52MnO4+ 8H+ + 5e = Mn2+ + 4H2O1.51Au(III) + 3e = Au1.50HClO + H+ + 2e = Cl+ H2O1.49ClO3+ 6H+ + 5e = 1/2 Cl2 + 3H2O1.47PbO2(固) + 4H+ + 2e = Pb2+ + 2H2O1.455HIO + H+ + e = 1/2 I2 + H2O1.45ClO3+ 6H+ + 6e = Cl+ 3H2O1.45BrO3

3、+ 6H+ + 6e =Br + 3H2O1.44Au(III) + 2e = Au(I)1.41Cl2(气) + 2e = 2Cl1.3595ClO4+ 8H+ + 7e = 1/2 Cl2 + 4H2O1.34Cr2O72+ 14H+ + 6e =2Cr3+ + 7H2O1.33MnO2(固) + 4H+ + 2e = Mn2+ + 2H2O1.23名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 1 页,共 5 页 - - - - - - - - - O2(气) + 4H+ +

4、4e = 2H2O1.229IO3+ 6H+ + 5e = 1/2 I2 + 3H2O1.20ClO4+ 2H+ + 2e = ClO3+ H2O1.19Br2(水) + 2e = 2Br1.087NO2 + H+ + e = HNO21.07Br3+ 2e = 3Br1.05HNO2 + H+ + e = NO(气) + H2O1.00VO2+ + 2H+ + e = VO2+ + H2O1.00HIO + H+ + 2e = I+ H2O0.99NO3+ 3H+ + 2e = HNO2 + H2O0.94ClO+ H2O + 2e = Cl+ 2OH0.89H2O2 + 2e = 2OH0

5、.88Cu2+ + I+ e = CuI( 固) 0.86Hg2+ + 2e = Hg0.845NO3+ 2H+ + e = NO2 + H2O0.80Ag+ + e = Ag0.7995Hg22+ + 2e = 2Hg0.793Fe3+ + e = Fe2+0.771BrO+ H2O + 2e = Br+ 2OH0.76O2(气) + 2H+ + 2e = H2O20.682AsO8+ 2H2O + 3e = As + 4OH0.682HgCl2 + 2e = Hg2Cl2(固) + 2Cl0.63Hg2SO4(固) + 2e = 2Hg + SO420.6151MnO4+ 2H2O + 3

6、e = MnO2 + 4OH0.588MnO4+ e = MnO420.564H3AsO4 + 2H+ + 2e = HAsO2 + 2H2O0.559I3+ 2e = 3I0.545名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 2 页,共 5 页 - - - - - - - - - I2(固) + 2e = 2I0.5345Mo(VI) + e = Mo(V)0.53Cu+ + e = Cu0.524SO2(水) + 4H+ + 6e = S4O62+ 2H2O0.51HgCI4

7、2+ 2e = Hg + 4Cl0.482SO2(水) + 2H+ + 4e = S2O32+ H2O0.40Fe(CN)63+ e = Fe(CN)640.36Cu2+ + 2e = Cu0.337VO2+ + 2H+ + 2e = V3+ + H2O0.337BiO+ + 2H+ + 3e = Bi + H2O0.32Hg2CI2(固)+ 2e = 2Hg + 2Cl0.2676HAsO2 + 3H+ + 3e = As + 2H2O0.248AgCI( 固)+ e = Ag + Cl0.2223SbO+ + 2H+ + 3e = Sb + H2O0.212SO42+ 4H+ + 2e =

8、 SO2(水) + H2O0.17Cu2+ + e = Cu0.519Sn4+ + 2e = Sn2+0.154S + 2H+ + 2e = H2S(气)0.141Hg2Br2 + 2e = 2Hg + 2Br0.1395TiO2+ + 2H+ + e = Ti3+ + H2O0.1S4O62+ 2e = 2S2O320.08AgBr( 固) + e = Ag + Br0.0712H+ + 2e = H20.000O2 + H2O + 2e = HO2+ OH0.067TiOCl+ + 2H+ + 3Cl+ e = TiCl4+ H2O0.09Pb2+ + 2e = Pb0.126Sn2+ +

9、 2e = Sn0.136名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 3 页,共 5 页 - - - - - - - - - AgI( 固) + e = Ag + I0.152Ni2+ + 2e = Ni0.246H3PO4 + 2H+ + 2e = H3PO3 + H2O0.276Co2+ + 2e = Co0.277Tl+ + e = Tl0.3360In3+ + 3e = In0.345PbSO4(固) + 2e = Pb + SO420.3553SeO32+ 3H2O +

10、 4e = Se + 6OH0.366As + 3H+ + 3e = AsH30.38Se + 2H+ + 2e = H2Se0.40Cd2+ + 2e = Cd0.403Cr3+ + e = Cr2+0.41Fe2+ + 2e = Fe0.440S + 2e = S20.482CO2 + 2H+ + 2e = H2C2O40.49H3PO3 + 2H+ + 2e = H3PO2 + H2O0.50Sb + 3H+ + 3e = SbH30.51HPbO2+ H2O + 2e = Pb + 3OH0.54Ga3+ + 3e = Ga0.56TeO32+ 3H2O + 4e = Te + 6OH

11、0.572SO32+ 3H2O + 4e = S2O32+ 6OH0.58SO32+ 3H2O + 4e = S + 6OH0.66AsO43+ 2H2O + 2e = AsO2+ 4OH0.67Ag2S(固) + 2e = 2Ag + S20.69Zn2+ + 2e = Zn0.7632H2O + 2e = H2 + 2OH8.28Cr2+ + 2e = Cr0.91名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 4 页,共 5 页 - - - - - - - - - HSnO2+

12、 H2O + 2e = Sn+ 3OH0.91Se + 2e = Se20.92Sn(OH)62+ 2e = HSnO2+ H2O + 3OH0.93CNO+ H2O + 2e = Cn+ 2OH0.97Mn2+ + 2e = Mn1.182ZnO22+ 2H2O + 2e = Zn + 4OH1.216Al3+ + 3e = Al1.66H2AlO3+ H2O + 3e = Al + 4OH2.35Mg2+ + 2e = Mg2.37Na+ + e = Na2.71Ca2+ + 2e = Ca2.87Sr2+ + 2e = Sr2.89Ba2+ + 2e = Ba2.90K+ + e = K2.925Li+ + e = Li3.042名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 5 页,共 5 页 - - - - - - - - -

展开阅读全文
相关资源
相关搜索

当前位置:首页 > 技术资料 > 技术总结

本站为文档C TO C交易模式,本站只提供存储空间、用户上传的文档直接被用户下载,本站只是中间服务平台,本站所有文档下载所得的收益归上传人(含作者)所有。本站仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。若文档所含内容侵犯了您的版权或隐私,请立即通知淘文阁网,我们立即给予删除!客服QQ:136780468 微信:18945177775 电话:18904686070

工信部备案号:黑ICP备15003705号© 2020-2023 www.taowenge.com 淘文阁